CALIBRATION
DR. BILL HALLER
REMEMBER:
- Gallons/min output
- Swath width
- Speed
“are all you need!”
2.5 miles
long
30 feet
wide
Joe Gator wants to spray water hyacinths
in a canal that is 2.5 miles long and 30 feet
wide. What is the area of the canal to
betreated in acres?
2.5 miles
long
30 feet
wide
Must get answer in acres,
which is 43,560 ft square,
so must change miles into feet
Joe Gator wants to spray water hyacinths
in a canal that is 2.5 miles long and 30 feet
wide. What is the area of the canal to be
treated in acres?
TO DETERMINE ACRES, MUST GET ALL UNITS IN SQ. FT SINCE AN ACRE IS 43,560 SQ. FT
2.5 miles
long
30 feet
wide
Must get answer in acres,
which is 43,560 ft square,
so must change miles into feet
2.5 miles times 5,280 ft/per mile = 13,200 ft
Joe Gator wants to spray water hyacinths
in a canal that is 2.5 miles long and 30 feet
wide. What is the area of the canal to be
treated in acres?
TO DETERMINE ACRES, MUST GET ALL UNITS IN SQ. FT SINCE AN ACRE IS 43,560 SQ. FT
2.5 miles
long
30 feet
wide
Must get answer in acres,
which is 43,560 ft square,
so must change miles into feet
2.5 miles times 5,280 ft/per mile = 13,200 ft
So area is 30 ft wide times 13,200 ft long = 396,000 ft sq.
Joe Gator wants to spray water hyacinths
in a canal that is 2.5 miles long and 30 feet
wide. What is the area of the canal to be
treated in acres?
TO DETERMINE ACRES, MUST GET ALL UNITS IN SQ. FT SINCE AN ACRE IS 43,560 SQ. FT
2.5 miles
long
30 feet
wide
Must get answer in acres,
which is 43,560 ft square,
so must change miles into feet
2.5 miles times 5,280 ft/per mile = 13,200 ft
So area is 30 ft wide times 13,200 ft long = 396,000 ft sq.
So divide by sq. ft per acre,,,
396,000 divided by 43,560 = 9.09 acres, or 9.1
Joe Gator wants to spray water hyacinths
in a canal that is 2.5 miles long and 30 feet
wide. What is the area of the canal to be
treated in acres?
TO DETERMINE ACRES, MUST GET ALL UNITS IN SQ. FT SINCE AN ACRE IS 43,560 SQ. FT
2.5 miles
long
30 feet
wide
10
feet
10
feet
Once Gator gets out to the canal he
realizes his truck mounted hand gun
will only be able to spray a distance of
10 feet on each side of the canal.
Therefore, what will be his actual area
treated in acres?
2.5 miles
long
30 feet
wide
10
feet
10
feet
THIS IS THE SAME QUESTION AS ABOVE, EXCEPT INSTEAD
OF 30 FT WIDE CANAL FULL OF WATER HYACINTHS,, THE
SWATH WIDTH IS ONLY 10 FT,, THINK ABOUT IT,, HOW MANY
ACRES WILL GATOR TREAT IF HE TREATS ONLY ONE SIDE
OF CANAL OUT A DISTANCE OF 10 FT??
Once Gator gets out to the canal he
realizes his truck mounted hand gun
will only be able to spray a distance of
10 feet on each side of the canal.
Therefore, what will be his actual area
treated in acres?
2.5 miles
long
30 feet
wide
THIS IS THE SAME QUESTION AS ABOVE, EXCEPT INSTEAD
OF 30 FT WIDE CANAL FULL OF WATER HYACINTHS,, THE
SWATH WIDTH IS ONLY 10 FT,, THINK ABOUT IT,, HOW MANY
ACRES WILL GATOR TREAT IF HE TREATS ONLY ONE SIDE
OF CANAL OUT A DISTANCE OF 10 FT??
2.5 miles times 5,280 ft/mile = 13,200 ft long, times 10 feet
wide = 132,000 sq ft.
10
feet
10
feet
Once Gator gets out to the canal he
realizes his truck mounted hand gun
will only be able to spray a distance of
10 feet on each side of the canal.
Therefore, what will be his actual area
treated in acres?
2.5 miles
long
30 feet
wide
THIS IS THE SAME QUESTION AS ABOVE, EXCEPT INSTEAD
OF 30 FT WIDE CANAL FULL OF WATER HYACINTHS,, THE
SWATH WIDTH IS ONLY 10 FT,, THINK ABOUT IT,, HOW MANY
ACRES WILL GATOR TREAT IF HE TREATS ONLY ONE SIDE
OF CANAL OUT A DISTANCE OF 10 FT??
