Part 21 Isometries Printed version of the lecture Differential Geometry on 20. November 2009 Tommy R. Jensen, Department of Mathematics, KNU 21.1 Overview Contents 1 Isometry 1 2 Orthogonal Transformations 3 3 Characterization of Isometries 5 4 Conclusion 6 Isometry (Koji Takei) 21.2 1 Isometry Isometries in Euclidean space Definition 1.1 An isometry of R3 is a mapping F : R3 → R3 that satisfies d(F(p), F(q)) = d(p, q) for all points p, q of R3 . 21.3 1 Example 1.2(1): translation Definition Let a be a point in R3 and define a mapping T by T (p) = p + a for all p in R3 . Then T is called the translation by a. A translation is an isometry We check, for any two points p, q : d(T (p), T (q)) = d(p + a, q + a) = ||(p + a) − (q + a)|| = ||p − q|| = d(p, q). 21.4 Example 1.2(2): rotation Definition Let ϑ be a real number in [0; 2π] and define a mapping C by C(p1 , p2 , p3 ) = (p1 cos ϑ − p2 sin ϑ , p1 sin ϑ + p2 cos ϑ , p3 ). Then C is called the rotation through the angle ϑ around the z axis. A rotation around the z axis is an isometry Some calculations using cos2 + sin2 = 1 prove ||C(p) −C(q)|| = ||p − q|| for all p, q in R3 . 21.5 Composition of isometries Lemma 1.3 If F and G are isometries of R3 , then the composite mapping G(F) is also an isometry of R3 . Proof of Lemma 1.3 Let p and q be points in R3 . Then d(G(F(p)), G(F(q))) = d(F(p), F(q)) = d(p, q). 21.6 2 Inverse function Properties of an inverse function If F : R3 → R3 is one-to-one and onto, then there exists a uniquely determined function F −1 : R3 → R3 with the properties F(F −1 ) = F −1 (F) = I, where I : R3 → R3 is the identity mapping: I(p) = p for all p in R3 . 21.7 Composition of translations Lemma 1.4 • If S and T are translations of R3 , then S(T ) = T (S), and this mapping is also a translation. • If T is the translation by a, then T −1 exists and is the translation by −a. • If p and q are points in R3 , then there exists a unique translation T such that T (p) = q. Special case If T is a translation and there exists a point p such that T (p) = p, then T is the identity mapping: T = I. 21.8 2 Orthogonal Transformations Orthogonal transformations Definition A mapping F : R3 → R3 is an orthogonal transformation if F is linear, and F(p) • F(q) = p • q for all p, q in R3 . Example: The rotation C of Example 1.2 is an orthogonal transformation: C(p) •C(q) = (p1 cos ϑ − p2 sin ϑ , p1 sin ϑ + p2 cos ϑ , p3 ) •(q1 cos ϑ − q2 sin ϑ , q1 sin ϑ + q2 cos ϑ , q3 ) = p1 q1 (cos2 ϑ + sin2 ϑ ) +p1 q2 (− cos ϑ sin ϑ + sin ϑ cos ϑ ) +p2 q1 (− sin ϑ cos ϑ + cos ϑ sin ϑ ) +p2 q2 (sin2 ϑ + cos2 ϑ ) + p3 q3 = p1 q1 + p2 q2 + p3 q3 = p • q. 21.9 Orthogonal transformations and isometry Lemma 1.5 If F : R3 → R3 is an orthogonal transformation, then F is an isometry of R3 . Proof of Lemma 1.5 First, F preserves norm: ||F(p)||2 = F(p) • F(p) = p • p = ||p||2 . 3 This implies ||F(p)|| = ||p|| for all points p in R3 . Next, F is an isometry, since for all p, q in R3 : d(F(p), F(q)) = ||F(p) − F(q)|| = ||F(p − q)|| = ||p − q|| = d(p, q). 21.10 Isometries and orthogonal transformations Lemma 1.6 If F is an isometry of R3 such that F(~0) = ~0, then F is an orthogonal transformation. Proof of Lemma 1.6 The proof has two parts: • proof that F(p) • F(q) = p • q for all p, q in R3 , and • proof that F is linear. 