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Exercise 12 A - WordPress.com

Class 8: Chapter 12 – Time and Distance Exercise 12 A
Q1. Express the following speeds in meter / sec:
72×1000 π‘š
i.
72km/hr =
ii.
117 km/hr=
iii.
5.4 km/hr=
iv.
12.6 km/hr=
3600 𝑠𝑒𝑐
= 20 π‘š/𝑠
117×1000 π‘š
3600 𝑠𝑒𝑐
5.4×1000 π‘š
3600 𝑠𝑒𝑐
= 32.5 π‘š/𝑠
= 1.5 π‘š/𝑠
12.6×1000 π‘š
3600 𝑠𝑒𝑐
= 3.5 π‘š/𝑠
Q2. Express the following speeds in km/hr:
18 π‘˜π‘š ×3600
i.
18 m/sec =
ii.
2 m/sec=
iii.
3 m/sec=
iv.
12.5 m/sec=
1000 β„Žπ‘Ÿ
2 π‘˜π‘š ×3600
1000 β„Žπ‘Ÿ
= 64.8 π‘˜π‘š/β„Žπ‘Ÿ
= 7.2 π‘˜π‘š/β„Žπ‘Ÿ
1
10 π‘˜π‘š ×3600
3
3×1000 β„Žπ‘Ÿ
= 12 π‘˜π‘š/β„Žπ‘Ÿ
12.5 π‘˜π‘š ×3600
1000 β„Žπ‘Ÿ
= 45 π‘˜π‘š/β„Žπ‘Ÿ
Q3. An athlete covers a distance of 1200 meters in 4 min.48 sec. Find his speed in
km/hr.
𝑆𝑝𝑒𝑒𝑑 =
1200 π‘š
1200π‘˜π‘š × 3600
=
= 15 π‘˜π‘š/β„Žπ‘Ÿ
4 min 48 𝑠𝑒𝑐
1000 × 288 β„Žπ‘Ÿ
Q4. Walking at the rate of 4 km/hr a man covers a certain distance in 21/2 hours. How
much time will be taken by the man to cover the same distance, if he cycles at
12km/hr?
π·π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ π‘π‘œπ‘£π‘’π‘Ÿπ‘’π‘‘ π‘€π‘Žπ‘™π‘˜π‘–π‘›π‘” = 4 × 2.5 = 10 π‘˜π‘š
1
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π‘‡π‘–π‘šπ‘’ π‘‘π‘œ π‘π‘œπ‘£π‘’π‘Ÿ 10 π‘˜π‘š π‘œπ‘› 𝑐𝑦𝑐𝑙𝑒 =
10 π‘˜π‘š × β„Žπ‘Ÿ
5
= β„Žπ‘Ÿ π‘œπ‘Ÿ 50 π‘šπ‘–π‘›π‘’π‘‘π‘’π‘ 
12 π‘˜π‘š
6
Q5. A car can finish a certain journey in 10 hours at a speed of 48 km/hr. By how
much the speed of car must be increased to cover the same distance in 8 hours?
π·π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ π‘π‘œπ‘£π‘’π‘Ÿπ‘’π‘‘ 𝑏𝑦 π‘‘β„Žπ‘’ π‘π‘Žπ‘Ÿ = 48 × 10 = 480 π‘˜π‘š
480 π‘˜π‘š
= 60 π‘˜π‘š/β„Žπ‘Ÿ
8 β„Žπ‘Ÿ
π‘˜π‘š
𝐻𝑒𝑛𝑐𝑒 π‘‘β„Žπ‘’ 𝑠𝑝𝑒𝑒𝑑 π‘šπ‘’π‘ π‘‘ 𝑏𝑒 π‘–π‘›π‘π‘Ÿπ‘’π‘Žπ‘ π‘’π‘‘ 𝑏𝑦 = 60 βˆ’ 48 = 12
β„Žπ‘Ÿ
𝑆𝑝𝑒𝑒𝑑 π‘‘π‘œ π‘π‘œπ‘£π‘’π‘Ÿ π‘‘β„Žπ‘’ π‘ π‘Žπ‘šπ‘’ π‘‘π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ 𝑖𝑛 8 β„Žπ‘Ÿ =
Q6. A bus covers a certain distance in 50 minutes, if it runs at a speed of 54 km/hr.
