More Equations Joseph Lee Metropolitan Community College Joseph Lee More Equations Definition: Perimeter of a Rectangle The perimeter of a rectangle is the distance around the edges. The perimeter is given by P = 2l + 2w where l represents the length of the rectangle and w represents the width of the rectangle. Joseph Lee More Equations Example 1.a Find the length of a rectangle if P = 26 and w = 5. Joseph Lee More Equations Example 1.a Find the length of a rectangle if P = 26 and w = 5. Solution. P = 2l + 2w Joseph Lee More Equations Example 1.a Find the length of a rectangle if P = 26 and w = 5. Solution. P = 2l + 2w 26 = 2l + 2(5) Joseph Lee More Equations Example 1.a Find the length of a rectangle if P = 26 and w = 5. Solution. P = 2l + 2w 26 = 2l + 2(5) 26 = 2l + 10 Joseph Lee More Equations Example 1.a Find the length of a rectangle if P = 26 and w = 5. Solution. P = 2l + 2w 26 = 2l + 2(5) 26 = 2l + 10 16 = 2l Joseph Lee More Equations Example 1.a Find the length of a rectangle if P = 26 and w = 5. Solution. P = 2l + 2w 26 = 2l + 2(5) 26 = 2l + 10 16 = 2l 8= l Joseph Lee More Equations Example 1.b Find the length of a rectangle if P = 48 and w = 13. Joseph Lee More Equations Example 1.b Find the length of a rectangle if P = 48 and w = 13. Solution. P = 2l + 2w Joseph Lee More Equations Example 1.b Find the length of a rectangle if P = 48 and w = 13. Solution. P = 2l + 2w 48 = 2l + 2(13) Joseph Lee More Equations Example 1.b Find the length of a rectangle if P = 48 and w = 13. Solution. P = 2l + 2w 48 = 2l + 2(13) 48 = 2l + 26 Joseph Lee More Equations Example 1.b Find the length of a rectangle if P = 48 and w = 13. Solution. P = 2l + 2w 48 = 2l + 2(13) 48 = 2l + 26 22 = 2l Joseph Lee More Equations Example 1.b Find the length of a rectangle if P = 48 and w = 13. Solution. P = 2l + 2w 48 = 2l + 2(13) 48 = 2l + 26 22 = 2l 11 = l Joseph Lee More Equations Example 1.c Find the length of any rectangle with perimeter, P, and width, w . Joseph Lee More Equations Example 1.c Find the length of any rectangle with perimeter, P, and width, w . Solution. P = 2l + 2w Joseph Lee More Equations Example 1.c Find the length of any rectangle with perimeter, P, and width, w . Solution. P = 2l + 2w P − 2w = 2l Joseph Lee More Equations Example 1.c Find the length of any rectangle with perimeter, P, and width, w . Solution. P = 2l + 2w P − 2w = 2l 2l P − 2w = 2 2 Joseph Lee More Equations Example 1.c Find the length of any rectangle with perimeter, P, and width, w . Solution. P = 2l + 2w P − 2w = 2l 2l P − 2w = 2 2 P − 2w = l 2 Joseph Lee More Equations Definition: Distance Formula The distance formula calculates the distance traveled by an object with constant rate. The distance is given by d = rt where r represents the rate of the object and t represents the time traveled at that rate. Joseph Lee More Equations Example 2.a Find the time traveled by an object that travels for d = 180 at with a constant rate of r = 60. Joseph Lee More Equations Example 2.a Find the time traveled by an object that travels for d = 180 at with a constant rate of r = 60. Solution. d = rt Joseph Lee More Equations Example 2.a Find the time traveled by an object that travels for d = 180 at with a constant rate of r = 60. Solution. d = rt 180 = (60)t Joseph Lee More Equations Example 2.a Find the time traveled by an object that travels for d = 180 at with a constant rate of r = 60. Solution. d = rt 180 = (60)t 180 60t = 60 60 Joseph