work means all work,
regardless of what kind
ALWAYS TRUE, but
Delta H =q only if
p= pex =constant and
non-pV work =0;
non-pV work is not 0
here (electrical work)
∆S requires a reversible process. You are
required to do one in part (b), but if you were
not, you would say: I can use the equation for
work for a reversible isothermal expansion of an
ideal gas and get qrev= -wrev.
BEING A STATE FUNCTION, ∆S DOES NOT
DEPEND ON WHETHER REVERSIBLE OR
IRREVERSIBLE.
∆U, ∆H, ∆S must be the SAME in part a
and b because they are state functions.
q and w will usually be different because
different paths can give more or less work
Boiling = Evaporation into bubbles. That
can only happen if the vapor pressure is
slightly above the applied pressure.
NO! You can get to know that without looking it up. The bond
dissociation table will quickly get you within a factor of 2. This reaction
is probably not as exothermic as was implied in what I read.