2.5 miles times 5,280 ft/mile = 13,200 ft long, times 10 feet
wide = 132,000 sq ft.
132,000 sq. ft divided by acre (43,560) = 3.03 acres treated on
each side x 2 = 6.06 acres
10
feet
10
feet
Once Gator gets out to the canal he
realizes his truck mounted hand gun
will only be able to spray a distance of
10 feet on each side of the canal.
Therefore, what will be his actual area
treated in acres?
1.75 miles across
On his way home, Gator passes by
a lake that is 1.75 miles across.
What is the surface area of this
circular lake in acres?
MUST CONVERT TO SQUARE FEET TO GET ACRES
1.75 miles across
On his way home, Gator passes by
a lake that is 1.75 miles across.
What is the surface area of this
circular lake in acres?
REMEMBER, IF ANY DIAMETER OF A CIRCLE IS GIVEN IN MILES CONVERT IT INTO FEET
BEFORE USING IN AREA OF CIRCLE FORMULA.
MUST CONVERT TO SQUARE FEET TO GET ACRES
1.75 miles times 5,280 ft/mile = 9,240 ft across the lake
1.75 miles across
On his way home, Gator passes by
a lake that is 1.75 miles across.
What is the surface area of this
circular lake in acres?
REMEMBER, IF ANY DIAMETER OF A CIRCLE IS GIVEN IN MILES CONVERT IT INTO FEET
BEFORE USING IN AREA OF CIRCLE FORMULA.
MUST CONVERT TO SQUARE FEET TO GET ACRES
1.75 miles times 5,280 ft/mile = 9,240 ft across the lake
Area of circle is A = ∏ (R)²
1.75 miles across
On his way home, Gator passes by
a lake that is 1.75 miles across.
What is the surface area of this
circular lake in acres?
REMEMBER, IF ANY DIAMETER OF A CIRCLE IS GIVEN IN MILES CONVERT IT INTO FEET
BEFORE USING IN AREA OF CIRCLE FORMULA.
MUST CONVERT TO SQUARE FEET TO GET ACRES
1.75 miles times 5,280 ft/mile = 9,240 ft across the lake
Area of circle is A = ∏ (R)²
Radius is one half of diameter or 9,240 divided by 2=4620 ft
1.75 miles across
On his way home, Gator passes by
a lake that is 1.75 miles across.
What is the surface area of this
circular lake in acres?
REMEMBER, IF ANY DIAMETER OF A CIRCLE IS GIVEN IN MILES CONVERT IT INTO FEET
BEFORE USING IN AREA OF CIRCLE FORMULA.
MUST CONVERT TO SQUARE FEET TO GET ACRES
1.75 miles times 5,280 ft/mile = 9,240 ft across the lake
Area of circle is A = ∏ (R)²
Radius is one half of diameter or 9,240 divided by 2=4620 ft
R square is R time R, so 4620 times 4620=21,344,400 ft sq
1.75 miles across
On his way home, Gator passes by
a lake that is 1.75 miles across.
What is the surface area of this
circular lake in acres?
REMEMBER, IF ANY DIAMETER OF A CIRCLE IS GIVEN IN MILES CONVERT IT INTO FEET
BEFORE USING IN AREA OF CIRCLE FORMULA.
MUST CONVERT TO SQUARE FEET TO GET ACRES
1.75 miles times 5,280 ft/mile = 9,240 ft across the lake
Area of circle is A = ∏ (R)²
Radius is one half of diameter or 9,240 divided by 2=4620 ft
R square is R time R, so 4620 times 4620=21,344,400 ft sq
1.75 miles across
A=3.14 (21,344,400)
On his way home, Gator passes by
a lake that is 1.75 miles across.
What is the surface area of this
circular lake in acres?
REMEMBER, IF ANY DIAMETER OF A CIRCLE IS GIVEN IN MILES CONVERT IT INTO FEET
BEFORE USING IN AREA OF CIRCLE FORMULA.
MUST CONVERT TO SQUARE FEET TO GET ACRES
1.75 miles times 5,280 ft/mile = 9,240 ft across the lake
Area of circle is A = ∏ (R)²
Radius is one half of diameter or 9,240 divided by 2=4620 ft
R square is R time R, so 4620 times 4620=21,344,400 ft sq
1.75 miles across
A=3.14 (21,344,400)
A=67,021,426 ft sq. so now divide by 43,560 sq ft per acre
= 1,538.6 acre
On his way home, Gator passes by
a lake that is 1.75 miles across.
What is the surface area of this
circular lake in acres?