Lee More Equations Example 2.a Find the time traveled by an object that travels for d = 180 at with a constant rate of r = 60. Solution. d = rt 180 = (60)t 180 60t = 60 60 3= t Joseph Lee More Equations Example 2.b Find the time traveled by an object that travels for d = 180 at with a constant rate of r = 50. Joseph Lee More Equations Example 2.b Find the time traveled by an object that travels for d = 180 at with a constant rate of r = 50. Solution. d = rt Joseph Lee More Equations Example 2.b Find the time traveled by an object that travels for d = 180 at with a constant rate of r = 50. Solution. d = rt 180 = (50)t Joseph Lee More Equations Example 2.b Find the time traveled by an object that travels for d = 180 at with a constant rate of r = 50. Solution. d = rt 180 = (50)t 180 50t = 50 50 Joseph Lee More Equations Example 2.b Find the time traveled by an object that travels for d = 180 at with a constant rate of r = 50. Solution. d = rt 180 = (50)t 180 50t = 50 50 18 = t 5 Joseph Lee More Equations Example 2.c Find the time traveled by any object that travels any distance, d, with a constant rate, r . Joseph Lee More Equations Example 2.c Find the time traveled by any object that travels any distance, d, with a constant rate, r . Solution. d = rt Joseph Lee More Equations Example 2.c Find the time traveled by any object that travels any distance, d, with a constant rate, r . Solution. d = rt d rt = r r Joseph Lee More Equations Example 2.c Find the time traveled by any object that travels any distance, d, with a constant rate, r . Solution. d = rt d rt = r r d = t r Joseph Lee More Equations Definition: Simple Interest The simple interest on a loan is the interest earned only on the principal. The simple interest is given by i = prt where p represents the amount of principal, r represents the interest rate as a decimal, and t represents the time, usually calculated in years. Joseph Lee More Equations Example 3.a Find the interest rate on a loan of $1000 that earns $50 simple interest over 2 years. Joseph Lee More Equations Example 3.a Find the interest rate on a loan of $1000 that earns $50 simple interest over 2 years. Solution. i = prt Joseph Lee More Equations Example 3.a Find the interest rate on a loan of $1000 that earns $50 simple interest over 2 years. Solution. i = prt 50 = (1000)(r )(2) Joseph Lee More Equations Example 3.a Find the interest rate on a loan of $1000 that earns $50 simple interest over 2 years. Solution. i = prt 50 = (1000)(r )(2) 50 = 2000r Joseph Lee More Equations Example 3.a Find the interest rate on a loan of $1000 that earns $50 simple interest over 2 years. Solution. i = prt 50 = (1000)(r )(2) 50 = 2000r 50 2000r = 2000 2000 Joseph Lee More Equations Example 3.a Find the interest rate on a loan of $1000 that earns $50 simple interest over 2 years. Solution. i = prt 50 = (1000)(r )(2) 50 = 2000r 50 2000r = 2000 2000 0.025 = r Joseph Lee More Equations Example 3.a Find the interest rate on a loan of $1000 that earns $50 simple interest over 2 years. Solution. i = prt 50 = (1000)(r )(2) 50 = 2000r 50 2000r = 2000 2000 0.025 = r Thus, the interest rate is $2.5%. Joseph Lee More Equations Example 3.b Find the interest rate on any loan of principal, p, that earns i simple interest over t years. Joseph Lee More Equations Example 3.b Find the interest rate on any loan of principal, p, that earns i simple interest over t years. Solution. i = prt Joseph Lee More Equations