East Campus, CB 117 361-698-1579 Math Learning Center West Campus, HS1 203 361-698-1860 EXPONENT RULES Rule Description 1 as an exponent ππ = ππ1 Product Rule ππππ β ππππ = ππππ+ππ 0 as an exponent Quotient Rule Power Rule Raising a product to a power Raising a quotient to a power Negative exponent ππ0 = 1 Any nonzero number to the power of zero equals 1. ππππ = ππππβππ ππ ππ To divide with the same base, subtract the exponents. (numerator) β (denominator) (ππππ )ππ = ππππβππ (ππππ)ππ = ππππ ππππ ππ ππ ππππ οΏ½ οΏ½ = ππ ππ ππ ππβππ = 1 ππππ ππβππ ππππ = ππβππ ππππ ππ βππ ππ ππ οΏ½ οΏ½ =οΏ½ οΏ½ ππ ππ Scientific Notation Anything βwithoutβ a power is raised to the power of 1. ππ ππ × 10 (π΄π΄ × 10ππ )(π΅π΅ × 10ππ ) = π΄π΄π΄π΄ × 10ππ+ππ (π΄π΄ × 10ππ ) ÷ (π΅π΅ × 10ππ ) = π΄π΄ ÷ π΅π΅ × 10ππβππ To multiply with the same bases, add the exponents. To raise a power to a power, multiply the exponents and leave the base unchanged. To raise a product to a power, raise each factor to that power. To raise a quotient to a power, raise each numerator and denominator to the power. To turn a negative exponent into a positive exponent, move the base and exponent to the denominator (or numerator), depending on where it is. In scientific notation there is one nonzero digit before the decimal point. πΈπΈπΈπΈ. 2 × 10β5 ππππ 9.0713 × 106 When multiplying or dividing, be sure the final answer is in scientific notation. East Campus, CB 117 361-698-1579 Math Learning Center West Campus, HS1 203 361-698-1860 Rule Example 1 Example 2 1 as an exponent 5 = 51 0.3 = 0.31 32 β 35 = 32+5 = 37 = 2,187 π¦π¦ 4 β π¦π¦ 5 = π¦π¦ 9 0 as an exponent Product Rule Quotient Rule Power Rule Raising a product to a power Raising a quotient to a power Negative exponent Scientific Notation Scientific Notation Multiplication Scientific Notation Division (β2)0 = 1 65 62 5β2 =6 890 = 1 π₯π₯ 6 = π₯π₯ 6β8 = π₯π₯ β2 8 π₯π₯ 3 = 6 = 216 (π§π§ 4 )3 = π§π§ 4β3 = π§π§12 (42)5 = 42β5 = 410 = 1,048,576 (ππβ)6 = ππ6 β6 (5π₯π₯)3 = 53 π₯π₯ 3 = 125π₯π₯ 3 7 1 2 12 1 οΏ½ οΏ½ = 2= 3 3 9 β2 5 (π₯π₯ 3 )7 π₯π₯ 21 π₯π₯ 3 = 7 οΏ½ οΏ½ = π¦π¦ π¦π¦ 7 π¦π¦ π₯π₯ 4 π₯π₯ 4 π¦π¦ 8 = = π₯π₯ 4 π¦π¦ 8 β8 π¦π¦ 1 1 1 = 2= 5 25 . 000014 = 1.4 × 10β5 3,879,000 = 3.879 × 106 (15 × 108 ) ÷ (30 × 105 ) = (15 ÷ 30) × 108β5 = .5 × 103 = 5 × 102 (107.1 × 10β6 ) ÷ (1.05 × 10β2 ) = (107.1 ÷ 1.05) × 10β6β(β2) = 102 × 10β4 = 1.02 × 10β2 Subtracted one from the exponent, since you move the decimal one spot to the right Added one to the exponent, since you move the decimal one spot to the left (β8 × 104 )(4 × 105 ) = (β8 β 4) × 104+5 = β32 × 109 = β3.2 × 1010 Subtracted one from the exponent, since you move the decimal one spot to the right (. 7 × 10β3 )(. 2 × 10β4 ) = (.7 β .2) × 10β3+(β4) = .14 × 10β7 = 1.4 × 10β8 Added two to the exponent, since you move the decimal two spots to the left
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