REMEMBER, IF ANY DIAMETER OF A CIRCLE IS GIVEN IN MILES CONVERT IT INTO FEET
BEFORE USING IN AREA OF CIRCLE FORMULA.
780 feet wide
1450 feet long
Average depth = 6 feet
In Gator’s housing division, there is a
rectangle pond that is 780 feet wide,
1450 feet long and has an average
depth of 6 feet. How many acre-feet
are in this pond?
FIRST GET THE AREA IN ACRES
780 feet wide
1450 feet long
Average depth = 6 feet
AN ACRE FOOT IS AN AREA OF
WATER OF 1 ACRE 1 FOOT DEEP
In Gator’s housing division, there is a
rectangle pond that is 780 feet wide,
1450 feet long and has an average
depth of 6 feet. How many acre-feet
are in this pond?
FIRST GET THE AREA IN ACRES
780 ft times 1450 = 1,131,000 ft sq divided
by 43,560 = 25.96 acres
780 feet wide
1450 feet long
Average depth = 6 feet
AN ACRE FOOT IS AN AREA OF
WATER OF 1 ACRE 1 FOOT DEEP
In Gator’s housing division, there is a
rectangle pond that is 780 feet wide,
1450 feet long and has an average
depth of 6 feet. How many acre-feet
are in this pond?
FIRST GET THE AREA IN ACRES
780 ft times 1450 = 1,131,000 ft sq divided
by 43,560 = 25.96 acres
780 feet wide
1450 feet long
Average depth = 6 feet
AN ACRE FOOT IS AN AREA OF
WATER OF 1 ACRE 1 FOOT DEEP
Now to get volume simply multiply acres
by average depth so 6 ft deep times 25.96
acres = 155.8 acre feet.
In Gator’s housing division, there is a
rectangle pond that is 780 feet wide,
1450 feet long and has an average
depth of 6 feet. How many acre-feet
are in this pond?
Gator just bought a new 14’
fiberglass air boat. The tank on
his new boat is 300 gallons is
calibrated to apply 40 gallons of
solution per acre. How many
acres can Gator treat per tank?
THINK ABOUT THIS ONE
THESE VALUES, 128 OZ PER
GALLON, 4 QUARTS PER
GALLON, PINTS PER GALLON,
FT PER MILE, SQ FT PER ACRE
ETC ARE PROVIDED IN THE
EXAM BOOKLET, BUT THEY
ARE GOOD TO KNOW.
Gator just bought a new 14’
fiberglass air boat. The tank on
his new boat is 300 gallons is
calibrated to apply 40 gallons of
solution per acre. How many
acres can Gator treat per tank?
THINK ABOUT THIS ONE
300 GALLONS OF TANK MIX AND
SPRAYING 40 GALLONS PER ACRE
THESE VALUES, 128 OZ PER
GALLON, 4 QUARTS PER
GALLON, PINTS PER GALLON,
FT PER MILE, SQ FT PER ACRE
ETC ARE PROVIDED IN THE
EXAM BOOKLET, BUT THEY
ARE GOOD TO KNOW.
Gator just bought a new 14’
fiberglass air boat. The tank on
his new boat is 300 gallons is
calibrated to apply 40 gallons of
solution per acre. How many
acres can Gator treat per tank?
THINK ABOUT THIS ONE
300 GALLONS OF TANK MIX AND
SPRAYING 40 GALLONS PER ACRE
300 gallons divided by 40 gallons per acre
= 7.5 acres.
THESE VALUES, 128 OZ PER
GALLON, 4 QUARTS PER
GALLON, PINTS PER GALLON,
FT PER MILE, SQ FT PER ACRE
ETC ARE PROVIDED IN THE
EXAM BOOKLET, BUT THEY
ARE GOOD TO KNOW.
Gator just bought a new 14’
fiberglass air boat. The tank on
his new boat is 300 gallons is
calibrated to apply 40 gallons of
solution per acre. How many
acres can Gator treat per tank?
THINK ABOUT THIS ONE
Bonus question = you want to apply 2 qts
per acre of herbicide with this system, a
total of 7.5 acres, how much herbicide do
you put in tank???
THESE VALUES, 128 OZ PER
GALLON, 4 QUARTS PER
GALLON, PINTS PER GALLON,
FT PER MILE, SQ FT PER ACRE
ETC ARE PROVIDED IN THE
EXAM BOOKLET, BUT THEY
ARE GOOD TO KNOW.
Gator just bought a new 14’
fiberglass air boat. The tank on
his new boat is 300 gallons is
calibrated to apply 40 gallons of
solution per acre.
