155S9.5_3 Comparing Variation in Two Samples MAT 155 Statistical Analysis April 21, 2012 Key Concept Dr. Claude Moore Cape Fear Community College Chapter 9 Inferences from Two Samples 91 Review and Preview 92 Inferences About Two Proportions 93 Inferences About Two Means: Independent Samples 94 Inferences from Dependent Samples 95 Comparing Variation in Two Samples Copyright © 2010, 2007, 2004 Pearson Education, Inc. This section presents the F test for comparing two population variances (or standard deviations). We introduce the F distribution that is used for the F test. Note that the F test is very sensitive to departures from normal distributions. Copyright © 2010, 2007, 2004 Pearson Education, Inc. Nov 189:41 AM Notation for Hypothesis Tests with Two Variances or Standard Deviations = larger of two sample variances = size of the sample with the larger variance = variance of the population from which the sample with the larger variance is drawn Nov 189:41 AM Requirements 1. The two populations are independent. 2. The two samples are simple random samples. 3. The two populations are each normally distributed. are used for the other sample and population Copyright © 2010, 2007, 2004 Pearson Education, Inc. Copyright © 2010, 2007, 2004 Pearson Education, Inc. Nov 189:41 AM Test Statistic for Hypothesis Tests with Two Variances Where s12 is the larger of the two sample variances Critical Values: Using Table A5, we obtain critical F values that are determined by the following three values: 1. The significance level α 2. Numerator degrees of freedom = n1 – 1 3. Denominator degrees of freedom = n2 – 1 Copyright © 2010, 2007, 2004 Pearson Education, Inc. Nov 189:41 AM Nov 189:41 AM Properties of the F Distribution • The F distribution is not symmetric. • Values of the F distribution cannot be negative. • The exact shape of the F distribution depends on the two different degrees of freedom. Copyright © 2010, 2007, 2004 Pearson Education, Inc. Nov 189:41 AM 1 155S9.5_3 Comparing Variation in Two Samples Finding Critical F Values April 21, 2012 Finding Critical F Values To find a critical F value corresponding to a 0.05 significance level, refer to Table A5 and use the righttail area of 0.025 or 0.05, depending on the type of test: Twotailed test: use 0.025 in right tail Onetailed test: use 0.05 in right tail Copyright © 2010, 2007, 2004 Pearson Education, Inc. Copyright © 2010, 2007, 2004 Pearson Education, Inc. Nov 189:41 AM Properties of the F Distribution cont. If the two populations do have equal Nov 189:41 AM Properties of the F Distribution cont. If the two populations have radically different variances, then F will be a large number. variances, then F = will be close to 1 because and are close in value. Copyright © 2010, 2007, 2004 Pearson Education, Inc. Remember, the larger sample variance will be s12 . Copyright © 2010, 2007, 2004 Pearson Education, Inc. Nov 189:41 AM Conclusions from the F Distribution Consequently, a value of F near 1 will be evidence in favor of the 2 conclusion that σ1 = σ22 . But a large value of F will be evidence against the conclusion of equality of the population variances. Copyright © 2010, 2007, 2004 Pearson Education, Inc. Nov 189:41 AM Nov 189:41 AM Example: Data Set 20 in Appendix B includes weights (in g) of quarters made before 1964 and weights of quarters made after 1964. Sample statistics are listed below. When designing coin vending machines, we must consider the standard deviations of pre1964 quarters and post1964 quarters. Use a 0.05 significance level to test the claim that the weights of pre 1964 quarters and the weights of post1964 quarters are from populations with the same standard deviation. Copyright © 2010, 2007, 2004 Pearson Education, Inc. Nov 189:41 AM 2 155S9.5_3 Comparing Variation in Two Samples April 21, 2012 Example: Requirements are satisfied: populations are independent; simple random samples; from populations with normal distributions Copyright © 2010, 2007, 2004 Pearson Education, Inc. Apr 1410:47 AM Example: Nov 189:41 AM Example: Use sample variances to test claim of equal population variances, still state conclusion in terms of standard deviations. Step 1: claim of equal standard deviations is equivalent to claim of equal variances Step 4: significance level is 0.05 Step 5: involves two population variances, use F distribution variances Step 6: calculate the test statistic Step 2: if the original claim is false, then Step 3: original claim Copyright © 2010, 2007, 2004 Pearson Education, Inc. For the critical values in this twotailed test, refer to Table A5 for the area of 0.025 in the right tail. Because we stipulate that the larger variance is placed in the numerator of the F test statistic, we need to find only the righttailed critical value. Copyright © 2010, 2007, 2004 Pearson Education, Inc. Nov 189:41 AM Example: Nov 189:41 AM Example: From Table A5 we see that the critical value of F is between 1.8752 and 2.0739, but it is much closer to 1.8752. Interpolation provides a critical value of 1.8951, but STATDISK, Excel, and Minitab provide the accurate critical value of 1.8907. Step 7: The test statistic F = 1.9729 does fall within the critical region, so we reject the null hypothesis of equal variances. There is sufficient evidence to warrant rejection of the claim of equal standard deviations. Copyright © 2010, 2007, 2004 Pearson Education, Inc. Nov 189:41 AM Copyright © 2010, 