Cubic and Cube Root as Inverses The cubic function y = π₯ 3 and the cube root function y = 3 π₯ are inverse functions (and inverse operations). y ο΄ y = x3 ο³ y=π π ο² ο± x οο΄ οο³ οο² οο± ο± οο± οο² οο³ οο΄ ο² ο³ ο΄ ο΅ y = x3 and y = 3 π₯ are reflections over the line y = x. If y = x3 has the point (2,8), then y = 3 π₯ has (8,2) Determine the inverse of g(x) = 5 π¦ = (π₯ + 1)3 β10 2 5 π₯ = (π¦ + 1)3 β10 2 5 π₯ + 10 = (π¦ + 1)3 2 2 π₯ + 4 = (π¦ + 1)3 5 3 2 π₯+4=π¦+1 5 π¦= 3 2 π₯+4β1 5 5 (π₯ 2 + 1)3 β10. Write the equation in terms of x and y Switch the x and y Solve for y: add 10 Solve for y: multiply by reciprocal of 5/2 Solve for y: take the cube root of both sides Solve for y: subtract 1 3 Determine the inverse of h(x) = 2 2π₯ + 6. 3 π¦ = 2 2π₯ + 6 Write the equation in terms of x and y π₯ = 2 3 2π¦ + 6 Switch the x and y π₯ β 6 = 2 3 2π¦ Solve for y: subtract 6 1 π₯ β 3 = 3 2π¦ 2 3 1 π₯ β 3 = 2π¦ 2 3 1 π₯β3 2 π¦= 2 Solve for y: divide by 2 Solve for y: cube both sides Solve for y: divide by 2 Use composition to show that π π₯ = 2 π₯ β 2 π π₯ = 3 2 3 π₯β1 2 3 + 1 and + 2 are inverses. 3 π₯β1 +2β2 2 +1 Substitute one function into the other. 3 2 3 π₯β1 2 +1 π₯β1 2 +1 2 Cancel out the +2 and -2 The third power cancels out the cube root xβ1+1 Multiplying by 2 cancels out dividing by 2 x -1 and +1 cancel each other leaving x. Since the equation simplified to x (and only x), the functions are inverses.
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