09_ch07a_pre-calculas12_wncp_solution.qxd 5/22/12 5:31 PM Home Page 17 Quit Lesson 7.3 Exercises, pages 611–618 A 3. Write each expression in terms of a single trigonometric function. cos u sin2u a) b) 2 sin u cos u ⴝ cot U ©P DO NOT COPY. ⴝ tan2U 7.3 Reciprocal and Quotient Identities—Solutions 17 09_ch07a_pre-calculas12_wncp_solution.qxd 5/22/12 5:31 PM Page 18 Home c) sin2u sec u cos u csc u d) 1 1 b b (cos U) a cos U sin U ⴝ (sin2U) a Quit sin2u tan2u ⴝ ⴝ sin U sin2U sin2U cos2U ⴝ cos2U 4. Determine the non-permissible values of u. a) sec u tan U ⴝ non-permissible values occur when cos U ⴝ 0, values occur when cos U ⴝ 0, so U ⴝ ⴙ k, k ç ⺪ so U ⴝ c) b) tan u 1 sec U ⴝ , so cos U csc U ⴝ d) 1 , so sin U sec u sin u sec U ⴝ non-permissible values occur when sin U ⴝ 0, so U ⴝ k, k ç ⺪; or when cos U ⴝ 0, so U ⴝ 2 ⴙ k, k ç ⺪ 2 csc u cos u ⴙ k, k ç ⺪ 2 sin U , so non-permissible cos U 1 , so non-permissible cos U values occur when cos U ⴝ 0, so U ⴝ ⴙ k, k ç ⺪; or when 2 sin U ⴝ 0, so U ⴝ k, k ç ⺪ 5. Verify each identity for the given value of u. a) tan u csc u sec u ⫽ sec2u; u ⫽ 150° Substitute: U ⴝ 150° L.S. ⴝ tan U csc U sec U ⴝ (tan 150°)(csc 150°)(sec 150°) ⴝ (ⴚtan 30°) a 1 1 ba b sin 150° cos 150° R.S. ⴝ sec2U ⴝ sec2(150°) ⴝ 1 cos (150°) 2 2 ⴚ1 b cos 30° ⴚ1 1 ⴝ (ⴚtan 30°) a ba b sin 30° cos 30° ⴝ a ⴚ1 ⴚ2 ⴝ a√ b (2) a√ b 3 3 4 ⴝ 3 ⴝ a√ b ⴚ2 3 ⴝ 2 4 3 The left side is equal to the right side, so U ⴝ 150° is verified. 18 7.3 Reciprocal and Quotient Identities—Solutions DO NOT COPY. ©P 09_ch07a_pre-calculas12_wncp_solution.qxd 5/22/12 5:31 PM Page 19 Home b) Quit 4 tan u csc2u ⫽ cot u; u ⫽ 3 sec2u Substitute: U ⴝ L.S. ⴝ ⴝ ⴝ 4 3 tan U csc2U sec2U R.S. ⴝ cot U ⴝ cot 4 2 4 atan b acsc a bb 3 3 sec2 a atan tan 3 1 ⴝ√ 2 b aⴚcos b 3 3 aⴚsin 1 ⴝ 4 b 3 4 3 3 2 b 3 √ 1 2 ( 3)aⴚ b 2 ⴝ √ 2 3 b aⴚ 2 1 3 ⴝ√ The left side is equal to the right side, so U ⴝ 4 is verified. 3 B 6. Prove each identity in question 5. a) tan U csc U sec U ⴝ sec2U L.S. ⴝ tan U csc U sec U 1 sin U 1 ⴝ a ba ba b cos U sin U cos U ⴝ 1 cos2U ⴝ sec2U ⴝ R.S. The left side is equal to the right side, so the identity is proved. b) tan U csc2U ⴝ cot U sec2U L.S. ⴝ ⴝ ⴝ ⴝ tan U csc2U sec2U a 1 2 sin U b ba cos U sin U a 1 2 b cos U 1 (sin U)(cos U) 1 2 b a cos U cos U sin U ⴝ cot U ⴝ R.S. The left side is equal to the right side, so