UIL"Sample"Test"
Science"
2015M2016"
Biology"
"
The distribution of desert biomes is
centered around 30° north and south
latitude due to ___________________.
A) The fall of atmospheric convection cells (Hadley
cells)
B) Seasonal variation in sunlight intensity.
C) Global circulation of surface water in the oceans.
D) Location on the leeward side of mountain
ranges.
E) Location on the windward side of mountain
ranges.
A researcher calculates the genotype frequencies in a
population as AA: 0.36 Aa: 0.10 aa: 0.54, which she
suspects does not follow Hardy-Weinberg equilibrium.
What would be the expected frequency of heterozygotes in
the F1 generation if the population was in Hardy-Weinberg
equilibrium?
A) 0.48
B) 0.41
C) 0.59
D) 0.35
E) 0.10
Steps"to"solve"HMW"ques3ons:"
p2+"2pq"+"q2"="1"
1.  Calculate"the"allele"frequency"(p,"q)"of"the"P1"
genera3on"from"the"P1"genotype"frequencies"
(p2,"2pq,"q2)."
"
AA=0.36=p2 " "Aa=0.10=2pq" "aa=0.54=q2"
"
p="f(A)="p2+"0.5"(2pq)="0.36+"0.05=0.41%
q="f(a)="q2"+"0.5"(2pq)="0.54+0.05=0.59%
"
2.  Use"the"allele"frequency"(p,"q)"of"the"P1"
genera3on"to"calculate"genotype"frequencies"
(p2,"2pq,"q2)"in"F1"genera3on."
p=0.41"and""q=0.59"in"the"P1"
"
Genotype"frequency"in"the"F1"
"
p2=f(AA)=0.17"""""2pq=f(Aa)=0.48""""q2=f(aa)=0.35"
"
The products of mitosis are two genetically
identical cells because:
"
A) the mitotic spindle allows for equal
segregation of chromosomes
B) it is preceded by DNA replication in the S
phase of interphase.
C) maternal and paternal chromatids are
unequally distribute to two daughter cells.
D) the distribution of DNA during telophase I
occurs before cytokinesis.
E) haploid cells unite during mitosis resulting in
identical daughter cells.
DNA"replica3on"during"the"S"phase"produces"
two"iden3cal"DNA"molecules"that"can"be"
distributed"during"mitosis"to"two"iden3cal"cells."
Chemistry"
"
1.% For"the"reac3on"
3NO2""""+"""H2O""""""""""""""""2HNO3""""+"""""NO"
Hint:""""""""46"g/mol""""""""18"g/mol"""""""""""""""""63"g/mol"""""""""""""30"g/mol"
What"is"the"maximum"amount"of"HNO3"which"could"be"formed"
from"184"g"of"NO2"and"27"g"of"H2O?"
"
a)  126."g"
b)  211."g""
c)  94.5"g""
d)  25.3"g"
e)  168."g"
Limi/ng%Reactant%Problem:%
Find"the"limi3ng"reactant"first,"then"get"the"answer."
184/46""="4"mol"NO2""""which"needs""4/3"="1.33"mol"H2O"
27/18"="1.5"mol"H2O"""which"is"too"much"(excess)""
base"answer"on"the"limi3ng"amount"–"the"NO2""
"
4"x"(2/3)"="8/3"mol"of"HNO3"produced"
"
8/3"(63)""=""168"g"HNO3"""
"
2.%
Which"of"the"following"liquids"has"the"highest"
vapor"pressure?"
a)  H2O"
b)  C5H12""
c)  C2H5OH""
d)  C10H12"
•  The"liquid"with"the"fewest/weakest"intermolecular"
forces"(imfs)"will"have"the"highest"vapor"pressure.""
•  Small"imfs"mean"faster/easier"vaporiza3on"rates"
and"higher"vapor"pressures."
•  Water"and"ethanol"both"have"rela3vely"strong"
imfs"(HMbonding)"and"therefore"have"rela3vely"low"
vapor"pressures."
•  Pentane"and"decane"both"only"have"dispersion"
forces"which"are"very"weak.""
•  Overall"imf"strength"scales"with"molecular"size"–"so"
decane"has"stronger"imfs"than"pentane.""
•  So"pentane"will"have"the"highest"vapor"pressure.""
3.% The"heat"of"combus3on"(∆H°)"for"propane"is"2220"kJ/mol."
How"many"kJ"of"energy"are"released"when"5.00"L"of"
propane"at"2.45"atm"and"25°C"is"burned?"
a)  1110"kJ"
b)  2220"kJ"
c)  1875"kJ"
d)  555"kJ"
e)  3330"kJ"
V=5.00L;""P=2.04atm;""T"(in"K)=°C+273.15"
"
"
"
"
"
"=298.15K"
use"ideal"gas"law"to"get"moles"of"propane"
n"="PV/RT"="(2.45i5)/(0.08206i298.15)"="0.500"mol"
"
0.500"mol"(2220"kJ/mol)""=""1110"kJ"
Physics"
"
1.  What"is"the"magnitude"of"the"net"force"needed"to"
bring"a"1850"kg"SUV"uniformly"to"a"stop"from"a"
speed"of"120"km/h"in"a"distance"of"60.0"m?"
"A)"1.03"×"103"N"
"B)"3.70"×"103"N"
"C)"1.71"×"104"N"
"D)"3.43"×"104"N"
"E)"2.22"×"105"N"
1.  With 120 km/h = 33.33 m/s
From v2 = v02 +2a(x – x0):
a = [v2 – v02]/[2(x – x0)]
a = [02 – 33.332]/[2(60)] = 9.259 m/s2
Thus,
ΣF = ma = (1850)(9.259) = 1.71 × 104 N
2.  A"transverse"wave"with"a"wavelength"of"0.25"m"
travels"down"a"75"m"long,"15"kg"wire.""If"the"wire"is"
has"a"tension"of"500"N,"then"what"is"the"speed"of"
the"wave?""
"A)"0.25"m/s"
"B)"0.67"m/s"
"C)"10"m/s"
"D)"50"m/s"
"E)"300"m/s"
2.  For a transverse wave on a string the
wave speed is given by:
v = [FT/µ]½, where µ = m/L
Thus,
v = [500/(15/75)]½ = 50 m/s
3.  The"radioac3ve"isotope"cobaltM60,"6027Co,"has"a"halfM
life"of"5.3"years.""If"the"ini3al"mass"of"60Co"is"531"kg,"
then"what"is"the"mass"of"60Co"aker"15.9"years?"
"A)"none"
"B)"0.027"kg"
"C)"3.6"kg"
"D)"20"kg"
"E)"66"kg"
3.  The number of half-lives is:
15.9/5.3 = 3
and after each half-life the amount will
reduce by ½ or (½)3.
Thus after 3 half-lives the remaining mass of
60Co will be:
(½)3 531 = 66 kg
end"of"ques3ons"