South Pasadena • Chemistry
Name
Period
Date
1 · Chemistry Foundations
STATION 1
•
SIGNIFICANT FIGURES
Indicate the number of significant figures in each of the following measurements.
0.092
2
5700
2
10.003
5
0.003800
4
80900
3
0.00350
3
101.00
5
0.003
1
Perform the following calculations, writing the answer with the correct number of significant figures.
(1.0)(0.850)
(0.08206)(298) = 0.03475931018 = 0.035
2600
= 24.27402008 = 24
(4.184)(25.6)
(2 sig figs)
(2 sig figs)
94.7 + 8.3 = 103.0 (round to tenths)
1 · Chemistry Foundations
STATION 2
•
SCIENTIFIC NOTATION
Write the following numbers in standard decimal notation.
3.29 × 10–4
0.000329
1.6 × 108
160,000,000
9 × 103
9000
2.1665 × 10–1
0.21665
4.218 × 100
4.218
5.005 × 102
500.5
Write the following numbers in scientific notation.
5.28
__5.28 × 100_____
6,589,000
____6.589 × 106___
2,000
__2 × 103_______
0.0009
____9 × 10−4______
15
__1.5 × 101______
0.092
____9.2 × 10−2____
32.8 × 104
3.28 × 105
0.00472 × 10–3
4.72 × 10−6
1 · Chemistry Foundations
STATION 3
•
MEASUREMENTS
Record the following measurements.
1
2
3
4
5
cm
10
20
30
40
50
mm
200
3.8 cm
25.1 mm
50
1
2
3
4
5
cm
4.20 cm
1
2
3
4
5
cm
0.52 cm
2
10
100
40
147 mL
1
42.1mL
0.72mL
0
8.3
°C
Use the plastic ruler to record the length of this line in cm:
12.52 cm
1 · Chemistry Foundations
STATION 4
• ACCURACY & PRECISION
Consider the following data from groups in Mr. Groves’ class for the mass of an object:
Group 1
Group 2
Group 3
Group 4
Group 5
Group 6
12.53 g
12.82 g
11.78 g
11.95 g
12.02 g
12.10 g
Dev: 0.38
0.67
0.37
0.20
0.13
0.05
This data should be reported as: _________  __________ g
Show your work.
Group 7
11.83 g
0.32
12.53 + 12.82 + 11.78 + 11.95 + 12.02 + 12.10 + 11.83
= 12.15 g
7
0.38 + 0.67 + 0.37 + 0.20 + 0.13 + 0.05 + 0.32
Avg deviation =
= 0.30 g
7
12.15 ± 0.30 g
Avg mass =
If the accepted mass is 12.15 g, what is the percent error of Group 1’s measurement?
% error =
| measured - accepted |
| 12.53 g − 12.15 g |
× 100% =
× 100% = 3.1%
accepted
12.15 g
Mr. Ku’s class obtains an answer of 12.05  0.45 g. The result of Mr. Ku’s class has [ more | less | the same ]
precision than/as that of Mr. Groves’ class.
1 · Chemistry Foundations
STATION 5
1 dm =
0.1 m
1 kg =
1000
g
1 mL =
0.001
L
•
1 cm =
2.50 kg = ? g
1000 g
2.50 kg 
 1 kg  = 2500 g
0.350 dL = ? L
12.6 m = ? km
1 km 
12.6 m 
= 0.0126 km
1000 m
2570 cm = ? km
1 km 
2570 cm 
= 0.0257 km
100000
–20°C = ? K
500 K = ? °C
UNITS
0.01
m
0.350 dL 
1L 
10 dL = 0.0350 L
K = −20 + 273 = 253 K
°C = 500 – 273 = 227°C
1 · Chemistry Foundations
STATION 6
• DIMENSIONAL
1.8 wks = ? min
7 d  24 h 60 min  60 s 
1.8 wk 
1 wk  1 d   1 h  1 min = 1,088,640 s
135 cm3 = ? in3
(1 inch = 2.54 cm)
3
1
in
 = 8.24 in3
135 cm3 
2.54 cm
2.3 m/s = ? km/h
2.3 m  1 km   60 s  60 min
= 8.28 km/h
s 1000 m 1 min  h 
ANALYSIS 1
1 · Chemistry Foundations
STATION 7
• DIMENSIONAL
ANALYSIS 2
Every roll contains 40 quarters. Each roll has a mass of 226.8 g.
1 roll = 40 quarters, 1 roll = 226.8 g
2.8 rolls = ? quarters
40 quarters
2.8 roll 
 1 roll  = 112 quarters
1814.4 grams = ? rolls
1 roll 
1814.4 g 
226.8 g = 8 rolls
85.05 grams = ? quarters
1 roll  40 quarters
85.05 g 
226.8 g  1 roll  = 15 quarters
1 quarter = ? grams
1 roll  226.8 g
1 quarter 
40 quarters  1 roll  = 5.67 g
1 · Chemistry Foundations
STATION 8
• DENSITY IDEAS
If a column of ethanol and water is created, the ethanol forms the top layer and water forms the bottom layer.
The density of ethanol is [ less than | the same as | greater than ] that of water.
If a 50.0-mL sample of each is obtained, the mass of ethanol is [ less than | the same as | greater than ] that of
water.
A 50-g piece of tree bark floats on water, while a 50-g piece of bone sinks.
List water, tree bark, and bone from least to most dense:
tree bark
<
water
<
bone
The volume of the piece of tree bark is [ less than | the same as | greater than ] that of the piece of bone.
Consider a block of aluminum (density = 2.70 g/cm3) and a block of zinc (7.14 g/cm3).
If the two blocks have the same mass, which has a greater volume? aluminum
If both blocks have a volume of 1.5 L, which has a greater mass?
zinc
1 · Chemistry Foundations
STATION 9
Data
Length of metal block
Width of metal block
Height of metal block
Mass of metal block
3.55 cm
1.55 cm
1.11 cm
54.48 g
• DENSITY
CALCULATIONS
Use the data to identify the metal in the block:
aluminum (density = 2.70 g/cm3)
copper
(density = 8.92 g/cm3)
iron
(density = 7.86 g/cm3)
gold
(density = 19.3 g/cm3)
m = 54.48 g
V = (3.55 cm)(1.55 cm)(1.11 cm) = 6.107775 cm3
D=?
D=
54.48 g
m
=
= 8.92 g/cm3
V 6.107775 cm3
The density of titanium is 4.50 g/cm3. What is the mass of a 35.0 cm3 titanium ball?
m=?
V = 35.0 cm3
D = 4.50 g/cm3
m = V × D = (35.0 cm3)(4.50 g/cm3) =158 g