Name ________________________________________ Date __________________ Class__________________ LESSON 3-8 Reading Strategy Use a Model Just like quadratic and linear functions, polynomial functions can be transformed. One type of transformation is reflection across the x- or y-axis. You can reflect a graph by making its “mirror” image across the axis. Look at the graph of f(x) x 3 x 2 4, which is reflected across the y-axis. The table shows rules for reflecting across the x-axis and the y-axis. Transformation Rule Before Reflection After Reflection Reflection across the x-axis f (x) f (x ) x 3 x 2 4 f (x) (x 3 x 2 4) Reflection across the y-axis f (x) f (x ) x 3 x 2 4 f (x) (x) 3 (x) 2 4 x3 x2 4 x 3 x 2 4 Answer each question. 1. a. Draw the graph of the polynomial f (x) x 3 x 2 4 reflected across the x-axis. b. The point x, f ( x ) is mapped to x, f ( x ) after reflection across the x-axis. Find the point that is mapped to (1, 2) after reflection across the x-axis. _________________________________________ 2. Write the function for each transformation of the polynomial. Polynomial a. f (x ) x 3 4 b. g(x) 6x 5 x 3 2 c. h (x ) x 2 3 x 5 Reflect across x-axis Reflect across y-axis Original content Copyright © by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor. 3-66 Holt McDougal Algebra 2 2. a. g(x) = −2(0.25x)4 + 7(0.25x)2 − 4 4 2 b. g(x) = 4(−2x + 7x − 4) 4. f(x − 2) + 8 5. −f(x + 4) − 3 6. −f(x − 5) − 5 7. f(x + 3) + 4 Problem Solving 1. N(x) = 0.02x3 + 0.4x2 + 0.2x + 235 2. Vertical translation of 200 units up 3. 3. g(x) = −4(x + 2)3 + 5 4. g(x) = 20x3 − 4 5. g(x) = 12(x − 3)3 − 15 4. Because only positive values have meaning in the context of the problem 6. 6 sin(x) + 1 ≈ 0.3x5 − x3 + 6x + 1 Reteach 5. An additional 200 cars are passing through the intersection every week. 3 1. Up; g(x) = x + 3 6. Possible answer: R(x) = C(x) − 30; vertical shift of 30 units down 7. 2C(x) = 0.04x3 + 0.8x2 + 0.4x + 70; possible answer: a new mall opened at the intersection. Reading Strategies 1. a. 3 2. Right; g(x) = (x − 3) + 2 b. (1, −2) 2. a. f(x) = −x3 − 4; f(x) = −x3 + 4 3. Vertical stretch; g(x) = 4x4 − 12x2 + 8 b. g(x) = 6x5 + x3 − 2; g(x) = 6x5 + x3 + 2 4. Horizontal compression; g(x) = 32x4 − 24x2 + 4 c. h(x) = −x2 + 3x − 5; h(x) = x2 + 3x + 5 3-9 CURVE FITTING WITH POLYNOMIAL Challenge MODELS 1. f(x) + 11 Practice A f(x − 2) + 27 −f(x) − 7 2. 0.5f(x) 3. −f(x) − 9 1. First 2. Third 3. Second 4. Second Original content Copyright © by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor. A35 Holt McDougal Algebra 2
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