In[7]:=
Clear@"Global`*"D; $Line = 0;
Let s be the sum of the three consecutive even numbers where n is any integer.
In[1]:=
Out[1]=
s = H2 n - 2L + H 2 nL + H 2 n + 2L
6n
Solve the following for n .
s
In[2]:=
SolveBs == 44 +
, nF
3
Out[2]=
88n ® 11<<
Use the above result, a replacment rule, to calculate the answer numbers. /. is a replacement operator.
In[3]:=
Out[3]=
8H2 n - 2L, H 2 nL, H 2 n + 2L< . n ® 11
820, 22, 24<
Form the product of the first and last numbers.
In[4]:=
Out[4]=
20 * 24
480