What must be the speed of the bus in order to reduce the time of journey to 40
minutes?
50
× 54 = 45 π‘˜π‘š
60
45 π‘˜π‘š × 60
𝑆𝑝𝑒𝑒𝑑 π‘‘π‘œ π‘π‘œπ‘£π‘’π‘Ÿ π‘‘β„Žπ‘’ π‘ π‘Žπ‘šπ‘’ π‘‘π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ 𝑖𝑛 40 π‘šπ‘–π‘› =
40 β„Žπ‘Ÿ
π·π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ π‘π‘œπ‘£π‘’π‘Ÿπ‘’π‘‘ 𝑏𝑦 π‘‘β„Žπ‘’ 𝑏𝑒𝑠 =
= 67.5 π‘˜π‘š/β„Žπ‘Ÿ
Q7. A motor car starts with the speed of 70 km/hr with its speed increasing every two
hours by 10 km/hr. In how much time will it cover a distance of 345 km?
𝑆𝑝𝑒𝑒𝑑 π‘Žπ‘‘ π‘‘β„Žπ‘’ π‘ π‘‘π‘Žπ‘Ÿπ‘‘ = 70π‘˜π‘š/β„Žπ‘Ÿ
π·π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ π‘π‘œπ‘£π‘’π‘Ÿπ‘’π‘‘ 𝑖𝑛 π‘“π‘–π‘Ÿπ‘ π‘‘ 2 β„Žπ‘œπ‘’π‘Ÿπ‘  = 140 π‘˜π‘š
𝑆𝑝𝑒𝑒𝑑 π΄π‘“π‘‘π‘’π‘Ÿ 2 β„Žπ‘œπ‘’π‘Ÿπ‘  = 80 π‘˜π‘š/β„Žπ‘Ÿ
π·π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ π‘π‘œπ‘£π‘’π‘Ÿπ‘’π‘‘ 𝑖𝑛 3π‘Ÿπ‘‘ π‘Žπ‘›π‘‘ π‘‘β„Žπ‘’ 4π‘‘β„Ž β„Žπ‘œπ‘’π‘Ÿ = 160 π‘˜π‘š
π‘‡π‘œπ‘‘π‘Žπ‘™ π‘‘π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ π‘π‘œπ‘£π‘’π‘Ÿπ‘’π‘‘ 𝑏𝑦 𝑒𝑛𝑑 π‘œπ‘“ 4π‘‘β„Ž β„Žπ‘œπ‘’π‘Ÿπ‘  = 140 + 160 = 300 π‘˜π‘š
π·π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ 𝑙𝑒𝑓𝑑 π‘‘π‘œ 𝑏𝑒 π‘π‘œπ‘£π‘’π‘Ÿπ‘’π‘‘ π‘Žπ‘“π‘‘π‘’π‘Ÿ 𝑒𝑛𝑑 π‘œπ‘“ 4π‘‘β„Ž β„Žπ‘œπ‘’π‘Ÿ = 345 βˆ’ 300 π‘˜π‘š
= 45 π‘˜π‘š
2
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𝑆𝑝𝑒𝑒𝑑 π΄π‘“π‘‘π‘’π‘Ÿ 4 β„Žπ‘œπ‘’π‘Ÿπ‘  = 90 π‘˜π‘š/β„Žπ‘Ÿ
π‘‡π‘–π‘šπ‘’ π‘‘π‘Žπ‘˜π‘’π‘› π‘‘π‘œ π‘π‘œπ‘£π‘’π‘Ÿ 45 π‘˜π‘š π‘Žπ‘‘ 𝑠𝑝𝑒𝑒𝑑 π‘œπ‘“
90π‘˜π‘š
= 0.5 β„Žπ‘œπ‘’π‘Ÿ
β„Žπ‘Ÿ
𝐻𝑒𝑛𝑐𝑒 π‘‘β„Žπ‘’ π‘‘π‘œπ‘‘π‘Žπ‘™ π‘‘π‘–π‘šπ‘’ π‘‘π‘œ π‘π‘œπ‘£π‘’π‘Ÿ 345 π‘˜π‘š = 4.5 β„Žπ‘Ÿ
Q8. A man takes 150 steps in walking 75 meters. If he takes 3 steps in 1 second, find
his speed in (i) m/sec (ii) km/hr.
