Inverse of Quadratic/Cubic Functions

Cubic and Cube Root as Inverses
The cubic function y = π‘₯ 3 and the cube root
function y = 3 π‘₯ are inverse functions (and inverse
operations).
y

y = x3
ο€³
y=πŸ‘ 𝒙
ο€²
ο€±
x

ο€­ο€³
ο€­ο€²
ο€­ο€±
ο€±
ο€­ο€±
ο€­ο€²
ο€­ο€³

ο€²
ο€³


y = x3 and y = 3 π‘₯ are reflections
over the line y = x.
If y = x3 has the point (2,8), then
y = 3 π‘₯ has (8,2)
Determine the inverse of g(x) =
5
𝑦 = (π‘₯ + 1)3 βˆ’10
2
5
π‘₯ = (𝑦 + 1)3 βˆ’10
2
5
π‘₯ + 10 = (𝑦 + 1)3
2
2
π‘₯ + 4 = (𝑦 + 1)3
5
3
2
π‘₯+4=𝑦+1
5
𝑦=
3
2
π‘₯+4βˆ’1
5
5
(π‘₯
2
+ 1)3 βˆ’10.
Write the equation in terms of x and y
Switch the x and y
Solve for y: add 10
Solve for y: multiply by reciprocal of 5/2
Solve for y: take the cube root of both sides
Solve for y: subtract 1
3
Determine the inverse of h(x) = 2 2π‘₯ + 6.
3
𝑦 = 2 2π‘₯ + 6
Write the equation in terms of x and y
π‘₯ = 2 3 2𝑦 + 6
Switch the x and y
π‘₯ βˆ’ 6 = 2 3 2𝑦
Solve for y: subtract 6
1
π‘₯ βˆ’ 3 = 3 2𝑦
2
3
1
π‘₯ βˆ’ 3 = 2𝑦
2
3
1
π‘₯βˆ’3
2
𝑦=
2
Solve for y: divide by 2
Solve for y: cube both sides
Solve for y: divide by 2
Use composition to show that 𝑓 π‘₯ = 2 π‘₯ βˆ’ 2
𝑔 π‘₯ =
3
2
3
π‘₯βˆ’1
2
3
+ 1 and
+ 2 are inverses.
3
π‘₯βˆ’1
+2βˆ’2
2
+1
Substitute one function into the other.
3
2
3
π‘₯βˆ’1
2
+1
π‘₯βˆ’1
2
+1
2
Cancel out the +2 and -2
The third power cancels out the cube
root
xβˆ’1+1
Multiplying by 2 cancels out dividing by 2
x
-1 and +1 cancel each other leaving x.
Since the equation simplified to x (and
only x), the functions are inverses.