10.00 mL of 2.00 x 10-3 M Fe(NO3)3 (Fe3+) + 0.200 M HNO3 (H+) 4.00 mL of 2.00 x 10-3 M HSCN Total Volume when reaction starts (i.e., when all reagents are mixed) is 20,00 mL. 6.00 mL H2O [Fe3+]I : 10.00 mL • 2.00 x 10-3 M = 20.00 mL • C2 ⇒ C2 = 1.00 x 10-3 M C2 = initial reactant concentration [HSCN]I : 4.00 mL • 2.00 x 10-3 M = 20.00 mL • C2 ⇒ C2 = 4.00 x 10-4 M When reactants are mixed their concentration is diluted. [H+]I : 10.00 mL • 0.200 M = 20.00 mL • C2 ⇒ C2 = 0.100 M 1. Fe3+ + HSCN ⇌ FeSCN2+ + H+ I (M) 1.00 x 10-3 4.00 x 10-4 0 0.100 C (M) - 0.53 x 10-4 - 0.53 x 10-4 + 0.53x 10-4 + 0.53 x 10-4 E (M) 9.47 x 10-4 3.47 x 10-4 0.53 x 10-4 0.100 Common information used for Questions 1 and 2 Solution to Exercises for Experiment 19 The change in concentration (x) [FeSCN 2 + ] [H + ] [0.53 x 10 −4 ] [0.100] Kc = = = 16.1 [Fe3+ ] [HSCN ] [9.47 x 10 −4 ] [3.47 x 10 −4 ] 2. I (M) Fe3+ 1.00 x 10-3 C (M) - 0.265 x 10-4 E (M) 9.74 x 10-4 Kc = + 2 HSCN 4.00 x 10-4 - 2(0.265 x 10-4) 3.47x 10-4 ⇌ Fe(SCN)2+ 0 + 0.265 x 10-4 0.265 x 10-4 [Fe(SCN )+2 ] [H + ]2 [0.265 x 10 −4 ] [0.100]2 = = 2.26 x 10 3 3+ 2 −4 −4 2 [Fe ] [HSCN ] [9.74 x 10 ] [3.47 x 10 ] + 2 H+ 0.100 + 2(0.265 x 10-4) 0.100 The change in concentration (x)
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