the identity is proved. ©P DO NOT COPY. 7.3 Reciprocal and Quotient Identities—Solutions 19 09_ch07a_pre-calculas12_wncp_solution.qxd 5/22/12 5:31 PM Page 20 Home Quit 7. For each identity: i) Verify the identity using graphing technology. ii) Prove the identity. a) 1 ⫺ sin u ⫽ (sin u)(csc u ⫺ 1) b) ⫺cot u ⫽ 1 1ⴚ tan U ⴚ1 i) Graph: y ⴝ and y ⴝ tan U 1 ⴚ tan U i) Graph: y ⴝ 1 ⴚ sin U and y ⴝ sin U a 1 ⴚ 1b sin U The graphs coincide, so the identity is verified. The graphs coincide, so the identity is verified. 1 ⴚ cot U 1 ⴚ tan U 1 1ⴚ tan U ⴝ 1 ⴚ tan U tan U ⴚ 1 ⴝ (tan U)(1 ⴚ tan U) ⴚ1 ⴝ tan U ii) R.S. ⴝ ii) R.S. ⴝ (sin U)(csc U ⴚ 1) ⴝ (sin U) a 1 - cot u 1 - tan u 1 ⴚ 1b sin U ⴝ 1 ⴚ sin U ⴝ L.S. The left side is equal to the right side, so the identity is proved. ⴝ ⴚcot U ⴝ L.S. The left side is equal to the right side, so the identity is proved. 8. For each identity: i) Verify the identity for u ⫽ 45°. ii) Prove the identity. a) cot u ⫺ csc u ⫽ 0 cos u i) Substitute: U ⴝ 45° cot U L.S. ⴝ ⴚ csc U cos U cot 45° ⴝ ⴚ csc 45° cos 45° √ 1 ⴝ ⴚ 2 1 √ 2 √ √ ⴝ 2ⴚ 2 ⴝ0 ⴝ R.S. The left side is equal to the right side, so U ⴝ 45° is verified. b) tan2u cos2u ⫹ sin2u ⫽ 2 csc2u i) Substitute: U ⴝ 45° L.S. ⴝ tan2U cos2U ⴙ sin2U ⴝ (tan 45°)2(cos 45°)2 ⴙ (sin 45°)2 ⴝ (1) a b ⴙ a b 1 2 1 2 ⴝ1 2 csc2U 2 ⴝ (csc 45°)2 R.S. ⴝ 2 2)2 ⴝ √ ( ⴝ 2 2 ⴝ1 The left side is equal to the right side, so U ⴝ 45° is verified. 20 7.3 Reciprocal and Quotient Identities—Solutions DO NOT COPY. ©P 09_ch07a_pre-calculas12_wncp_solution.qxd 5/22/12 5:31 PM Page 21 Home cot U ⴚ csc U cos U cos U sin U 1 ⴝ ⴚ cos U sin U 1 1 ⴝ ⴚ sin U sin U ii) L.S. ⴝ tan2U cos2U ⴙ sin2U ii) L.S. ⴝ ⴝa sin2U b (cos2U) ⴙ sin2U cos2U ⴝ sin2U ⴙ sin2U ⴝ 2 sin2U ⴝ ⴝ0 ⴝ R.S. The left side is equal to the right side, so the identity is proved. 9. For each identity: Quit 2 csc2U ⴝ R.S. The left side is equal to the right side, so the identity is proved. 7 i) Verify the identity for u ⫽ 6 . ii) Prove the identity. a) csc u ⫽ csc u - 1 1 - sin u 7 i) Substitute: U ⴝ 6 L.S. ⴝ csc U 7 6 ⴝ ⴚcsc 6 ⴝ csc ⴝ ⴚ2 csc U ⴚ 1 1 ⴚ sin U 7 csc ⴚ1 6 ⴝ 7 1 ⴚ sin 6 ⴚ2 ⴚ 1 R.S. ⴝ ⴝ 1 1 ⴚ aⴚ b 2 ⴝ ⴚ2 The left side is equal to the 7 right side, so U ⴝ is 6 verified. csc U ⴚ 1 1 ⴚ sin U 1 ⴚ1 sin U ⴝ 1 ⴚ sin U 1 ⴚ sin U ⴝ (sin U)(1 ⴚ sin U) 1 ⴝ sin U ii) R.S. ⴝ ⴝ csc U ⴝ L.S. The