πΏπ‘’π‘›π‘”π‘‘β„Ž π‘œπ‘“ π‘œπ‘›π‘’ 𝑠𝑑𝑒𝑝 =
75
= 0.5 π‘š
150
π·π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ π‘π‘œπ‘£π‘’π‘Ÿπ‘’π‘‘ 𝑖𝑛 1 𝑠𝑒𝑐 = 0.5 × 3 = 1.5 π‘š/𝑠𝑒𝑐
𝑖) 𝑆𝑝𝑒𝑒𝑑 𝑖𝑛 π‘š/𝑠 = 1.5 π‘š/𝑠𝑒𝑐
𝑖𝑖) 𝑆𝑝𝑒𝑒𝑑 𝑖𝑛
π‘˜π‘š 1.5 π‘˜π‘š × 3600
=
= 5.4 π‘˜π‘š/β„Žπ‘Ÿ
β„Žπ‘Ÿ
1000 × 1β„Žπ‘Ÿ
Q9. A man walks at 5 km/hr for 6 hours and at 4 km/hr for l2hours. Find his average
speed.
π‘‡π‘œπ‘‘π‘Žπ‘™ π·π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ πΆπ‘œπ‘£π‘’π‘Ÿπ‘’π‘‘
π‘‡π‘œπ‘‘π‘Žπ‘™ π‘‘π‘–π‘šπ‘’ π‘‘π‘Žπ‘˜π‘’π‘› π‘‘π‘œ π‘π‘œπ‘£π‘’π‘Ÿ π‘‘β„Žπ‘’ π‘‘π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’
5 × 6 + 4 × 12
1 π‘˜π‘š
π΄π‘£π‘’π‘Ÿπ‘Žπ‘”π‘’ 𝑆𝑝𝑒𝑒𝑑 =
=4
6 + 12
3 β„Žπ‘Ÿ
π΄π‘£π‘’π‘Ÿπ‘Žπ‘”π‘’ 𝑆𝑝𝑒𝑒𝑑 =
Q10. A man covers a distance of 144 km at the speed of 36 km/hr and another 256 km
at the speed of 64 km/hr. Find his average speed for the whole journey.
π‘‡π‘œπ‘‘π‘Žπ‘™ π·π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ πΆπ‘œπ‘£π‘’π‘Ÿπ‘’π‘‘
π‘‡π‘œπ‘‘π‘Žπ‘™ π‘‘π‘–π‘šπ‘’ π‘‘π‘Žπ‘˜π‘’π‘› π‘‘π‘œ π‘π‘œπ‘£π‘’π‘Ÿ π‘‘β„Žπ‘’ π‘‘π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’
144 + 256
π‘˜π‘š
π΄π‘£π‘’π‘Ÿπ‘Žπ‘”π‘’ 𝑆𝑝𝑒𝑒𝑑 =
= 50
144 256
β„Žπ‘Ÿ
+
36
64
π΄π‘£π‘’π‘Ÿπ‘Žπ‘”π‘’ 𝑆𝑝𝑒𝑒𝑑 =
3
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Q11. Two buses travel to a place at 45 km/hr and 60 km/hr respectively. If the second
1
bus takes 5 hours less than the first for the same journey, find the length of the
2
journey.