THINK ABOUT THIS ONE
Bonus question = you want to apply 2 qts
per acre of herbicide with this system, a
total of 7.5 acres, how much herbicide do
you put in tank???
2 quarts per acre times 7.5 acres = 15 quarts
THESE VALUES, 128 OZ PER
GALLON, 4 QUARTS PER
GALLON, PINTS PER GALLON,
FT PER MILE, SQ FT PER ACRE
ETC ARE PROVIDED IN THE
EXAM BOOKLET, BUT THEY
ARE GOOD TO KNOW.
Gator just bought a new 14’
fiberglass air boat. The tank on
his new boat is 300 gallons is
calibrated to apply 40 gallons of
solution per acre.
THINK ABOUT THIS ONE
Bonus question = how many gallons is 15
quarts???
THESE VALUES, 128 OZ PER
GALLON, 4 QUARTS PER
GALLON, PINTS PER GALLON,
FT PER MILE, SQ FT PER ACRE
ETC ARE PROVIDED IN THE
EXAM BOOKLET, BUT THEY
ARE GOOD TO KNOW.
Gator just bought a new 14’
fiberglass air boat. The tank on
his new boat is 300 gallons is
calibrated to apply 40 gallons of
solution per acre.
THINK ABOUT THIS ONE
Bonus question = how many gallons is 15
quarts???
There are 4 qts in a gallon, so 15 divided by 4
= 3.75 gallons
THESE VALUES, 128 OZ PER
GALLON, 4 QUARTS PER
GALLON, PINTS PER GALLON,
FT PER MILE, SQ FT PER ACRE
ETC ARE PROVIDED IN THE
EXAM BOOKLET, BUT THEY
ARE GOOD TO KNOW.
Gator just bought a new 14’
fiberglass air boat. The tank on
his new boat is 300 gallons is
calibrated to apply 40 gallons of
solution per acre.
THINK ABOUT THIS ONE
Bonus question = how many ounces in 0.75
gallons???
THESE VALUES, 128 OZ PER
GALLON, 4 QUARTS PER
GALLON, PINTS PER GALLON,
FT PER MILE, SQ FT PER ACRE
ETC ARE PROVIDED IN THE
EXAM BOOKLET, BUT THEY
ARE GOOD TO KNOW.
Gator just bought a new 14’
fiberglass air boat. The tank on
his new boat is 300 gallons is
calibrated to apply 40 gallons of
solution per acre.
THINK ABOUT THIS ONE
Bonus question = how many ounces in 0.75
gallons???
128 ounces per gallon times 0.75 gallons = 96
ounces
Why did the airboat sink?
Gator just bought a new 14’
fiberglass air boat. The tank on
his new boat is 300 gallons is
calibrated to apply 40 gallons of
solution per acre.
While reading a label, Gator reads
that a surfactant needs to be added
to the tank at 2% v/v. If his tank is
300 gallons, how many gallons of
surfactant does Gator need to add
to the tank?
2.0% is like 2 gallons in 100 gallons total mix
or 98 water plus 2 gallons of surfactant.
(Can you answer without a calculator???)
ALWAYS, ALWAYS, ALWAYS
MOVE DECIMAL FOR
PERCENT TWO PLACES TO
THE LEFT AND THEN
MULTIPLY.
While reading a label, Gator reads
that a surfactant needs to be added
to the tank at 2% v/v. If his tank is
300 gallons, how many gallons of
surfactant does Gator need to add
to the tank?
2.0% is like 2 gallons in 100 gallons total mix
or 98 water plus 2 gallons of surfactant.
(Can you answer without a calculator???)
2.0% = .02 times 300 gallons
= 6 gallons of surfactant
ALWAYS, ALWAYS, ALWAYS
MOVE DECIMAL FOR
PERCENT TWO PLACES TO
THE LEFT AND THEN
MULTIPLY.
While reading a label, Gator reads
that a surfactant needs to be added
to the tank at 2% v/v. If his tank is
300 gallons, how many gallons of
surfactant does Gator need to add
to the tank?
How
many
feet in
60 sec ?
35 sec
15 feet
Gator decides to determine the
speed of his new boat. If his spray
width is 15 feet wide while moving
forward at a rate of 80 feet every 35
second, what is Gator’s speed in
feet per minute?
How
many
feet in
60 sec ?
RED HERRING HERE - READ THE QUESTION,
WHAT IS ASKED???
35 sec
15 feet
Gator decides to determine the
speed of his new boat. If his spray
width is 15 feet wide while moving
forward at a rate of 80 feet every 35
second, what is Gator’s speed in
feet per minute?
How
many
feet in
60 sec ?
RED HERRING HERE - READ THE QUESTION,
WHAT IS ASKED???
