Lecture Notes 7 Rates of Change and the Derivative Rates of Change and the Derivative Introduction to Computational Science , Fall 2010 Marcus Pendergrass Hampden-Sydney College Example: Height Versus Time Lecture Notes 7 Dr. Pendergrass I A ball is tossed straight up from a bridge that is 11 meters above the water. I Newton’s laws give us a model for the height of the ball as a function of time: s(t) = 11 + 15t − 4.9t2 I s = height in meters above water I t = time in seconds after release Dr. Pendergrass (H-SC) Lecture Notes 7 Fall 2010 2/3 Example: Height Versus Time Lecture Notes 7 Dr. Pendergrass I A ball is tossed straight up from a bridge that is 11 meters above the water. I Newton’s laws give us a model for the height of the ball as a function of time: s(t) = 11 + 15t − 4.9t2 I s = height in meters above water I t = time in seconds after release Dr. Pendergrass (H-SC) Lecture Notes 7 Fall 2010 2/3 Example: Height Versus Time Lecture Notes 7 Dr. Pendergrass I A ball is tossed straight up from a bridge that is 11 meters above the water. I Newton’s laws give us a model for the height of the ball as a function of time: s(t) = 11 + 15t − 4.9t2 I s = height in meters above water I t = time in seconds after release Dr. Pendergrass (H-SC) Lecture Notes 7 Fall 2010 2/3 Example: Height Versus Time Lecture Notes 7 Dr. Pendergrass I A ball is tossed straight up from a bridge that is 11 meters above the water. I Newton’s laws give us a model for the height of the ball as a function of time: s(t) = 11 + 15t − 4.9t2 I s = height in meters above water I t = time in seconds after release Dr. Pendergrass (H-SC) Lecture Notes 7 Fall 2010 2/3 Example: Height Versus Time Lecture Notes 7 Dr. Pendergrass I A ball is tossed straight up from a bridge that is 11 meters above the water. I Newton’s laws give us a model for the height of the ball as a function of time: s(t) = 11 + 15t − 4.9t2 I s = height in meters above water I t = time in seconds after release Dr. Pendergrass (H-SC) Lecture Notes 7 Fall 2010 2/3 Example: Height Versus Time Lecture Notes 7 s(t) = 11 + 15t − 4.9t2 t (sec) s(t) (m) t (sec) s(t) (m) 0.00 11.0000 2.00 21.4000 Dr. Pendergrass (H-SC) 0.25 14.4438 2.25 19.9437 Dr. Pendergrass 0.50 17.2750 2.50 17.8750 0.75 19.4938 2.75 15.1937 1.00 21.1000 3.00 11.9000 Lecture Notes 7 1.25 22.0938 1.50 22.4750 1.75 22.2438 3.25 7.9938 3.50 3.4750 3.75 -1.6563 Fall 2010 3/3 Example: Height Versus Time Lecture Notes 7 s(t) = 11 + 15t − 4.9t2 t (sec) s(t) (m) t (sec) s(t) (m) 0.00 11.0000 2.00 21.4000 Dr. Pendergrass (H-SC) 0.25 14.4438 2.25 19.9437 Dr. Pendergrass 0.50 17.2750 2.50 17.8750 0.75 19.4938 2.75 15.1937 1.00 21.1000 3.00 11.9000 Lecture Notes 7 1.25 22.0938 1.50 22.4750 1.75 22.2438 3.25 7.9938 3.50 3.4750 3.75 -1.6563 Fall 2010 3/3 Example: Height Versus Time Lecture Notes 7 s(t) = 11 + 15t − 4.9t2 t (sec) s(t) (m) t (sec) s(t) (m) 0.00 11.0000 2.00 21.4000 Dr. Pendergrass (H-SC) 0.25 14.4438 2.25 19.9437 Dr. Pendergrass 0.50 17.2750 2.50 17.8750 0.75 19.4938 2.75 15.1937 1.00 21.1000 3.00 11.9000 Lecture Notes 7 1.25 22.0938 1.50 22.4750 1.75 22.2438 3.25 7.9938 3.50 3.4750 3.75 -1.6563 Fall 2010 3/3 Example: Height Versus Time Lecture Notes 7 s(t) = 11 + 15t − 4.9t2 t (sec) s(t) (m) t (sec) s(t) (m) I 0.00 11.0000 2.00 21.4000 0.25 14.4438 2.25 19.9437 Dr. Pendergrass 0.50 17.2750 2.50 17.8750 0.75 19.4938 2.75 15.1937 1.00 21.1000 3.00 11.9000 1.25 22.0938 1.50 22.4750 1.75 22.2438 3.25 7.9938 3.50 3.4750 3.75 -1.6563 What is the velocity of the ball at a given time t? Dr. Pendergrass (H-SC) Lecture Notes 7 Fall 2010 3/3
© Copyright 2026 Paperzz