𝐿𝑒𝑑 π‘₯ 𝑏𝑒 π‘‘β„Žπ‘’ π‘‘π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ π‘œπ‘“ π‘‘β„Žπ‘’ π‘—π‘œπ‘’π‘Ÿπ‘›π‘’π‘¦
π‘₯
π‘‡π‘–π‘šπ‘’ π‘‘π‘Žπ‘˜π‘’π‘› 𝑏𝑦 π‘‘β„Žπ‘’ πΉπ‘–π‘Ÿπ‘ π‘‘ 𝑏𝑒𝑠 =
β„Žπ‘Ÿ
45
π‘₯
π‘‡π‘–π‘šπ‘’ π‘‘π‘Žπ‘˜π‘’π‘› 𝑏𝑦 π‘‘β„Žπ‘’ π‘†π‘’π‘π‘œπ‘›π‘‘ 𝑏𝑒𝑠 =
β„Žπ‘Ÿ
60
π‘₯
π‘₯
11
π‘‡β„Žπ‘’π‘Ÿπ‘’π‘“π‘œπ‘Ÿπ‘’:
βˆ’
=
45 60
2
π‘†π‘œπ‘™π‘£π‘–π‘›π‘” π‘“π‘œπ‘Ÿ π‘₯ = 990 π‘˜π‘š
Q12. A boy goes to school from his village at 3km/hr and returns back at 2km/hr. If
he takes 5 hours in all, what is the distance between the village and the school?
𝐿𝑒𝑑 π‘₯ 𝑏𝑒 π‘‘β„Žπ‘’ π‘‘π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ π‘œπ‘“ π‘‘β„Žπ‘’ π‘—π‘œπ‘’π‘Ÿπ‘›π‘’π‘¦
π‘₯
π‘‡π‘–π‘šπ‘’ π‘‘π‘Žπ‘˜π‘’π‘› π‘‘π‘œ π‘Ÿπ‘’π‘Žπ‘β„Ž π‘ π‘β„Žπ‘œπ‘œπ‘™ = β„Žπ‘Ÿ
3
π‘₯
π‘‡π‘–π‘šπ‘’ π‘‘π‘Žπ‘˜π‘’π‘› π‘Ÿπ‘’π‘‘π‘’π‘Ÿπ‘› π‘“π‘Ÿπ‘œπ‘š = β„Žπ‘Ÿ
2
π‘₯ π‘₯
π‘‡β„Žπ‘’π‘Ÿπ‘’π‘“π‘œπ‘Ÿπ‘’: + = 5
3 2
π‘†π‘œπ‘™π‘£π‘–π‘›π‘” π‘“π‘œπ‘Ÿ π‘₯ = 6 π‘˜π‘š
1
Q13. A bus completes a journey of 420 km in 6 hours. The first ¾ part of the
2
journey performed at 63 km/hr. Calculate the speed of the rest of the journey.
𝐿𝑒𝑑 π‘₯ 𝑏𝑒 π‘‘β„Žπ‘’ 𝑠𝑝𝑒𝑒𝑑 π‘œπ‘“ π‘‘β„Žπ‘’ π‘Ÿπ‘’π‘ π‘‘ π‘œπ‘“ π‘‘β„Žπ‘’ π‘—π‘œπ‘’π‘Ÿπ‘›π‘’π‘¦
3
1
105
1
× 420 ×
+
=6
4
63
π‘₯
2
π‘†π‘œπ‘™π‘£π‘–π‘›π‘” π‘“π‘œπ‘Ÿ π‘₯ = 70 π‘˜π‘š/β„Žπ‘Ÿ
4
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Q14. A man drives 150 km from town A to town B in 3 hours 20 min and returns back
to town A from town B in 4 hours 10 min. Find his average speed for the whole
journey.
π‘‡π‘œπ‘‘π‘Žπ‘™ π·π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ πΆπ‘œπ‘£π‘’π‘Ÿπ‘’π‘‘
π‘‡π‘œπ‘‘π‘Žπ‘™ π‘‘π‘–π‘šπ‘’ π‘‘π‘Žπ‘˜π‘’π‘› π‘‘π‘œ π‘π‘œπ‘£π‘’π‘Ÿ π‘‘β„Žπ‘’ π‘‘π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’
150 + 150
π‘˜π‘š
π΄π‘£π‘’π‘Ÿπ‘Žπ‘”π‘’ 𝑆𝑝𝑒𝑒𝑑 =
= 40
1
1
β„Žπ‘Ÿ
3 + 4
3
6
π΄π‘£π‘’π‘Ÿπ‘Žπ‘”π‘’ 𝑆𝑝𝑒𝑒𝑑 =
Q15. A car completed a journey in 7 hours. One-third of the journey was performed
at 20 km/hr and the rest at 30 km/hr. Find the total length of the journey.
