Investigating the effect of surface area to volume ratios on osmosis. Introduction Surface area to volume ratios are a way of measuring the size of an object. The surface area of the outermembrane is numerically compared to the volume. For example, in Figure 1 there are three cubes that have different sizes but are the same shape. The smallest cube has the largest surface area to volume ratio and the largest cube has the smallest. Figure 1. The surface area to volume ratio of three objects Dimensions: 1cm x 1cm x 1cm Surface area = 1+1+1+1+1+1cm2 =6cm2 Volume = 1cm3 SA:Vol = 6:1 Dimensions: 2cm x 2cm x 2cm Surface area = 4+4+4+4+4+4cm2 = 24cm2 Volume = 8cm3 SA:Vol = 24:8 = 3:1 Dimensions: 3cm x 3cm x 3cm Surface area = 9+9+9+9+9+9cm2 =54cm2 Volume = 27cm3 SA:Vol = 54:27 = 2:1 Osmosis is the movement of water across a semi-permeable membrane from areas of high concentration to low concentration. Aim To determine the effect of surface area to volume ratios on the movement of water through cubes of potato. Variables Variable Description Independent Dependent Controlled Hypothesis Use third person, present tense. [If the size of an object is larger, then …………….. . This will happen because……. .] Materials Potato Water 2 x 200ml beakers White tile Scalpel Ruler 50ml Measuring cylinder Pipette Paper towel Electronic balance Method 1. Pour 200ml of water into the 300ml beaker (use a measuring cylinder) 2. Carefully cut 2 cubes of potato (approximately 2x2x2cm, use a ruler to measure) 3. Carefully cut 1 of the cubes of potato into four cubes (each approximately 1x1x1cm, use a ruler to measure) 4. Weigh the 2cm3 cubes using a balance, record the mass in a table 5. Weigh the combined mass of the four 1cm3 cubes, record mass in a table 6. Place the cubes into the beaker, ensure the solution completely covers the cubes 7. Leave for 15 minutes 8. Remove the cubes from the beakers and remove excess water from cubes with paper towel 9. Reweigh the chips and record results in table 10. Collect class results 11. Calculate the average change in mass and then the percentage average change in mass of each set of cubes. Results Individual Results: Dimensions of cube (cm) Mass at time = 0 (g) Mass after 15mins (g) Change in mass (g) % mass change 1x1x1 2x2x2 3x3x3 Class Results: Dimensions of cube (cm) CLASS INDIVIDUAL RESULTS Average % mass change 1x1x1 2x2x2 3x3x3 Discussion 1. The Independent variable was the different sizes of the potato cubes. What relationship was found between this variable and the % mass change? 2. What was happening for the mass of the potato cubes to change? (hint: refer to osmosis) 3. Rank the potato cube sizes in order of the largest surface area to volume ratio (SA:volume) to the smallest? 4. Link and explain how the SA:volume affects the mass change of the potato cubes. 5. How does this investigation help us understand why cells are small?
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