log (2 ) log 5 x x - = log (3 1) 8 x- = 4 log (3 6) 6 x +

Algebra 2 Trig
Unit 7: Exponents & Logs
Day 10 – 6.4: Change of Base Practice
Name:
Period:
Question
Roll
1. Solve for x:
a.
34 x  27
b. 33 x  15
c. 10 x  4  7  5
2. Solve for x:
a.
9 3
2x
2 x 4
b. 25
x4
3 x 1
5
c. 8
x 1
1
 
2
2 x 1
3. Solve for x:
a.
log7 (2  x)  log 7 5 x
b. log 2 (3x  1)  8
c. 4  log9 (3x  6)  6
4. Solve for x:
a.
log(1  3x)  3  4
b. log 2 2 x  log 2 x  5
c. log 2 x  log 3  4
5. Evaluate using change of base:
a.
log5 8 
b. log8 14 
c. log 26 9 