Cuboid Investigation Volume: Total space inside the cuboid Formula: π = πππππ‘β × π€πππ‘β × βπππβπ‘ Units: Usually ππ3 (βcubic centimetresβ, βcentimetres cubedβ, βccβ, βmlβ) Surface area: The total area (flat space) of all 6 faces of the cuboid Formula: ππ΄ = 2 × (πππππ‘β × π€πππ‘β + πππππ‘β × βπππβπ‘ + π€πππ‘β × βπππβπ‘) Units: Usually ππ2 (βsquare centimetresβ, βcentimetres squaredβ) Investigate the different surface areas of cuboids with a volume of ππππππ . What is the largest surface area you can find? What is the smallest? ο· How do I begin? Think of any three numbers that multiply together to make 900. These can be the dimensions of your cuboid. Draw a diagram and work out the total surface area. ο· What next? Once you have three numbers that work, you can create a new set of three by scaling one number up and another down. Eg, if you have 50ππ, 9ππ and 2ππ, then 25ππ, 18ππ and 2ππ will also work (halving one number and doubling another in this case). Eg: Dimensions: Surface area: πΏππππ‘β = 2ππ ππππ‘β = 50ππ 2 × (2 × 50 + 2 × 9 + 50 × 9) = πππππππ Conclusions: The cuboid with the largest surface area was: ____________________ It has a total surface area of: ____________________ The cuboid with the smallest surface area was: ____________________ It has a total surface area of: ____________________ What do you notice? π»πππβπ‘ = 9ππ Cuboid Investigation SOLUTIONS Volume: Total space inside the cuboid Formula: π = πππππ‘β × π€πππ‘β × βπππβπ‘ Units: Usually ππ3 (βcubic centimetresβ, βcentimetres cubedβ, βccβ, βmlβ) Surface area: The total area (flat space) of all 6 faces of the cuboid Formula: ππ΄ = 2 × (πππππ‘β × π€πππ‘β + πππππ‘β × βπππβπ‘ + π€πππ‘β × βπππβπ‘) Units: Usually ππ2 (βsquare centimetresβ, βcentimetres squaredβ) Investigate the different surface areas of cuboids with a volume of ππππππ . What is the largest surface area you can find? What is the smallest? ο· How do I begin? Think of any three numbers that multiply together to make 900. These can be the dimensions of your cuboid. Draw a diagram and work out the total surface area. ο· What next? Once you have three numbers that work, you can create a new set of three by scaling one number up and another down. Eg, if you have 50ππ, 9ππ and 2ππ, then 25ππ, 18ππ and 2ππ will also work (halving one number and doubling another in this case). Eg: Dimensions: Surface area: πΏππππ‘β = 2ππ ππππ‘β = 50ππ π»πππβπ‘ = 9ππ 2 × (2 × 50 + 2 × 9 + 50 × 9) = πππππππ Conclusions: The cuboid with the largest surface area was: 1ππ × 1ππ × 900ππ It has a total surface area of: 3602ππ2 (note: no limit on surface area if not restricted to whole numbers) The cuboid with the smallest surface area was: 9ππ × 10ππ × 10ππ It has a total surface area of: 560ππ2 (note: the cube 9.65 β¦ ππ × 9.65 β¦ ππ × 9.65 β¦ ππ × gives the overall min: 559.3 β¦ ππ2 ) What do you notice? The more similar the lengths, the smaller the surface area. The closer the cuboid gets to a cube, the smaller the surface area. Cuboid Investigation SOLUTIONS Continued Full list of possible surface areas for each integer factor triple: Length Width Height 9 6 5 5 5 6 4 5 4 5 3 3 3 4 3 3 2 3 2 2 2 3 2 2 2 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 10 10 12 10 9 6 15 6 9 5 15 12 10 5 6 5 18 4 15 10 9 3 6 5 3 2 30 25 20 18 15 12 10 9 6 5 4 3 2 1 10 15 15 18 20 25 15 30 25 36 20 25 30 45 50 60 25 75 30 45 50 100 75 90 150 225 30 36 45 50 60 75 90 100 150 180 225 300 450 900 SA 560 600 630 640 650 672 690 720 722 770 810 822 840 850 936 990 1072 1074 1080 1120 1136 1218 1224 1280 1512 1808 1920 1922 1930 1936 1950 1974 2000 2018 2112 2170 2258 2406 2704 3602
© Copyright 2026 Paperzz