y = 3x + 5
2x + 4y = 34
2x + 4(3x + 5) = 34
y = 3(1) + 5
2x + 12x + 20 = 34
14x + 20 = 34
y=3+5
y=8
14x = 14
x = 1
then find y
y = -2x - 6
6x + 3y = 11
6x + 3(-2x - 6) = 11
6x - 6x - 18 = 11
- 36 = 11

Jeff Bivin -- LZHS
x = 5y + 1
2x - 10y = 2
2(5y + 1) - 10y = 2
10y + 2 - 10y = 2
2= 2
3x – 5y = 14
2x + 4y = -20
Decide which variable
you want to eliminate.
I think I’ll
choose to
eliminate the y
variable.
3x – 5y = 14
2x + 4y = -20
56
3(-2) – 5y = 14
10x + 20y = -100
-6 - 5y = 14
-5y = 20
y = -4
12x - 20y =
22x
= -44
x = -2
then find y
2x + 7y = 48
3x + 5y = 28
Decide which variable
you want to eliminate.
I think I’ll
choose to
eliminate the x
variable.
2x + 7y = 48
3x + 5y = 28
6x + 21y = 144
3x + 5(8) = 28
-6x - 10y = -56
3x + 40 = 28
3x = -12
x = -4
11y = 88
y = 8
4x + 3y = -19
6x + 5y = -32
Decide which variable
you want to eliminate.
I think I’ll
choose to
eliminate the x
variable.
4x + 3y = -19
6x + 5y = -32
12x + 9y = -57
6x + 5(-7) = -32
-12x - 10y = 64
6x - 35 = -32
6x = 3
-y = 7
y = -7
then find x
x 

1
2
, 7 
1
2