PA 1140 Waves and Quanta Unit 4: Atoms and Nuclei Lecture course slides can be seen at: • http://www.star.le.ac.uk/~mbu/ lectures.html PA 1140 Waves and Quanta Unit 4: Atoms and Nuclei Ch. 40 Nuclear size and Shape • Nuclei exist bcse strong nuclear force overcomes electrostatic repulsion force over close distances inside nucleus • Energetics & stability of nucleus depends on number of protons & electrons inside Z, the number of protons, the atomic number of the atom. N, the number of neutrons. A, the mass number of the nucleus, the total number of nucleons, A=N+Z. From scattering experiments, nuclei are roughly spherical with radius proportional to number of nucleons A1/3 R = R0 A1/3 where R0=1.2-1.5 femtometres = 1.2-1.5x10-15m PA 1140 Waves and Quanta Unit 4: Atoms and Nuclei Ch. 40 Nuclear size and Shape R = R0 A1/3 • • • • Volume is proportional to A, so density constant Nucleus looks like a liquid drop For light nuclei N~Z For heavier nuclei the number of neutrons increases • The extra uncharged neutrons act to stabilize heavy nuclei from repulsive electrostatic forces PA 1140 Waves and Quanta Unit 4: Atoms and Nuclei Nuclear density Estimate the density of nuclear matter. Density: ! = M /V = M 4" ( )R03 A 3 M = mass of proton/neutron = 1.67x10-27kg x A R0= 1.5x10-15m Find density = 1.18x1017kg m-3 PA 1140 Waves and Quanta Unit 4: Atoms and Nuclei Ch. 40 The radioactive decay process β-Decay: either a neutron turns into a proton, with emission of an electron (β-) or proton turns into a neutron (β+): 14 6 14 7 " C ! N + e +!e 13 7 N ! 136 C + e+ + ! e So A remains same, Z changes by +/-1 γ-Decay: excited nucleus decays into lower energy state via emission of a photon. A and Z constant α-Decay: tends to occur in heavier elements, which can become more stable by reducing their size 232 90 228 T ! 228 Ra + ! = 88 88 Ra + He N and Z decrease by 2, A decreases by 4 PA 1140 Waves and Quanta Unit 4: Atoms and Nuclei Ch. 40 Mass and binding energy • Binding energy per nucleon varies with mass number A • For small A (<50) • • Steady increase in number of nearest neighbours as A increases Therefore an increase in no. of bonds per nucleon • For medium A (>50) curve ~flat • • • Additional nucleons too far away Nuclear forces saturate Only nearest neighbours important • For large A (>200) • • Coulomb repulsion force becomes large Nucleus unstable, spontaneous fission • Fusion of nuclei to the left of Fe • Fission to the right PA 1140 Waves and Quanta Unit 4: Atoms and Nuclei Ch. 40 Mass and binding energy • This plot of mass difference per nucleon v A is the negative of the binding energy curve • The rest mass per nucleon for both very heavy (A>200) and very light (A<20) nuclides is more than for nuclides of intermediate mass • Thus, energy is released when a very heavy nucleus breaks up into two lighter nuclei (fission) • Or when two light nuclei fuse together to form a heavier nucleus (fusion) PA 1140 Waves and Quanta Unit 4: Atoms and Nuclei Fission • Very heavy nuclei can spontaneously break apart, placing limit on size of nucleus and number of possible elements • Some heavy elements can be induced to fission by capture of a neutron • Fission of 235U (right): • Nucleus excited by capture of neutron • Splits into two daughter nuclei & emits more neutrons (avg 2.5) • Coulomb repulsion force drives fragments apart • Thermal energy released (exothermic) • Self-sustaining reaction (chain reaction) possible • Big bang with nasty isotopes • Or control in reactor by keeping number of viable neutrons per reaction to 1 n + 235U ! 141Ba + 92 Kr + 3n PA 1140 Waves and Quanta Unit 4: Atoms and Nuclei Fusion 2 H + 3 H ! 4 He + n +17.6MeV • Two light nuclei fuse to form a heavier nucleus • Energy per unit mass > fission • Abundance of light elements holds great promise for producing power from fusion • Fewer dangers than fission (chain reactions, nasty isotopes) • Bcse of coulomb repulsion, kinetic energies ~1MeV needed to get deuterium and tritium close enough for nuclear forces to become effective & fusion to occur • Scattering more likely • Particles must be heated to high enough temps (~108K) for fusion to occur as a result of thermal collisions • Temps like this found in stars • At this temp, gas is a plasma of +ve ions and e• Confining plasma difficult • Done by star’s high gravity • Barely achieved in any fusion reactor to date
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