element song http://www.youtube.com/watch?v=zGM‐wSKFBpo&feature=related January 29th, 2014 1-29-14 Chem 1A S2014 1 What do we say in chem. 1A? Chem 1A F2013 Chem 1A S2014 2 If you have not taken and passed the chemistry 1A diagnostic placement exam, it is too late to do so. The due date is not the start date! 10-23-13 1-29-14 We will only add students that have passing diagnostic scores from F13 or S13. 4 1-29-14 Chem 1A S2014 5 1 Lab begins this week! Next week in disc: Monday / Tuesday Got goggles? Next week in Lab: No toes! Wednesday / Thursday •Nomenclature Handout •There will be an online There will be an online Mastering Chemistry assignment this week assignment this week for for discussion covering dimensional dimensional Analysis & Analysis & nomenclature Got lab coat? •Experiment 1 •Practice Proficiency quiz Got Gloves? Got pre lab? Got pre‐lab? No pre‐lab, no lab! 1-29-14 Chem 1A S2014 6 1-29-14 Chem 1A S2014 8 It’s time to play… Chapter 1: Key Topics Reading: Ch. 1.1‐1.7 II will only cover a few examples of calculations using unit ill l f l f l l ti i it conversions. lead (II) sulfide PbS potassium permanganate KMnO4 ammonium nitrite NH4NO2 HC2H3O2(aq) acetic acid Chapter 2: Key Topics Reading: Ch 2 1 2 7 Reading: Ch. 2.1‐2.7 I will cover a few examples of calculations with isotopes and mole/mass concepts. 1-29-14 Chem 1A S2014 BCl3 9 1-29-14 boron trichloride Chem 1A S2014 10 2 Problem Solving in Chemistry: Many of the problems you will solve in chemistry involves a technique called Dimensional Analysis. (Ch.1) Ch t 1 Chapter 1 Dimensional analysis converts one unit to another by using conversion factors. conversion factors Matter, Measurement, and Problem Solving and Problem Solving unit (1) × conversion factor = unit (2) The resulting quantity is equivalent to the original quantity, it differs only by the units. 1-29-14 Chem 1A S2014 13 1-29-14 Chem 1A S2014 Example problem: Problem Solving in Chemistry: A certain automobile has a fuel economy of 32 miles/gallon. When submitting written work in this class: •Labs What is the same fuel economy in km/L? •Quizzes i How do you start this problem? •Exams Ask what you need! new distance and volume units All work must be accompanied by units. What is given? The work given must show a logical progression towards the answer given. How do these quantities relate? gallons can be converted to L ll b d L Now you are ready to set up the problem using dimensional analysis! There will be severe grading penalties if this is not the case! Chem 1A S2014 miles and gallons miles can be converted to km il b d k The answer must have units itself that match the work. 1-29-14 14 15 1-29-14 Chem 1A S2014 16 3 Example problem: Problem solving in chemistry: You need to be systematic in your approach. You can’t memorize every type of problem. A certain automobile has a fuel economy of 32 miles/gallon. What is the same fuel economy in km/L? The Plan: The Plan: convert miles to km then gal to L miles → ft → in → cm → m → km then gal → L look this up! you should know these cf you should know these cf’ss X 32miles 5280ft 1m 1km 1gal X 12in X 2.54cm X X X × × × × 2 × 3 × = 13.588 km/L 1 gal 1mile 1ft 1in 10 cm 10 m 3.79L X X X X X X round to 2 sig figs: 14 km/L 1-29-14 Chem 1A S2014 18 Here is how you should approach solving problems: 1 Put your calculator down. 1. P t l l t d 2. Read the problem. 3. Read it again! 4. Identify the units needed. 5. Identify the units given. 6. Set up a conceptual plan for the solution. 7 Write down any conversion factors you might need. 7. Write down any conversion factors you might need 8. Set up a conversion from the starting units to the needed units using dimensional analysis. 9. Now use your calculator! 10. Check for sig figs, order of magnitude and units 1-29-14 Chem 1A S2014 19 Examples of the wrong way to solve a problem: What the solution to a problem should look like! a plan in outlined 3 sf’s X X No plan! X X No Units! X Wrong cf’s! X X X You also expect a l large number! b The correct sig figs are expressed in the answer: Notice that all units are written: No Partial Credit! Conversion factors cancel out the units! 1-29-14 Chem 1A S2014 20 1-29-14 Chem 1A S2014 ?????? 