left side is equal to the right side, so the identity is proved. ©P DO NOT COPY. b) cos u - cot u ⫽ ⫺cot u 1 - sin u 7 6 cos U ⴚ cot U L.S. ⴝ 1 ⴚ sin U 7 7 cos ⴚ cot 6 6 ⴝ 7 1 ⴚ sin 6 √ √ 3 ⴚ ⴚ 3 2 i) Substitute: U ⴝ ⴝ 1 ⴚ aⴚ b √ ⴝⴚ 3 R.S. ⴝ ⴚcot U 1 2 7 ⴝ ⴚcot 6 √ ⴝⴚ 3 The left side is equal to the 7 right side, so U ⴝ is 6 verified. ii) L.S. ⴝ cos U ⴚ cot U 1 ⴚ sin U cos U sin U ⴝ 1 ⴚ sin U (cos U)(sin U) ⴚ cos U cos U ⴚ ⴝ ⴝ (1 ⴚ sin U)(sin U) (cos U)(sin U ⴚ 1) (1 ⴚ sin U)(sin U) ⴚ cos U ⴝ sin U ⴝ ⴚcot U ⴝ R.S. The left side is equal to the right side, so the identity is proved. 7.3 Reciprocal and Quotient Identities—Solutions 21 09_ch07a_pre-calculas12_wncp_solution.qxd 5/22/12 5:31 PM Page 22 Home Quit 10. Use algebra to solve each equation over the domain 0 ≤ x < 2. Give the roots to the nearest hundredth where necessary. √ a) tan x ⫽ cot x b) cos x ⫹ 3 sin x ⫽ 0 Assume tan x ⴝ 0, then divide by tan x. cot x tan x ⴝ tan x tan x 1 1ⴝ tan2x 1 3 tan x ⴝ ⴚ√ tan2x ⴝ 1 tan x ⴝ — 1 5 3 x ⴝ ,x ⴝ ,x ⴝ , or 4 4 4 7 xⴝ 4 For tan x ⴝ 0, x ⴝ 0 or x ⴝ Verify by substitution that neither value of x is a root of the given equation. Verify the roots by substitution. c) 2 cos x ⫽ 7 ⫺ 3 sec x 3 2 cos x ⴝ 7 ⴚ cos x Multiply by cos x, then collect terms on one side. 2 cos2x ⴚ 7 cos x ⴙ 3 ⴝ 0 (2 cos x ⴚ 1)(cos x ⴚ 3) ⴝ 0 Either 2 cos x ⴚ 1 ⴝ 0 cos x ⴝ xⴝ Assume cos x ⴝ 0, then divide by cos x. √ sin x cos x cos x ⴙ 3 cos x ⴝ 0 √ 1 ⴙ 3 tan x ⴝ 0 1 2 5 or x ⴝ 3 3 Or cos x ⴚ 3 ⴝ 0 cos x ⴝ 3 This equation has no solution. Verify the roots by substitution. xⴝ 11 5 or x ⴝ 6 6 For cos x ⴝ 0, x ⴝ 3 or x ⴝ 2 2 Verify by substitution that neither value of x is a root of the given equation. Verify the roots by substitution. d) sin2x ⫽ sin x cos x sin2x ⴚ sin x cos x ⴝ 0 (sin x)(sin x ⴚ cos x) ⴝ 0 Either sin x ⴝ 0 x ⴝ 0 or x ⴝ Or sin x ⴚ cos x ⴝ 0 sin x ⴝ cos x Assume cos x ⴝ 0, then divide by cos x. tan x ⴝ 1 xⴝ 5 or x ⴝ 4 4 For cos x ⴝ 0, x ⴝ 3 or x ⴝ 2 2 Verify by substitution that neither value of x is a root of the given equation. Verify the roots by substitution. 