Solutions Name _______________________________ Block ____ Date __________ Algebra: R.2 Functions Bell Work: What is the domain and range for each function? y a. b. c. y y (3,5) 5 x 3 Domain: π β€ π β€ π Range: π β€ π β€ π (5, 3) x x Domain: π β β Range: π β€ π Domain: π β€ π Range: π β€ π π(π) 1. Use functions f, g and h to answer the following questions. 14 π y 12 10 8 Multiply by 3 and then subtract 2 6 4 2 π β12 0 1 2 3 4 β10 β8 β6 β4 π(π) 3 6 12 24 48 96 If π(π₯) = 48, then what is π₯? h. π(π) = ππ β π c. Classify f i. d. π³π³π³π³π³π³ Write an equation in vertex form for h j. e. π(π) = (π + π)π β π What is β(β8)? k. Classify h Classify g l. πΈπΈπΈπΈπΈπΈπΈπΈπΈ f. π₯=π = ππ π¬ππππππππππ 6 β6 Write an equation for f b. 4 β4 g. 3(β4) β 2 = βππ 2 β2 What is π(β4)? a. β2 5 x If β(π₯) = β2, then what is π₯? π₯ = βπ What is π(3)? π₯ = βπ = ππ If π (π₯) = 16, then what is π₯? 3π₯ β 2 = 16 Write an equation for g π(π) = π(π)π 3π₯ = 18 π=π 2. Aura thinks the solution to the systems of equations below is (β2, 4) while Edison thinks the solution is (2, β2). Teresito thinks they are both wrong. Who is correct? Solve the system to Justify your answer. 3(β2) + 2(4) = 2ο 5(β2) β 12 = 4 ο 3π₯ + 2π¦ = 2 5π₯ β 12 = π¦ Edison is Correct 3(2) + 2(β2) = 2ο 5(2) β 12 = β2 ο 3π₯ + 2(5π₯ β 12) = 2 3π₯ + 10π₯ β 24 = 2 13π₯ = 26 π=π 3. Graph the function β(π₯ ) = ββ3 β π₯ . Use inequalities to describe the domain and range. 5(2) β 12 = π¦ π = βπ y 8 6 4 Domain: π β€ π Range: π β€ π 2 x β8 β6 β4 β2 2 4 6 8 β2 β4 β6 β8 4. If π(π₯ ) = β5 π₯+2 and g(x) = (x β 2)3, find each output value below (if possible). If it is not possible, explain why not. a. f(β2) Not Possible, you canβt divide by 0 b. g(β1) = βππ c. g(4) = π d. f(β7) + g(1) = 1 + (β1) = π e. f(3) β g(2) = β1 + 0 = βπ 5. Write and solve a system of equations to solve the following problem. Be sure to define your D = the number of dimes variables and answer the question at the end. Q = the number of quarters Jessica has 147 coins that are all dimes and quarters. The number of quarters is 6 fewer than twice the number of dimes. What is the value of her coins? π« + πΈ = πππ πΈ = ππ β π π· + 2π· β 6 = 147 3π· = 153 π· = 51 π = 2(51) β 6 π = 96 Value = 51(. 10) + 96(.25) = $ππ. ππ PARCC Prep 6. 2 7. y 8 x 2 0 y 0 -3 6 4 2 x β8 β6 β4 2 β2 4 6 8 β2 β4 β6 β8 8. π(0) = 4(2)0 = 4 βπ π(5) = 4(2)5 = 128 Ξπ 124 ππππππππ = = 24.8 ππππππ 5 Ξπ‘ 9. Use a graph in calculator to solve the system of equations. Write solution(s) in (x, y) form. Make a sketch of the graph with the solutions labeled. (hint: enlarge the window!) y = x2 β x + 12 y = 2x2 + 3x + 7 y (β5, 42) (1, 12) x 10. Write an equation for f(x). π(π) = β(π β π)π + π 11. Solve each equation or inequality below, if possible by using graphs. a. β(x β 3)(x + 1) = 4 y 1 π=π 12. b. |π₯ β 3| > 4 c. (x β 5)3 = 8 y x β1 y x x 7 7 π < βπ or π > π π=π Graph the parent function π¦ = |π₯| (dotted) and then graph π(π) = |π β π| β π (solid) by transforming the parent. Label the vertex, intercepts and roots on the graph of f. y 8 6 4 2 x β8 β6 β4 β2 2 4 6 8 β2 (3, β1) Vertex Roots(x-intercepts): π = π, π = π β4 π intercept: π = π β6 β8
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