ExamView - Ch. 7 Test Practice.tst

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Algebra II: Chapter 7 Exam Practice
1
Find the inverse of y = 4x 2 − 8 .
4
Solve. Check for extraneous solutions.
1
1
(3x + 10) 3 = (4 + 9x) 3
A
B
C
D
x−8
4
x−8
y2 =
4
y = ±
x =
y = ±
A
B
-1
1
7
6
1
2
C
y+8
4
D
x+8
4
5
Solve. Check for extraneous solutions.
3
2
Let f(x) = −4x − 2 and g(x) = 3x − 7. Find f(x)
+ g(x).
A
B
C
D
3
(x + 4 ) 5 = 8
A
B
C
D
–7x – 9
–x + 5
–7x + 5
–x – 9
6
Solve. Check for extraneous solutions.
Simplify.
18
x − 7 − 9 = −5
28
36
4
12
1
1
2
⋅ 18 2
A
B
1
18
C
D
18 4
18
1
A
B
C
D
23
9
11
16
1
Practice Practice Practice Practice Practice Practice Practice Practice Practice Practice Practice
7
Solve the equation. Check for extraneous
solutions.
3
10
B
C
D
11
Let f(x) = 5x + 2 and g(x) = −6x + 7. Find
f ⋅ g and its domain.
A
C
D
D
9
−30x 2 + 23x + 14; all real numbers
10x 2 + 47x − 42; all real numbers
−30x 2 + 23x + 14; all real numbers except x
7
=
6
10x 2 + 47x − 42; all real numbers except x =
2
−
5
12
B
C
D
1
25
1
5
25
5
Simplify.
2 4 6x + 5 4 6x
A
B
C
D
Simplify 3 135a 10 b 6 . Assume that all variables
are positive.
A
56 2
122
2 11
11 2
Which is equivalent to 125 −2/3 ?
B
A
B
C
72
x − 8 = −5
A
8
50 +
Simplify:
3a 3 b 2 3 5a
5a 3 b 2 3 3a
3a 3 b 3 a
none of these
2
42 4 6x
7 4 12x
7 4 6x
not possible to simplify
13
Simplify: (5 4 / 5 ⋅ 5 4 / 5 ) −10
14
Simplify:
25 1 / 6
25 2 / 3
Practice Practice Practice Practice Practice Practice Practice Practice Practice Practice Practice
C
15
Find the inverse of the relation
(0, –5), (–5, 0), (1, 9).
16
Graph the relation and its inverse. Use open
circles to graph the points of the inverse.
x
–3
–1
1
2
y
–9
7
7
7
D
A
17
B
3
Write an equation for the inverse of the relation
y = −22x − 7.
Practice Practice Practice Practice Practice Practice Practice Practice Practice Practice Practice
18
Rationalize the denominator of the expression.
Assume that all variables are positive.
3
A
B
C
D
2
3 2
23 3
3
108
3
3 2
A
B
C
D
Simplify the expression. Assume all variables are
positive.
20
3
6x 3 y 7
⋅
3
23
4x 5
A
B
C
D
42 + 12
−6 − 6
42 − 12
36 + 12
6
6
6
6
−3x 2 − 2x − 1
−3x 2 − 2x − 7
2x 2 − 2x + 10
2x 2 − 2x − 14
Let f(x) = 3x + 5 and g(x) = 4x + 7. Find
(f û g)(5).
A
B
C
D
Simplify.
ÊÁ
ˆ2
ÁÁ −6 + 6 ˜˜˜
Ë
¯
24
21
Let f(x) = x 2 + 2x − 1 and g(x) = 2x − 4. Find
2f(x) – 3g(x).
108
3
19
22
27
86
87
20
Rationalize the denominator of the expression.
Assume that all variables are positive.
3
6
3
2
Simplify 27 2 / 3 .
A
B
C
D
A
27
18
1
3
9
2 3 12
3
B
3
C
D
4
24
2
12
2
none of these
Practice Practice Practice Practice Practice Practice Practice Practice Practice Practice Practice
25
Simplify.
ÁÊÁ 4 − 6 ˜ˆ˜ ÁÊÁ 6 +
ÁË
˜¯ ÁË
27
ˆ
6 ˜˜˜
¯
Rationalize the denominator of the expression.
Assume that all variables are positive.
6x 8 y 9
5x 2 y 4
A
B
C
D
26
6
6
6
6
C
D
A
B
3
2x 3 ⋅
2x 3 ⋅
8x 7 ⋅
3
3
4x 11
4x 2
30x 10 y 13
3
5x 2 y 4
5x 3 y 2 30y
none of these
C
D
28
Rationalize the denominator of the expression.
Assume that all variables are positive.
2+
3
3
D
3
A
2 3 6 + 9 3 18
6
B
2 3 36 + 3 3 4
6
C
23 6 + 9 3 4
6
D
2 3 36 + 3 3 4
6
32x 11
none of the above
5
3
6
4x 4 . Assume that all variables are positive.
C
30y
5
B
7x − 49x
x 7 − x 49
− 42x
Simplify
x3y2
A
Multiply and simplify if possible.
Ê
ˆ
7x ÁÁÁ x − 7 7 ˜˜˜
Ë
¯
A x 7 − 49 x
B
29
30 + 24
4 + 10
18 + 24
18 − 2
ID: A
Algebra II: Chapter 7 Exam Practice
Answer Section
1
D
2
D
3
A
4
B
5
A
6
B
7
–117
8
A
9
A
10
D
11
A
12
15
C
1
5 16
1
5
(–5, 0), (0, –5), (9, 1)
16
B
17
y=−
18
D
19
2x 2 y 2 3 3x 2 y
20
C
21
D
22
C
23
B
24
D
25
D
26
A
27
A
28
D
29
B
13
14
x+7
22
1