11. Identify any errors in this proof, then write a correct algebraic proof. sin u 1 Correct proof: = To prove: 1 - sin u csc u - 1 1 sin u R.S. ⴝ L.S. ⫽ csc U ⴚ 1 1 - sin u 1 sin u sin u ⴝ ⫽ 1 1 sin u ⴚ1 ⫽ sin u ⫺ 1 1 - 1 csc u 1 ⫽ csc u - 1 ⫽ ⫽ R.S. 22 sin U 1 ⴝ 1 ⴚ sin U sin U sin U ⴝ 1 ⴚ sin U ⴝ L.S. From the 1st line of the proof to the 2nd line, sin U sin U sin U cannot be written as . ⴚ 1 1 ⴚ sin U sin U From the 4th line of the proof to the 5th line, 1 1 . ⴚ 1 cannot be written as csc U csc U ⴚ 1 7.3 Reciprocal and Quotient Identities—Solutions DO NOT COPY. ©P 09_ch07a_pre-calculas12_wncp_solution.qxd 5/22/12 5:31 PM Page 23 Home Quit 12. Identify which equation below is an identity. Justify your answer. Prove the identity. Solve the other equation over the domain ⫺ ≤ x ≤ . Give the roots to the nearest hundredth. a) 2 sin2x + 1 ⫽ 2 csc2x ⫺ 1 sin x I graphed each side of the equation. The graphs do not coincide, so this is an equation. From the graphs, the roots are approximately: x ⴝ 0.81 and x ⴝ 2.33 b) 1 + csc2x sin2x + 1 ⫽ csc x sin x I graphed each side of the equation. The graphs appear to coincide, so this is probably the identity. 1 ⴙ csc2x csc x 1 1ⴙ sin2x ⴝ 1 sin x R.S. ⴝ Multiply numerator and denominator by sin2x. R.S. ⴝ sin2x ⴙ 1 sin x ⴝ L.S. The left side is equal to the right side, so the identity is proved. C 13. Here are two identities that involve the cotangent ratio: 1 cos u cot u ⫽ and cot u ⫽ tan u sin u a) Show how you can derive one identity from the other. cot U ⴝ 1 tan U 1 sin U cos U cos U cot U ⴝ sin U cot U ⴝ ©P DO NOT COPY. Write tan U ⴝ sin U . cos U Multiply numerator and denominator by cos U. 7.3 Reciprocal and Quotient Identities—Solutions 23 09_ch07a_pre-calculas12_wncp_solution.qxd 5/22/12 5:31 PM Page 24 Home Quit b) Determine the non-permissible values of u for each identity. Explain why these values are different. How could you illustrate this using graphing technology? 1 tan U sin U Since tan U ⴝ , then cos U For cot U ⴝ sin U ⴝ 0 and For cot U ⴝ sin U ⴝ 0 cos U ⴝ 0 So, U ⴝ k, k ç ⺪ and U ⴝ cos U sin U So, U ⴝ k, k ç ⺪ ⴙ k, k ç ⺪ 2 The values are different because there are two restrictions for and only one restriction for cos U . sin U 1 tan U 1 , and set the TABLE for intervals of , it shows tan U 2 cos U ERROR for all values of X in the table. When I graph y ⴝ , with the sin U When I graph y ⴝ same TABLE settings, it shows ERROR only for X ⴝ k, k ç ⺪. 24 7.3 Reciprocal and Quotient Identities—Solutions DO NOT COPY. ©P
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