Class 8: Cube Roots – Exercise 7 C 1. Find the cubes of: i. 16 163 = 16 x 16 x 16 = 4096 ii. iv. 0.73 = 0.7 x 0.7 x 0.7 = 0.343 30 303 = 30 x 30 x 30 = v. 27000 iii. 0.7 0.06 0.063 = 0.06 x 0.06 x 0.06 = 1.2 0.000216 1.23 = 1.2 x 1.2 x 1.2 = vi. 1.728 vii. viii. 2 3 ( ) = 5 8 125 1 3 ( ) = 9 1 729 3 3 512 5 125 (1 ) = 2. Test whether the given number is a perfect cube or not: i. 729 = 7 x 7 x 7 (hence a perfect cube) ii. 3380 = 4 x 5 x 13 x 13 (hence not a perfect cube) iii. 10584 = 8 x 3 x 3 x 3 x 3 x 7 x 7 (hence not a perfect cube) iv. 13824 = (2 x 2 x 2) x (2 x 2 x 2) x (2 x 2 x 2) x (3 x 3 x 3) (hence a perfect cube) 3. Find the smallest number by which 11979 must be multiplied so that the product is a perfect cube. 11979 = 3 x 3 x 11 x 11 x 11 Therefore multiply the number by 3 for it to be a perfect cube. 1 For more information please go to: https://icsemath.com/ 4. Find the smallest number by which 8788 must be divided so that the quotient is a perfect cube. 8788 = 2 x 2 x 13 x 13 x 13 Hence divide the number by 4 so that the quotient is a perfect square 5. Find the cube root of: i. 1728 = 23 x 23 x 33 Therefore the cube root of 1728 is 12 ii. 5832 = 23 x 93 Therefore the cube root of 5832 is 18 iii. 10648 = 23 x 113 Therefore the cube root of 10648 is 22 iv. 35937 = 33 x 113 Therefore the cube root of 35937 is 33 216 v. 2197 4 vi. 6×6×6 = 508 1331 13×13×13 5832 = Therefore the cube root of = 1331 42875 = vii. 42.875 = viii. 0.000110592 = 1000 2×2×2×9×9×9 11×11×11 10×10×10 110592 = 2197 is 6 13 Therefore the cube root of 4 5×5×5×7×7×7 1000000000 216 508 1331 = 18 11 Therefore the cube root of 42.875 is 3.5 4×4×4×4×4×4×3×3×3 1000×1000×1000 Therefore the cube root of 0.000110592 is 0.048 6. Evaluate: i. 3 3 √1352 × √1625 3 3 = √2 × 2 × 2 × 13 × 13 × √5 × 5 × 5 × 13 = 2 × 5 × 13 = 130 ii. iii. iv. 3 √ 51.2 0.4096 3 = √ 512000 4096 3 = √ 2×2×2×2×2×2×2×2×2×10×10×10 2×2×2×2×2×2×2×2×2×2×2×2 =5 3 √√0.000064 = 3√0.008 = 0.2 3 √√0.004096 + 3√0.729 3 = √0.064 + 0.9 = 0.4 + 0.9 = 1.3 2 For more information please go to: https://icsemath.com/
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