On the Perimeter of a Triangle in a Minkowski Plane Author(s): H. Maehara and T. Zamfirescu Source: The American Mathematical Monthly, Vol. 112, No. 6 (Jun. - Jul., 2005), pp. 521-522 Published by: Mathematical Association of America Stable URL: http://www.jstor.org/stable/30037523 Accessed: 25/08/2009 09:03 Your use of the JSTOR archive indicates your acceptance of JSTOR's Terms and Conditions of Use, available at http://www.jstor.org/page/info/about/policies/terms.jsp. JSTOR's Terms and Conditions of Use provides, in part, that unless you have obtained prior permission, you may not download an entire issue of a journal or multiple copies of articles, and you may use content in the JSTOR archive only for your personal, non-commercial use. Please contact the publisher regarding any further use of this work. Publisher contact information may be obtained at http://www.jstor.org/action/showPublisher?publisherCode=maa. 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MathematicsDepartment,Northwestern University,Evanston, IL 60208-2730 [email protected] On the Perimeter of a Triangle in a Minkowski Plane H. Maehara and T. Zamfirescu A Minkowskiplane is a planeendowedwith a normthatis not necessarilyEuclidean. The Minkowskilengthof a curvein a Minkowskiplaneis definedin a manneranalogous to the way it is definedin the Euclideancase. A circleof radiusr in a Minkowski plane with norm I|| IIis the locus of points X satisfying IX - P II= r for a fixed "center"P. It is a convex curvethatis symmetricwith respectto its center.Golab's theoremshowsthattheMinkowskilengthof a circleof unitradiuslies between6 and8 (see [2]). Let L denotethe Minkowskilength.We establishthe following: Theorem 1. Let ABC be a triangle in a Minkowskiplane, and suppose that one is the minimum radius of a circle that encloses the triangle ABC. Then 4 < L(ABC) < 6. Since thereis an arbitrarilythin trianglewith two sides close to a diameterof the circle,the lowerbound4 cannotbe improvedin any Minkowskiplane.Forthe case of the Euclideannormit is not difficultto see thatthe upperbound6 can be reducedto 3/3 [1]. However,in the max-normIl(x,y)IIo = max{Ixl,lyl} any threecomers of the unit circle (whichis a Euclideansquare)form a trianglewith perimeter6. Hence the upperboundof the theoremcannotbe improvedin general. Proof Let r be a circle circumscribedaboutABC in the sense that it has smallest radiusamongall circlesthatcontainA, B, andC in theirconvexhulls.It is easily seen thateitherthe centerof the circle is inside the triangleor on one of its sides, or there exists a congruentcircumscribedcirclewith this property.So we may assumethatthe centerof F is the origin O andlies insideABCor on one of its sides. The circle r is supposed to have radius 1. Since I||A- BII < 2, IIB - CII < 2, and |IC - AI| < 2, we have L(ABC) < 6. We have to show that L(ABC) _ 4. If I||A- BII = 2, then ||A - BII+ II|B- C|| + I||C- Al|| A - BII+ IIB- Al = 4. Hencewe considerthe case that ||A - BII,IIB - CII,and ||C - All areall less than2. Notice thatin this case O lies insideABC,while A, B, andC all lie on r. Let D, E, F, G, H, and I be points on the sides of ABC such that ADOI, BFOE, andCHOGareparallelograms (see Figure1). Then II||A - D|| + ||A - = IIA- DII+ ||D|| ||AII= 1, ||B - E| + ||B - F|| = |B - E| + \\E\\ _ \B\ = 1, ||C - G|| + ||C - H|| = ||C - G|| + ||G|| > ||C|| = 1. June-July 2005] NOTES 521 B F G C Figure 1. To provethatL(ABC)> 4, it is enoughto showthat ||D-E||+|IIF-GII + IIH-I > 1. Amongthe similartrianglesDEO, OFG, andIOH, we may supposethatDEO is the biggestandIOHthe smallest.Then ID - Eli IIF|| _ I|I. Let J be the pointsuch thatOFGJis a parallelogram,and let K be the intersectionof GJ andAC. Then the triangleKGCis a translateof IOH,and II||D- E|| IIF|| II= J - | GII> IIJ - KII, lIF - Gll = IJII, IIH- III|| = ||IIC - K||II. Therefore, II|D - EI||+ IIF- GII+ IIH- I II> IIJ- KII+ IIJ||||II + IIC- KII > IICII=1. U Remark. The lowerboundin the theoremis valid for any closed curveinsteadof a triangle.Moreprecisely,let i2be a simpleclosed curvein a Minkowskiplane,andlet one be the smallestradiusof a circlethatencloses 2. ThenL(2) > 4. ACKNOWLEDGMENT. The paper was startedwhile the second authorvisited Ryukyu University in 2002, where he was supportedby the JSPS InvitationFellowship Programfor Research in Japan. REFERENCES 1. H. Maehara,Onthetotaledge-lengthof a tetrahedron, thisMONTHLY 108 (2001)237-243. 2. A. C. Thompson, MinkowskiGeometry,CambridgeUniversity Press, New York 1996. College of Education, RyukyuUniversity,Nishihara, Okinawa, 903-0213, Japan [email protected] FachbereichMathematik,Universitit Dortmund,44221 Dortmund,Germany [email protected] 522 © THE MATHEMATICAL ASSOCIATION OF AMERICA [Monthly 112
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