Section 3.6.notebook January 06, 2011 Substitution and Elimination Method Review Example 1: x = 4y + 10 4x + 2y = 4 Example 2: 6x - 5y = 9 2x - y = 1 Substitution and Elimination Method Review Example 1: x = 4y + 10 4x + 2y = 4 Example 2: 6x - 5y = 9 2x - y = 1 Section 3.6.notebook January 06, 2011 Section 3.6ThreeVariable Systems Objective: To solve a system with 2 or more variables and equations. Substitution Method Example 1: Solve for the variables. x + 5y - 6z = 29 y + 4z = -10 z = -3 Substitution Method Example 2: Solve for the variables. x - 2y + 3z = 9 y + 3z = 5 z=2 Section 3.6.notebook January 06, 2011 Elimination Method Example 3: Solve for all variables. x - 2y + 3z = 9 -x + 3y = -4 2x - 5y + 5z = 17 Elimination Method Example 3: Solve for all variables. x - 2y + 3z = 9 -x + 3y = -4 2x - 5y + 5z = 17 Section 3.6.notebook January 06, 2011 Elimination Method Example 4: Solve for all variables. x +y+z= 6 2x - y + z = 3 3x -z=0 Elimination Method Example 5: Solve for all variables. x - 3y + z = 1 3x + y - 2z = -2 x - y- z= 1 Section 3.6.notebook January 06, 2011 Elimination Method Example 6: Solve for all variables. x+ y+ z= 4 2x - y + 2z = 5 x - 2y - z = -3 Homework... Section 3.6 Page 224 1, 4, 9, 15
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