21 4 Examples of the wrong way to solve a problem: Examples of the wrong way to solve a problem: There is no credit for magically pulling an answer out of your pulling an answer out of your butt! No credit! No Credit! Work does not match! Not Even Wrong 1-29-14 See me in my office ASAP... Correct answer... Dr. Mack Chem 1A S2014 22 Example problem: 1-29-14 Chem 1A S2014 23 Example problem: The aluminum in a package containing 75ft2 of foil weighs 12 oz. The aluminum in a package containing 75ft2 of foil weighs 12 oz. If the density of aluminum is 2.70 g/cm3, what is the thickness of the foil in mm? If the density of aluminum is 2.70 g/cm3, what is the thickness of the foil in mm? How do you start this problem? First find the total volume of the foil: Ask what you need! The thickness of the foil. What is given? area, mass and density volume and area give thickness! thickness = Now you are ready to set up the problem using dimensional analysis! 1-29-14 28.4 g cm3 × = 126 cm3 1 oz 2.70 g Keep the extra sig figs and round at the end. Next find thickness from volume and area: How do these quantities relate? How do these quantities relate? mass and density give volume 12 oz × you may need to look up some conversion factors! Chem 1A S2014 24 1-29-14 volume = area 126 cm3 10 mm = 0.018 mm 2 2 × 1 cm 12 in ⎞ ⎛ 2.54 cm ⎞ 75 ft2 × ⎛⎜ × ⎟ ⎜ ⎟ ⎝ 1ft ⎠ ⎝ 1 in ⎠ Chem 1A S2014 25 5 It’s time to play… What is the area of a circle? A = πr2 What is the volume of a cylinder? V = L×πr2 What is the volume of a sphere? 4 V = πr 3 3 How many feet are in a mile? I will place another dimensional analysis problem in the notes that is not covered in class. 5280 ft = 1 mile You should know these and many other general knowledge facts from your K‐ facts from your K‐12 education! 1-29-14 Chem 1A S2014 28 1-29-14 Chem 1A S2014 Example problem: Example problem: A certain wire alloy has a density of 7.65 g/cm3. What length (m) of wire corresponds to 25.0 lbs of the wire if the radius is 0.55 mm? A certain wire alloy has a density of 7.65 g/cm3. What length (m) of wire corresponds to 25.0 lbs of the wire if the radius is 0.55 mm? First one must realize that the wire is cylindrical in shape. 29 Conceptual Plan: use density as a conversion factor mass → volume → length (knowing the radius) length (knowing the radius) radius You should know this from high school... length 1-29-14 Chem 1A S2014 30 1-29-14 Chem 1A S2014 32 6 To find the length of the wire, begin with volume: mass is related to volume by density: by density: d= L × πr 2 = setting the two equal: 1-29-14 m V L= L= Chem 1A S2014 mass d × πr 2 Plugging in the values... m V= d solving for volume: solving for L: A certain wire alloy has a density of 7.65 g/cm3. What length (m) of wire corresponds to 25.0 lbs of the wire if the radius is 0.55 mm? V = L × π r2 25.0 lb × L = m d 7.65 mass d × πr 2 1 kg 103 g × 2.205 lb 1 kg (1 cm)2 g × π× (0.55mm) (0 55mm) 2 × 3 (10 mm)2 cm = 1. 5 595 × 103 m 34 Watch your units, conversion factors are needed! 1-29-14 or × 1m 102 cm 1.6 × 103 m (2 sig. fig.) Chem 1A S2014 35 Chemical Symbols: To what we can’t see! What we observe… Ch t 2 Chapter 2 Atoms and Elements Chemical symbols (H2O) allow us to connect… 1-29-14 Chem 1A S2014 36 1-29-14 Chem 1A S2014 37 7 Where do we begin… The Periodic Table Why do we call it the “Periodic Table”? Because, “periodically”, we use it in chemistry… 1-29-14 Chem 1A S2014 38 1-29-14 Chem 1A S2014 The Periodic Table: The Modern Periodic Table 39 Metals and Nonmetals The modern organization of the periodic table came about as a result of the work of Dimitri Mendeleyev Characteristics: •Ordered elements by atomic mass •Repeating pattern of properties Metals •Elements with similar properties in the same column Periodic Law – when the elements are arranged in order of increasing atomic mass, certain sets of d fi i t i t i t f properties recur periodically. Patterns used to predict properties of undiscovered elements 1-29-14 Chem 1A S2014 40 1-29-14 Chem 1A S2014 41 8 The Periodic Table: Metaloids The modern periodic table is defined by: Groups (families) G (f ili ) (columns down) Periods (rows across) aka: Semiconductors 1-29-14 Chem 1A S2014 42 1-29-14 Chem 1A S2014 43 Chemical Symbols and Formula: Elements: H = hydrogen O = oxygen Tin is in group 4A (14) in the 5th period. C = carbon Molecules: H2 = hydrogen O2 = oxygen some of the names are not systematic! H2O = water Uh‐‐Oh! Uh this is confusing… Yes it is… Get over it Get over it and get used to it! CH4 = methane 1-29-14 Chem 1A S2014 44 1-29-14 Chem 1A S2014 45 9 How do I remember all of these things: To pass this class: You are required to develop d d l a working knowledge of 1: Memorize the common elements and their symbols: How many? As many as possible! How many? As many as possible! 2: Complete the worksheets provided on the web site. Do extra homework problems. 3: Make up flash cards and practice with your classmates, friends or family. Practice Chemical Nomenclature Chemistry is really: Chem ‐ is 1-29-14 Chem 1A S2014 Practice Practice 46 1-29-14 ‐ Chem 1A S2014 try 47 10
© Copyright 2026 Paperzz