21.11 Proof that F(p) • F(q) = p • q for all p, q in R3 . We know that F is an isometry, and F(~0) = ~0. Therefore: ||F(p)|| = d(~0, F(p)) = d(F(~0), F(p)) = d(~0, p) = ||p||. If p, q are two points in R3 , then ||F(p) − F(q)||2 = ||p − q||2 : (F(p) − F(q)) • (F(p) − F(q)) = (p − q) • (p − q), so linearity of the dot product implies ||F(p)||2 − 2F(p) • F(q) + ||F(q)||2 = ||p||2 − 2p • q + ||q||2 . Because of ||F(p)|| = ||p|| and ||F(q)|| = ||q|| we get F(p) • F(q) = p • q. 21.12 Proof that F is linear Let u1 = (1, 0, 0), u2 = (0, 1, 0) and u3 = (0, 0, 1). We know that F preserves dot products, so F(ui ) • F(u j ) = ui • u j = δi j for 1 ≤ i, j ≤ 3. Let p = (p1 , p2 , p3 ) be any point in R3 . Orthonormal expansion gives: F(p) = ∑(F(p) • F(ui ))F(ui ) = ∑(p • ui )F(ui ) = ∑ pi F(ui ). If p, q are points and a, b are real numbers, then F(ap + bq) = ∑(api + bqi )F(ui ) = a ∑ pi F(ui ) + b ∑ qi F(ui ) = aF(p) + bF(q). This shows that F is a linear function. 21.13 4 3 Characterization of Isometries Characterization of isometries Theorem 1.7 Let F be an isometry of R3 . There exists a unique translation T and a unique orthogonal transformation C such that F = T (C). Proof of Theorem 1.7 The proof has two parts: • proof of existence of T and C, and • proof of uniqueness of T and C. 21.14 Proof of existence of T and C with F = T (C) We know that F is an isometry. Let T be the translation by F(~0). Then T −1 is the translation by −F(~0), by Lemma 1.4. It follows from Lemma 1.3 that T −1 (F) is an isometry. Because of T −1 (p) = p − F(~0) for all points p in R3 , we get T −1 (F)(~0) = T −1 (F(~0)) = F(~0) − F(~0) = ~0. Lemma 1.6 implies that T −1 (F) is equal to an orthogonal transformation C. From C = T −1 (F) follows T (C) = T (T −1 (F)) = F. 21.15 Proof of uniqueness of T and C with F = T (C) We assume that T is a translation and C is an orthogonal transformation such that F = T (C). We will prove that T is the translation by F(~0), so T = T, and C = T −1 (F) = C. We have T (C) = T (C) =⇒ C = T −1 (T (C)). Both C and C are linear functions, therefore C(~0) = C(~0) = ~0. Now ~0 = C(~0) = T −1 (T (C))(~0) = T −1 (T )(C(~0)) = T −1 (T )(~0). But T −1 (T ) is a translation, so if it maps ~0 to ~0, then T −1 (T ) is the identity, T −1 (T ) = I. This implies T = T. It follows from C = T −1 (F) = T −1 (F) that C is equal to C. 21.16 5 Decomposition of an isometry Definition Let F be an isometry such that F = T (C) where T is a translation and C is an orthogonal transformation. Then T is called the translation part of F. And C is called the orthogonal part of F. In matrix notation, F can be calculated as a1 c11 F(p1 , p2 , p3 ) = a2 + c21 a3 c31 c12 c22 c32 c13 p1 c23 p2 , c33 p3 where (ci j ) is an orthogonal matrix, with its inverse equal to its transpose, and the translation part of F is the translation by a = (a1 , a2 , a3 ). 21.17 4 Conclusion The End END OF THE LECTURE! (Never give up. . . ) 21.18 Next time: Tangent Map of an Isometry 21.19 6
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