Since there are 60 seconds in a minute, why not find
his speed in feet per second and multiply by 60???
35 sec
15 feet
Gator decides to determine the
speed of his new boat. If his spray
width is 15 feet wide while moving
forward at a rate of 80 feet every 35
second, what is Gator’s speed in
feet per minute?
How
many
feet in
60 sec ?
RED HERRING HERE - READ THE QUESTION,
WHAT IS ASKED???
Since there are 60 seconds in a minute, why not find
his speed in feet per second and multiply by 60???
80 ft divided by 30 seconds = 2.285 ft per
second times 60 seconds per minute equals 137
ft per minute.
35 sec
15 feet
Gator decides to determine the
speed of his new boat. If his spray
width is 15 feet wide while moving
forward at a rate of 80 feet every 35
second, what is Gator’s speed in
feet per minute?
Once again being the careful young
man he is, Gator decides to check the
calibration of his new equipment. He
collects 13 gallons of water during a 4
minute period. What is the output rate
(gallons/minute) of his new pump?
13 gallons in 4 minutes
Once again being the careful young
man he is, Gator decides to check the
calibration of his new equipment. He
collects 13 gallons of water during a 4
minute period. What is the output rate
(gallons/minute) of his new pump?
13 gallons in 4 minutes
13 divided by 4 = 3.25 gpm
Once again being the careful young
man he is, Gator decides to check the
calibration of his new equipment. He
collects 13 gallons of water during a 4
minute period. What is the output rate
(gallons/minute) of his new pump?
10’ 10’
Gator is asked to come out and spray a
canal that is 2.5 miles long; however, he
can only spray 10 feet on each side. His
equipment is calibrated to deliver 50
gallons per acre. How many total gallons
of mix will it take Gator to spray the canal?
10 ft on 2 sides = 20 ft sprayed
10’ 10’
Gator is asked to come out and spray a
canal that is 2.5 miles long; however, he
can only spray 10 feet on each side. His
equipment is calibrated to deliver 50
gallons per acre. How many total gallons
of mix will it take Gator to spray the canal?
10 ft on 2 sides = 20 ft sprayed
2.5 miles x 5,280 ft/mi = 13,200 ft long
10’ 10’
Gator is asked to come out and spray a
canal that is 2.5 miles long; however, he
can only spray 10 feet on each side. His
equipment is calibrated to deliver 50
gallons per acre. How many total gallons
of mix will it take Gator to spray the canal?
10 ft on 2 sides = 20 ft sprayed
2.5 miles x 5,280 ft/mi = 13,200 ft long
20 x 13,200 ft =
10’ 10’
264,000 ft²
43,560
= 6.06 acres
Gator is asked to come out and spray a
canal that is 2.5 miles long; however, he
can only spray 10 feet on each side. His
equipment is calibrated to deliver 50
gallons per acre. How many total gallons
of mix will it take Gator to spray the canal?
10 ft on 2 sides = 20 ft sprayed
2.5 miles x 5,280 ft/mi = 13,200 ft long
20 x 13,200 ft =
264,000 ft²
43,560
= 6.06 acres
50 gallons on each acre so 50 x 6.06 = 303 gallons
10’ 10’
Gator is asked to come out and spray a
canal that is 2.5 miles long; however, he
can only spray 10 feet on each side. His
equipment is calibrated to deliver 50
gallons per acre. How many total gallons
of mix will it take Gator to spray the canal?
Gator has had a rough week and decides to spray a
canal via his truck using a hand gun. He calculates
his speed along the canal bank to be 200 feet per
minute. If his handgun will cover a swath 25 feet wide
and the handgun will discharge 4 gallons of spray per
minute, what is the spray volume (gallons per acre)?
200 ft/min x 25 ft wide = 5,000 ft²/min
Gator has had a rough week and decides to spray a
canal via his truck using a hand gun. He calculates
his speed along the canal bank to be 200 feet per
minute. If his handgun will cover a swath 25 feet wide
and the handgun will discharge 4 gallons of spray per
minute, what is the spray volume (gallons per acre)?
200 ft/min x 25 ft wide = 5,000 ft²/min
43,560
5,000
= 8.71 minutes to cover 1 acre
Gator has had a rough week and decides to spray a
canal via his truck using a hand gun. He calculates
his speed along the canal bank to be 200 feet per
minute. If his handgun will cover a swath 25 feet wide
and the handgun will discharge 4 gallons of spray per
minute, what is the spray volume (gallons per acre)?
