Professor Katiraie
Calculus One
Quiz 1 Form A
Spring 2008
Name
_
Total Possible Points = 20
Sections 1.1 - 1.3
Solve the problem.
1) 1he information in the chart gives the salary of a person for the stated years. Model the data with a linear
function (Find a linear function) using the points (1,24,300) and (3,26,700).
Salary,y
_ 2.-&700- "I-tf300
Year, x
1990,0
$23,500
1\\,
.=. {2oo
1991,1
$24,300
'3­
1992,2
$25,200
~- 2..1+ '3UQ ::: \ ZOo (X.-
IJ
1993,3
1994,4
$26,700
$27,200
. .
~..::=
I'Z 00)(.
J
" L"7l
=- , I'200"
+ .~ 00
- Vz..oO +-'Z...tt-1o~
2) A shoe company will make a new type of shoe. 1he fixed cost for the production will be $24,000. 1he variable
cost will be $35 per pair of shoes. 1he shoes will sell for $108 for each pair. How many pairs of shoes will have
to be sold for the company to break even on this new line of shoes?
0.0) t::= 2-Lf-ooo + "35")(
~. Bre.Jf- (W~
~sr
R.M~=
I08X.
~"
----;#
" -.
'2-'+000
.=:
7 ?
· ~3 Z?
fa.jf"S
3) When going more than 38 miles per hour, the gas mileage of a certain car fits the model y = 43.81 - .395x where x
is the speed of the car in miles per hour and y is the miles per gallon of gasoline. Based on this model, at what
speed will the car average 15 miles per gallon? (Round to nearest whole number.)
IS = 4-3. t>( - 0.'39;; ;<
-
?l X ==
'12-·11f ~ 73 Mf"-'J
Write a function for the following graph. Assume that the relatiL·o~:n:s:hi:·~ps:ar::.e.:li:n:::ear::.:.:.---------- ......
4)
­
-_...._._. t.. ­
-+,>(+2-) -~<X~O
-~)l.+2. /
.M.....
\ <X~'2.
- If-X +If
x
!
+--+---+---t=<:-!l.-+--+---+----+~ - 'tJ
l.......... ._
L L.... _ _.. . .__ ...L .
_~/1
b~&
It---
l
M;::- 2- 3
'1
0-- .
'::: -
~\(~~ (OI'V)
~~
--ti + 7.....
-
l
'2­
'm. ::=
Q.'Z.-...::= -l...
I--C
~~~4 (<J'lt)
~ :;-2.-)( + z..
J!izJ;*~C
-tf-_ o-:::;.
'((I.;:::;
~-
'2..-'
0
-
lL
T
== -'f(X-1)
d::::::- -If-)l +- If­
o<X~f
Compute and simplify the difference quotient [f(x + h) - f(x))/h.
= 2;x2 + 13x
5) f(x)
- 10
.
f(~+kJ.:= 2..-(x+l)1-+\'3(t"+lJ_\~ -=
2.)('1-+
f,(l+"Lk'\.. + l~x-+13l-\a
.f-l)l+-~J _~ (~J == ~~~lf')[k +-1..k'\.-t-~ *"l:J~,..1O - C~+%~ . ~·~
h ( 4-)(, + 'L ~ -\- \ '3)
~l'/.~l~ f(t.) = xC <f'tjth-t- 13J _-Lf- K+ 1.(+-13]
::=
Using the graph below. sketch the graph of the given function.
(-2,3)
d;: ; J(~+ ~)- ~
4
3
rYVI-JM.!J
~.
01.:1.,....
-~
-'Z..-
ttl)Wv\'1. ~
. . . . . . . . -.
y
----+---:;;;;­
.
_'L
-\
2­
~
I
-"2.­
o
2­
't
S~ ~ 7-. \J.-~ ~~
~~'(\.;'
J~{~
~
'"1--­
l
1,....
x
\
,
6) Sketch the Graph of y = f(x + 2) - 1
Graph the indicated new function. given the graph for y = f(x).
7)y=-tf (x)
~
...........
'I... _.... _.
:.. : :.. :.. :. :, t~;
-4)
.. .. .. ....
~
0
-3 -If
.
y
.......o.o. ..........
:::::::::: ::::::::::"
; x..~' t1P......d.... w ~L
";'l:,
0
-3
2­
o
~
,
l ..
i .
­
:(j,:-4~::::::
X. it :::::::::::,,:::::::::::
-~
~~ ~ ~ aY;J/~J ~'iT'~ ~ -~
0
+2­
0
J
~ tte.4.- 0 I
1t:-,;t:eltl.4 -!L
'I- r ~
.A• •
,;-­