𝐿𝑒𝑑 π‘₯ 𝑏𝑒 π‘‘β„Žπ‘’ π‘‘π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ π‘œπ‘“ π‘‘β„Žπ‘’ π‘—π‘œπ‘’π‘Ÿπ‘›π‘’π‘¦
π‘₯/3 2π‘₯/3
+
=7
20
30
π‘†π‘œπ‘™π‘£π‘–π‘›π‘” π‘“π‘œπ‘Ÿ π‘₯ = 180 π‘˜π‘š
1
Q16. A cyclist covered a certain distance in 3 hours. The speed for first half of the
2
distance was15 km/hr and for the second half it was 20 km/hr. Find the total distance
covered by him.
𝐿𝑒𝑑 π‘₯ 𝑏𝑒 π‘‘β„Žπ‘’ π‘‘π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ π‘œπ‘“ π‘‘β„Žπ‘’ π‘—π‘œπ‘’π‘Ÿπ‘›π‘’π‘¦
π‘₯/2 π‘₯/2
1
+
=3
15
20
2
π‘†π‘œπ‘™π‘£π‘–π‘›π‘” π‘“π‘œπ‘Ÿ π‘₯ = 60 π‘˜π‘š
Q17. A person travels equal distances with speeds of 3 km/hr, 4 km/hr and 5 km/hr
and takes a total time of 47 minutes. Find the total distance.
𝐿𝑒𝑑 π‘₯ 𝑏𝑒 π‘‘β„Žπ‘’ π‘‘π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ π‘œπ‘“ π‘’π‘Žπ‘β„Ž 𝑙𝑒𝑔
π‘₯ π‘₯ π‘₯ 47
+ + =
3 4 5 60
5
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π‘†π‘œπ‘™π‘£π‘–π‘›π‘” π‘“π‘œπ‘Ÿ π‘₯ = 1 π‘˜π‘š π‘Žπ‘›π‘‘ π‘‘β„Žπ‘’ π‘‘π‘œπ‘‘π‘Žπ‘™ π‘‘π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ = 3 π‘˜π‘š
Q18. A farmer travelled a distance of 61 km in 9 hours. He travelled partly on foot at
4 km/hr and partly on bicycle at 9 km./hr. Find the distance travelled by him on foot.
𝐿𝑒𝑑 π‘₯ 𝑏𝑒 π‘‘β„Žπ‘’ π‘‘π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ π‘‘π‘Ÿπ‘Žπ‘£π‘’π‘™π‘’π‘‘ 𝑏𝑦 π‘“π‘œπ‘œπ‘‘
π‘₯ 61 βˆ’ π‘₯
+
=9
4
9
π‘†π‘œπ‘™π‘£π‘–π‘›π‘” π‘“π‘œπ‘Ÿ π‘₯ = 16 π‘˜π‘š
1
Q19. Rohan cycles to his office at the rate of 12 km/hr and is late by 3 minutes.
2
However, if he travels at 15 km/hr, he reaches 5 minutes earlier than the usual time.
What is the distance of his office from his residence?
𝐿𝑒𝑑 π‘₯ 𝑏𝑒 π‘‘β„Žπ‘’ π‘‘π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ π‘‘π‘œ π‘œπ‘“π‘“π‘–π‘π‘’. The difference of the time in the two cases
is 8 minutes.
π‘₯
π‘₯
8
βˆ’
=
12.5 15
60
π‘†π‘œπ‘™π‘£π‘–π‘›π‘” π‘“π‘œπ‘Ÿ π‘₯ = 10 π‘˜π‘š (Distance of his office from his residency)
Q20. Robert is travelling on his cycle and has calculated to reach point A at 2 p.m. if
he travels at 10 km/hr. However, he will reach there at 12 noon if he travels at 15
km/hr. At what speed must he travel to reach A at 1P.m.?