200 ft/min x 25 ft wide = 5,000 ft²/min
43,560
5,000
= 8.71 minutes to cover 1 acre
4 gallons/min x 8.7 min/acre
= 34.8 gallons/acre
Gator has had a rough week and decides to spray a
canal via his truck using a hand gun. He calculates
his speed along the canal bank to be 200 feet per
minute. If his handgun will cover a swath 25 feet wide
and the handgun will discharge 4 gallons of spray per
minute, what is the spray volume (gallons per acre)?
Gator has a bad problem with algae in a 4 acre pond with an average
depth of 7.5 feet. He decides to use an algaecide containing 3 pounds
of active ingredient (3EC) per gallon. Being the great calibration
specialist he is, Gator reads the label which specifies a 0.5 ppm active
ingredient treatment rate. How many gallons of product does Gator
need to purchase?
Anything with ppm/ppb need pond volume
Gator has a bad problem with algae in a 4 acre pond with an average
depth of 7.5 feet. He decides to use an algaecide containing 3 pounds
of active ingredient (3EC) per gallon. Being the great calibration
specialist he is, Gator reads the label which specifies a 0.5 ppm active
ingredient treatment rate. How many gallons of product does Gator
need to purchase?
Anything with ppm/ppb need pond volume
1 acre ft = 2.7 million pounds of water
Gator has a bad problem with algae in a 4 acre pond with an average
depth of 7.5 feet. He decides to use an algaecide containing 3 pounds
of active ingredient (3EC) per gallon. Being the great calibration
specialist he is, Gator reads the label which specifies a 0.5 ppm active
ingredient treatment rate. How many gallons of product does Gator
need to purchase?
Anything with ppm/ppb need pond volume
1 acre ft = 2.7 million pounds of water
2.7 lbs AI/acre ft = 1 ppm
Gator has a bad problem with algae in a 4 acre pond with an average
depth of 7.5 feet. He decides to use an algaecide containing 3 pounds
of active ingredient (3EC) per gallon. Being the great calibration
specialist he is, Gator reads the label which specifies a 0.5 ppm active
ingredient treatment rate. How many gallons of product does Gator
need to purchase?
Anything with ppm/ppb need pond volume
1 acre ft = 2.7 million pounds of water
2.7 lbs AI/acre ft = 1 ppm
.0027 lbs AI/acre ft = 1 ppb
Gator has a bad problem with algae in a 4 acre pond with an average
depth of 7.5 feet. He decides to use an algaecide containing 3 pounds
of active ingredient (3EC) per gallon. Being the great calibration
specialist he is, Gator reads the label which specifies a 0.5 ppm active
ingredient treatment rate. How many gallons of product does Gator
need to purchase?
Anything with ppm/ppb need pond volume
1 acre ft = 2.7 million pounds of water
2.7 lbs AI/acre ft = 1 ppm
.0027 lbs AI/acre ft = 1 ppb
Need 0.5 ppm in pond or 0.5ppm/acre ft
Gator has a bad problem with algae in a 4 acre pond with an average
depth of 7.5 feet. He decides to use an algaecide containing 3 pounds
of active ingredient (3EC) per gallon. Being the great calibration
specialist he is, Gator reads the label which specifies a 0.5 ppm active
ingredient treatment rate. How many gallons of product does Gator
need to purchase?
Anything with ppm/ppb need pond volume
1 acre ft = 2.7 million pounds of water
2.7 lbs AI/acre ft = 1 ppm
.0027 lbs AI/acre ft = 1 ppb
Need 0.5 ppm in pond or 0.5ppm/acre ft
0.5 x 2.7 = 1.35 lbs AI/acre ft = 0.5 ppm
Gator has a bad problem with algae in a 4 acre pond with an average
depth of 7.5 feet. He decides to use an algaecide containing 3 pounds
of active ingredient (3EC) per gallon. Being the great calibration
specialist he is, Gator reads the label which specifies a 0.5 ppm active
ingredient treatment rate. How many gallons of product does Gator
need to purchase?
Anything with ppm/ppb need pond volume
1 acre ft = 2.7 million pounds of water
2.7 lbs AI/acre ft = 1 ppm
.0027 lbs AI/acre ft = 1 ppb
Need 0.5 ppm in pond or 0.5ppm/acre ft
0.5 x 2.7 = 1.35 lbs AI/acre ft = 0.5 ppm
Volume = 4 x 7.5 = 30 acre ft x 1.35 lbs/acre/ft = 40.5 lbs
Gator has a bad problem with algae in a 4 acre pond with an average
depth of 7.5 feet. He decides to use an algaecide containing 3 pounds
of active ingredient (3EC) per gallon. Being the great calibration
specialist he is, Gator reads the label which specifies a 0.5 ppm active
ingredient treatment rate. How many gallons of product does Gator
need to purchase?
