CUMMULATIVE
CUM
EXAM 1 CHEMISTRY
MARK
ARKING SCHEME AND VALUE POINTS
QUE
S
1
2
3
4
5
6
7
8
2-chlorobutane
C6H5NH2< C6 H5 NH – CH3< C6 H5 – CH2 – NH2
It has free CHO group.
O3/h2O-Zn dust
Boric acid
p-nitrophenol< m-nitrophenol< Phenol<
Phe
p-cresol
reson- presence of EWG increases
es the
th acid strength thus pka value is low but ERG decr
decreases it
3-methyl-pent-2-ene-1,2-diol
N,N-dimethylbenzenamine
Biodegradable
Non-biodegradable
Can be easily decomposed
Slow degradation occurs
Unbranched chain
Hydrocarbon chain is highly branche
nched
9
1
1
1
1
1
1
1
1
1
1
1
1
1
10
11
12
a) Peptide linkage is an amide
ide formed between –COOH group and –NH2 group
p ( -CO-NH- )
b) When a protein in its native
tive form, is subjected to change in temperature orr cha
change in pH,
protein loses its biological
al activity.
ac
This is called denaturation of protein.
Benzene ---- C6H5-SO3H + NaOH ---------- C6H5SO3Na+ Naoh---C6H5ONa +dilHCl---- phen
henol
Soaps containing sodium salts are
re formed
fo
by heating fat(ester of fatty acid) with aqNa
qNaOH
solution.
ions Thus form insoluble scum and separates out so b
becomes
Hard water contains Ca and Mg ions.
useless
1
1
1+1+
1
1
1
1
13
(i)
C6H5OH + Zn(dust)
(ii)
CH3CH2 CH2C(CH3)=CH2
(iii) CH3CH2OH CrO3 CH3CHO
14
15
16
C6H6
CH3COCl , Anhy AlCl3
H2O/conc H2SO4
CH3MgBr/ H2O
A) Presence of R grp showing
ng resonance
re
Resonating structures
B) Reaction forming propan-2
2-ol
(a) CH3 COOC2H5 H2O / H+ CH3COOH
CO
+ C2H5OH
(X)
(Y)
(Z)
CH3 COOH
Na2CO3
CH3COONa
COO
Sodalime
(Y)
(A)
Heat
CH3COOH
LiAlH4
CH3CH2OH
(Y)
a) Unstable at rt(stable at 0-5
5 C)
C
C6H5COCH3
CH3CH2 CH2C(OH)(CH3)-CH3
(CH3)2 CH-OH
1
1
1
1
1
1
1
CH4
(B)
1
1
1
b) N is less electro-ve than O thus lone pair is easily available.
c) because one of the –NH2 is involved in resonance with carbonyl group and hence acquires
positive charge.
17
1
1
HBr → H+ + Br-
1
1
Or
1
( where R = -CH3)
18
19
a) Resonance effect leading to partial double bond character thus making it difficult to
cleave it.
b) As the new intermolecular interactions with the solvent have same strength as the ones
being broken individually.
c) Acetone is soluble in water due to hydrogen bonding with water molecules.
Benzophenone has two large size phenyl group and they do not permit hydrogen bonding.
(i) C6H5NO2
;
C6H5NH2
A
(ii) CH3CN
A
20
/
CH3COOH
B
C6H5N2+Cl–
B
∆
CH3CONH2
C6H5OH
1
1
1
1.5
C
CH3NH2
1.5
C
(i) As primary amines form inter molecular H – bonds, but tertiary amines don’t form 1
H – bonds.
(ii) Aniline forms salt with Lewis acid AlCl3.
(iii) Because the positve charge on carbonyl carbon of CH3 CHO decreases to a lesser
1
1
extent due to one electron releasing (+I effect) CH3 group as compared to CH3 COCH3
(two electron releasing CH3 groups) and hence more reactive.
21
22
Presence of EWG at ortho and para enhances the acidic strength of the phenol. Its due to effective
delocalisation of negative charge in phenoxide ion.
Resonating structures of both
a) Phenoxide is more stable
b) Ethers don’t have inter H bonding
c) Phenol with FeCl3--- voilet
22
OR
a)
1
1+1
1
1
1
1
1
23
b)
c) (CH3)-C-I + C2H5OH
i)
Narcotic analgesics- morphine
mor
ii)
Aspartame / Saccharin
rin / Alitame / Sucrolose.(any one)
iii)
Dutiful / caring / human
mane in the large interest of public health in rurall are
area.
24
a) I)
1
1+1
1
1
1
ii)
1
iii)
1
24
OR
b)
(i) Heat with I2 and NaOH→propano
anone gives yellow ppt. of iodoform
(ii) Add Schiff’s reagent →Benzald
nzaldehyde gives pink colour.
(Any other correct test)
a)i)
1
1
1
ii)
iii)
1
1
(b) (i) Add neutral FeCl3 in both
bo the solutions, phenol forms violet colourr but benzoic
acid does not.
ii)aldehyde gives fehling test as red ppt.
1
1
25
a) I)
1
ii)
1
iii)
1
25
OR
b)
Amylose
Water soluble
15-20% of starch
a) I)
Amylopectin
Insoluble in water
80-85% of starch
1+1
1
each individual product
ct mentioned
m
ii)
1
iii)
1
26
26
OR
b)
Pyranose
Furanose
Resembles pyran ring- 1 ‘0’ and 5 ‘C’
‘C
Resembles furan ring-1 ‘0’ and 4 ‘C’
Glucose shows this structure
Fructose shows (or shown by struct
ructure)
a) Competitive inhibition- drug compete for natural site + diagram
Allosteric site-drug don’tt bind
bin to actual site but different site and changes the
conformation of originall site.+
site diagram
b) i)antiallergic and antacid both
bo work on different receptors
ii)non adrenaline is low and thus signal sending activity becomes low
a) analgesics- abolish pain without
with
impairment of consciousness
non-narcotic- not addictive
ive and
a eg-aspirin, paracetamol
narcotic- addictive abd given
iven to control severe pain. Eg- morphine, heroin
b) i)unstable at cooking tempe
perature
ii)during lack of natural chemical
chem
messenger as they mimic the natural one and switch on
the receptor.
1+1
1.5
1.5
1
1
1
1
1
1
1