𝐿𝑒𝑑 π‘‘β„Žπ‘’ π‘‘π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ π‘‘π‘Ÿπ‘Žπ‘£π‘’π‘™π‘™π‘’π‘‘ = π‘₯ π‘˜π‘š
π‘₯
π‘₯
βˆ’
=2
10 15
π‘†π‘œπ‘™π‘£π‘–π‘›π‘” π‘“π‘œπ‘Ÿ π‘₯ = 60 π‘˜π‘š
60 60
βˆ’
=1
10
𝑆
6
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π‘†π‘œπ‘™π‘£π‘–π‘›π‘” π‘“π‘œπ‘Ÿ 𝑆 = 12 π‘˜π‘š/β„Žπ‘Ÿ
Q21. If a train runs at 40 km/hr, it reaches its destination late by 11 minutes, but if it
runs at 50 km/hr, it is late by 5 minutes only. Find the correct time for the train to
complete its journey.
𝐿𝑒𝑑 π‘₯ 𝑏𝑒 π‘‘β„Žπ‘’ π‘‘π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ π‘‘π‘Ÿπ‘Žπ‘£π‘’π‘™π‘™π‘’π‘‘ 𝑏𝑦 π‘‘β„Žπ‘’ π‘‘π‘Ÿπ‘Žπ‘–π‘› = π‘₯ π‘˜π‘š
π‘₯
π‘₯
6
βˆ’
=
40 50
60
π‘†π‘œπ‘™π‘£π‘–π‘›π‘” π‘“π‘œπ‘Ÿ π‘₯ = 20 π‘˜π‘š (Distance of his office from his residency)
π‘‡π‘–π‘šπ‘’ π‘‘π‘Žπ‘˜π‘’π‘› π‘‘π‘œ π‘π‘œπ‘£π‘’π‘Ÿ 20 π‘˜π‘š = 30 π‘šπ‘–π‘›π‘’π‘‘π‘’π‘ 
π‘‡β„Žπ‘’π‘Ÿπ‘’π‘“π‘œπ‘Ÿπ‘’ π‘‘β„Žπ‘’ π‘π‘œπ‘Ÿπ‘Ÿπ‘’π‘π‘‘ π‘‘π‘–π‘šπ‘’ 𝑖𝑠 19 π‘šπ‘–π‘›π‘’π‘‘π‘’π‘ 
Q22. The distance between Delhi and Hyderabad is 1800 km. A train leaves Delhi and
proceeds towards Hyderabad at a uniform speed of 60 km/hr. Another train leaves
Hyderabad at the same time and proceeds towards Delhi at a uniform speed of 48
km/hr. When and where will they meet?
𝐿𝑒𝑑 π‘‘β„Žπ‘’ π‘‘π‘Ÿπ‘Žπ‘–π‘› π‘šπ‘’π‘’π‘‘ π‘Žπ‘‘ π‘Ž π‘‘π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ π‘₯ π‘“π‘Ÿπ‘œπ‘š π·π‘’π‘™β„Žπ‘–
π‘₯
1800 βˆ’ π‘₯
=
60
48
π‘†π‘œπ‘™π‘£π‘–π‘›π‘” π‘“π‘œπ‘Ÿ π‘₯ = 1000 π‘˜π‘š. π‘‡β„Žπ‘’ π‘‘π‘Ÿπ‘Žπ‘–π‘›π‘  𝑀𝑖𝑙𝑙 π‘šπ‘’π‘’π‘‘ 1000π‘˜π‘š π‘“π‘Ÿπ‘œπ‘š π·π‘’π‘™β„Žπ‘–.
π‘‡π‘–π‘šπ‘’ π‘‘π‘Žπ‘˜π‘’π‘› π‘π‘’π‘“π‘œπ‘Ÿπ‘’ π‘‘β„Žπ‘’π‘š π‘šπ‘’π‘’π‘‘ =
1000
2
= 16 β„Žπ‘Ÿ
60
3
7
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