Anything with ppm/ppb need pond volume
1 acre ft = 2.7 million pounds of water
2.7 lbs AI/acre ft = 1 ppm
.0027 lbs AI/acre ft = 1 ppb
Need 0.5 ppm in pond or 0.5ppm/acre ft
0.5 x 2.7 = 1.35 lbs AI/acre ft = 0.5 ppm
Volume = 4 x 7.5 = 30 acre ft x 1.35 lbs/acre/ft = 40.5 lbs
Gallons of 3 lbs/gallon product
Gator has a bad problem with algae in a 4 acre pond with an average
depth of 7.5 feet. He decides to use an algaecide containing 3 pounds
of active ingredient (3EC) per gallon. Being the great calibration
specialist he is, Gator reads the label which specifies a 0.5 ppm active
ingredient treatment rate. How many gallons of product does Gator
need to purchase?
Anything with ppm/ppb need pond volume
1 acre ft = 2.7 million pounds of water
2.7 lbs AI/acre ft = 1 ppm
.0027 lbs AI/acre ft = 1 ppb
Need 0.5 ppm in pond or 0.5ppm/acre ft
0.5 x 2.7 = 1.35 lbs AI/acre ft = 0.5 ppm
Volume = 4 x 7.5 = 30 acre ft x 1.35 lbs/acre/ft = 40.5 lbs
Gallons of 3 lbs/gallon product
40.5
3
= 13.5 gallons
Gator has a bad problem with algae in a 4 acre pond with an average
depth of 7.5 feet. He decides to use an algaecide containing 3 pounds
of active ingredient (3EC) per gallon. Being the great calibration
specialist he is, Gator reads the label which specifies a 0.5 ppm active
ingredient treatment rate. How many gallons of product does Gator
need to purchase?
Gator is called to treat a section of canal with
a 5% pelleted herbicide at a rate of 25 pounds
of pellets per acre. If the canal section is 6
miles long and 40 feet wide, what is the total
amount of pellets to be applied?
RED HERRING HERE - READ THE QUESTION,
WHAT IS ASKED???
Gator is called to treat a section of canal with
a 5% pelleted herbicide at a rate of 25 pounds
of pellets per acre. If the canal section is 6
miles long and 40 feet wide, what is the total
amount of pellets to be applied?
RED HERRING HERE - READ THE QUESTION,
WHAT IS ASKED???
6 x 5,280 ft/mile = 31680 ft x 40 ft = 1,267,200ft²
Gator is called to treat a section of canal with
a 5% pelleted herbicide at a rate of 25 pounds
of pellets per acre. If the canal section is 6
miles long and 40 feet wide, what is the total
amount of pellets to be applied?
RED HERRING HERE - READ THE QUESTION,
WHAT IS ASKED???
6 x 5,280 ft/mile = 31680 ft x 40 ft = 1,267,200ft²
1,267,200ft²
= 29.09 acres @ 25 lbs/acre = 727 lbs
43,560
Gator is called to treat a section of canal with
a 5% pelleted herbicide at a rate of 25 pounds
of pellets per acre. If the canal section is 6
miles long and 40 feet wide, what is the total
amount of pellets to be applied?
Gator has another boat that has a centrifugal
spreader mounted on it. He wants to apply a
10% pelleted herbicide at a rate of 50 pounds
of pellets per acre. Gator tests his boat and
determines his boat will treat 0.3 acres per
minute. How many pounds must be
broadcast each minute?
RED HERRING HERE - READ THE QUESTION,
WHAT IS ASKED???
Gator has another boat that has a centrifugal
spreader mounted on it. He wants to apply a
10% pelleted herbicide at a rate of 50 pounds
of pellets per acre. Gator tests his boat and
determines his boat will treat 0.3 acres per
minute. How many pounds must be
broadcast each minute?
RED HERRING HERE - READ THE QUESTION,
WHAT IS ASKED???
50 lbs/acre x .3 = 15 lbs/min
Gator has another boat that has a centrifugal
spreader mounted on it. He wants to apply a
10% pelleted herbicide at a rate of 50 pounds
of pellets per acre. Gator tests his boat and
determines his boat will treat 0.3 acres per
minute. How many pounds must be
broadcast each minute?
Ole Gator wants to do some touch up on torpedograss around a
condo pond and only needs to mix up glyphosate and surfactant for
1/3 of an acre. He typically uses 3 quarts of glyphosate with 0.5%
surfactant per acre in a total mix of 60 gallons per acre. How much
glyphosate, diluent (water), and surfactant should he add to his 100
gallon tank to do the 1/3 acre treatment.