Example 3.b Find the interest rate on any loan of principal, p, that earns i simple interest over t years. Solution. i = prt i prt = pt pt Joseph Lee More Equations Example 3.b Find the interest rate on any loan of principal, p, that earns i simple interest over t years. Solution. i = prt i prt = pt pt i = r pt Joseph Lee More Equations Definition: Linear Equation in Two Variables A linear equation in two variables is any equation Ax + By = C where A, B, and C are real numbers. Joseph Lee More Equations Definition: Linear Equation in Two Variables A linear equation in two variables is any equation Ax + By = C where A, B, and C are real numbers. Examples 1 2x + 3y = 6 Joseph Lee More Equations Definition: Linear Equation in Two Variables A linear equation in two variables is any equation Ax + By = C where A, B, and C are real numbers. Examples 1 2x + 3y = 6 2 x − 4y = 8 Joseph Lee More Equations Definition: Linear Equation in Two Variables A linear equation in two variables is any equation Ax + By = C where A, B, and C are real numbers. Examples 1 2x + 3y = 6 2 x − 4y = 8 A linear equation in two variables may be written in y = mx + b form. Joseph Lee More Equations Example 4.a Write 2x + 3y = 6 in y = mx + b form. Joseph Lee More Equations Example 4.a Write 2x + 3y = 6 in y = mx + b form. Solution. 2x + 3y = 6 Joseph Lee More Equations Example 4.a Write 2x + 3y = 6 in y = mx + b form. Solution. 2x + 3y = 6 3y = −2x + 6 Joseph Lee More Equations Example 4.a Write 2x + 3y = 6 in y = mx + b form. Solution. 2x + 3y = 6 3y = −2x + 6 1 1 (3y ) = (−2x + 6) 3 3 Joseph Lee More Equations Example 4.a Write 2x + 3y = 6 in y = mx + b form. Solution. 2x + 3y = 6 3y = −2x + 6 1 1 (3y ) = (−2x + 6) 3 3 2 y = − x +2 3 Joseph Lee More Equations Example 4.b Write x − 4y = 8 in y = mx + b form. Joseph Lee More Equations Example 4.b Write x − 4y = 8 in y = mx + b form. Solution. x − 4y = 8 Joseph Lee More Equations Example 4.b Write x − 4y = 8 in y = mx + b form. Solution. x − 4y = 8 −4y = −x + 8 Joseph Lee More Equations Example 4.b Write x − 4y = 8 in y = mx + b form. Solution. x − 4y = 8 −4y = −x + 8 1 1 − (−4y ) = − (−x + 8) 4 4 Joseph Lee More Equations Example 4.b Write x − 4y = 8 in y = mx + b form. Solution. x − 4y = 8 −4y = −x + 8 1 1 − (−4y ) = − (−x + 8) 4 4 y= Joseph Lee 1 x −2 4 More Equations Example 4.c Write y + 2 = −3(x − 1) in y = mx + b form. Joseph Lee More Equations Example 4.c Write y + 2 = −3(x − 1) in y = mx + b form. Solution. y + 2 = −3(x − 1) Joseph Lee More Equations Example 4.c Write y + 2 = −3(x − 1) in y = mx + b form. Solution. y + 2 = −3(x − 1) y + 2 = −3x + 3 Joseph Lee More Equations Example 4.c Write y + 2 = −3(x − 1) in y = mx + b form. Solution. y + 2 = −3(x − 1) y + 2 = −3x + 3 y = −3x + 1 Joseph Lee More Equations Example 4.d Write 3x − 5y + 2 = 0 in y = mx + b form. Joseph Lee More Equations Example 4.d Write 3x − 5y + 2 = 0 in y = mx + b form. Solution. 3x − 5y + 2 = 0 Joseph Lee More Equations Example 4.d Write 3x − 5y + 2 = 0 in y = mx + b form. Solution. 3x − 5y + 2 = 0 −5y = −3x − 2 Joseph Lee More Equations Example 4.d Write 3x − 5y + 2 = 0 in y = mx + b form. Solution. 3x − 5y + 2 = 0 −5y = −3x − 2 1 1 − (−5y ) = − (−3x − 2) 5 5 Joseph Lee More Equations Example 4.d Write 3x − 5y + 2 = 0 in y = mx + b form. Solution. 3x − 5y + 2 = 0 −5y = −3x − 2 1 1 − (−5y ) = − (−3x − 2) 5 5 y= Joseph Lee 3 2 x+ 5 5 More Equations
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