2007, 2004 Pearson Education, Inc. Nov 189:41 AM 3 155S9.5_3 Comparing Variation in Two Samples April 21, 2012 Recap Example: There is sufficient evidence to warrant rejection of the claim that the two standard deviations are equal. The variation among weights of quarters made after 1964 is significantly different from the variation among weights of quarters made before 1964. Copyright © 2010, 2007, 2004 Pearson Education, Inc. Nov 189:41 AM In this section we have discussed: • Requirements for comparing variation in two samples • Notation. • Hypothesis test. • Confidence intervals. • F test and distribution. Copyright © 2010, 2007, 2004 Pearson Education, Inc. Nov 189:41 AM Hypothesis Test of Equal Variances. In Exercises 5 and 6, test the given claim. Use a significance level of α = 0.05 and assume that all populations are normally distributed. Hypothesis Test of Equal Variances. In Exercises 5 and 6, test the given claim. Use a significance level of α = 0.05 and assume that all populations are normally distributed. 507/5. Zinc Treatment Claim: Weights of babies born to mothers given placebos vary more than weights of babies born to mothers given zinc supplements (based on data from “The Effect of Zinc Supplementation on Pregnancy Outcome,” by Goldenberg, et al., Journal of the American Medical Association, Vol. 274, No. 6). Sample results are summarized below. Placebo group: n = 16, x = 3088 g, s = 728 g Treatment group: n = 16, x = 3214 g, s = 669 g 507/6. Weights of Pennies Claim: Weights of pre1983 pennies and weights of post1983 pennies have the same amount of variation. (The results are based on Data Set 20 in Appendix B.) Weights of pre1983 pennies: n = 35, x = 3.07478 g, s = 0.03910 g Weights of post1983 pennies: n = 37, x = 2.49910 g, s = 0.01648 g 507/5. TI results 507/6. TI results Box 4: Not enough evidence to support the claim that weights of babies born to mothers given placebos vary more than weights of babies born to mothers given zinc supplements. Nov 1810:08 AM Hypothesis Tests of Claims About Variation. In Exercises 9–18, test the given claim. Assume that both samples are independent simple random samples from populations having normal distributions. 508/10. Braking Distances of Cars A random sample of 13 fourcylinder cars is obtained, and the braking distances are measured and found to have a mean of 137.5 ft and a standard deviation of 5.8 ft. A random sample of 12 sixcylinder cars is obtained and the braking distances have a mean of 136.3 ft and a standard deviation of 9.7 ft (based on Data Set 16 in Appendix B). Use a 0.05 significance level to test the claim that braking distances of four cylinder cars and braking distances of sixcylinder cars have the same standard deviation. Nov 1810:08 AM Hypothesis Tests of Claims About Variation. In Exercises 9–18, test the given claim. Assume that both samples are independent simple random samples from populations having normal distributions. 508/12. Home Size and Selling Price Using the sample data from Data Set 23 in Appendix B, 21 homes with living areas under 2000 ft2 have selling prices with a standard deviation of $ 32,159.73. There are 19 homes with living areas greater than 2000 ft2 and they have selling prices with a standard deviation of $ 66,628.50. Use a 0.05 significance level to test the claim of a real estate agent that homes larger than 2000 ft2 have selling prices that vary more than the smaller homes. 508/12. TI results Correct Fvalue because of larger numerator; same Pvalue. 508/10. TI results Incorrect Fvalue because of smaller numerator; same Pvalue. Nov 1810:08 AM Nov 1810:08 AM 4 155S9.5_3 Comparing Variation in Two Samples Hypothesis Tests of Claims About Variation. In Exercises 9–18, test the given claim. Assume that both samples are independent simple random samples from populations having normal distributions. 508/15. Radiation in Baby Teeth Listed below are amounts of strontium90 (in millibec querels or mBq per gram of calcium) in a simple random sample of baby teeth obtained from Pennsylvania residents and New York residents born after 1979 (based on data from “ An Un expected Rise in Strontium90 in U. S. Deciduous Teeth in the 1990s,” by Mangano, et al., Science of the Total Environment). Use a 0.05 significance level to test the claim that amounts of Strontium90 from Pennsylvania residents vary more than amounts from New York residents. Pennsylvania: 155 142 149 130 151 163 151 142 156 133 138 161 New York: 133 140 142 131 134 129 128 140 140 140 137 143 L1 S95A L2 S95B April 21, 2012 Hypothesis Tests of Claims About Variation. In Exercises 9–18, test the given claim. Assume that both samples are independent simple random samples from populations having normal distributions. 509/16. BMI for Miss America Listed below are body mass indexes (BMI) for Miss America winners from two different time periods. Use a 0.05 significance level to test the claim that winners from both time periods have BMI values with the same amount of variation. BMI (from recent winners): 19.5 20.3 19.6 20.2 17.8 17.9 19.1 18.8 17.6 16.8 BMI (from the 1920s and 1930s): 20.4 21.9 22.1 22.3 20.3 18.8 18.9 19.4 18.4 19.1 L1 S95C L2 S95D 509/16. TI results 508/15. TI results Box 3: Support the claim that amounts of Strontium90 from Pennsylvania residents vary more than amounts from New York residents. Nov 1810:08 AM Nov 1810:08 AM 5
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