.33 of 3 quarts = 0.99 qts or 1.0 qt = glyphosate
Ole Gator wants to do some touch up on torpedograss around a
condo pond and only needs to mix up glyphosate and surfactant for
1/3 of an acre. He typically uses 3 quarts of glyphosate with 0.5%
surfactant per acre in a total mix of 60 gallons per acre. How much
glyphosate, diluent (water), and surfactant should he add to his 100
gallon tank to do the 1/3 acre treatment.
.33 of 3 quarts = 0.99 qts or 1.0 qt = glyphosate
.33 of 60 gallons = 19.8 gallons water
Ole Gator wants to do some touch up on torpedograss around a
condo pond and only needs to mix up glyphosate and surfactant for
1/3 of an acre. He typically uses 3 quarts of glyphosate with 0.5%
surfactant per acre in a total mix of 60 gallons per acre. How much
glyphosate, diluent (water), and surfactant should he add to his 100
gallon tank to do the 1/3 acre treatment.
.33 of 3 quarts = 0.99 qts or 1.0 qt = glyphosate
.33 of 60 gallons = 19.8 gallons water
.5% Surfactant in 20 gallons?
Ole Gator wants to do some touch up on torpedograss around a
condo pond and only needs to mix up glyphosate and surfactant for
1/3 of an acre. He typically uses 3 quarts of glyphosate with 0.5%
surfactant per acre in a total mix of 60 gallons per acre. How much
glyphosate, diluent (water), and surfactant should he add to his 100
gallon tank to do the 1/3 acre treatment.
.33 of 3 quarts = 0.99 qts or 1.0 qt = glyphosate
.33 of 60 gallons = 19.8 gallons water
.5% Surfactant in 20 gallons?
.005 x 20 = 0.1 gallons x 128 oz/gallons = 12.8 oz
Ole Gator wants to do some touch up on torpedograss around a
condo pond and only needs to mix up glyphosate and surfactant for
1/3 of an acre. He typically uses 3 quarts of glyphosate with 0.5%
surfactant per acre in a total mix of 60 gallons per acre. How much
glyphosate, diluent (water), and surfactant should he add to his 100
gallon tank to do the 1/3 acre treatment.
Gator wants to do a bit of backpack work
on some cattails with his 3 gallon
backpack sprayer. To make a 3 gallon mix
of 2% glyphosate and 0.25% surfactant,
how much herbicide and how much
surfactant does he had to the tank?
.002 x 3 gallons
Opps!!!
Gator wants to do a bit of backpack work
on some cattails with his 3 gallon
backpack sprayer. To make a 3 gallon mix
of 2% glyphosate and 0.25% surfactant,
how much herbicide and how much
surfactant does he had to the tank?
.002 x 3 gallons
Opps!!!
.02 x 3 gallons = 0.06 gal. x 128 oz/gal
= 7.68 ounces glyphosate
Gator wants to do a bit of backpack work
on some cattails with his 3 gallon
backpack sprayer. To make a 3 gallon mix
of 2% glyphosate and 0.25% surfactant,
how much herbicide and how much
surfactant does he had to the tank?
.002 x 3 gallons
Opps!!!
.02 x 3 gallons = 0.06 gal. x 128 oz/gal
= 7.68 ounces glyphosate
.0025 x 3 gallons = .0075 gal x 128 oz/gal
= 0.96 oz surfactant
Gator wants to do a bit of backpack work
on some cattails with his 3 gallon
backpack sprayer. To make a 3 gallon mix
of 2% glyphosate and 0.25% surfactant,
how much herbicide and how much
surfactant does he had to the tank?
How do you determine the output in
gallons per minute of a boom sprayer and
a handgun? How do you determine the
output of a granular spreader in pounds of
granules per minute?
Boom sprayer catch test
REMEMBER:
- Gallons/min output
- Swath width
- Speed
“are all you need!”
How do you determine the output in
gallons per minute of a boom sprayer and
a handgun? How do you determine the
output of a granular spreader in pounds of
granules per minute?
Handgun catch test
REMEMBER:
- Gallons/min output
- Swath width
- Speed
“are all you need!”
How do you determine the output in
gallons per minute of a boom sprayer and
a handgun? How do you determine the
output of a granular spreader in pounds of
granules per minute?
Granular Spreader catch test
REMEMBER:
- Gallons/min output
- Swath width
- Speed
“are all you need!”
How do you determine the output in
gallons per minute of a boom sprayer and
a handgun? How do you determine the
output of a granular spreader in pounds of
granules per minute?
CALIBRATION
DR. BILL HALLER
ANY QUESTION ???