Section 2.2 Solutions 1) Distance between points: π = β(6 β 3)2 + (8 β 4)2 π = β(3)2 + (4)2 π = β9 + 16 π = β25 1) Answer: distance = 5 3) Distance between points: π = β(4 β 2)2 + (β1 β (β5))2 π = β(2)2 + (4)2 π = β4 + 16 π = β20 = β4β5 3) Answer: distance = 2β5 5) Distance between points: π = β(4 β 7)2 + (3 β 3)2 π = β(β3)2 + (0)2 π = β9 + 0 π = β9 5) Answer: distance = 3 7) 3+6 4+8 9 12 , )=( , ) 2 2 2 2 Midpoint = ( 7) Answer Midpoint = (9/2, 6) or (4.5, 6) 9) 2+4 β5+(β1) 6 β6 , )=( , ) 2 2 2 2 Midpoint = ( Answer Midpoint = (3,-3) 11) 4+7 3+3) 11 6 , 2 ) = ( 2 , 2) 2 Midpoint = ( 11) Answer Midpoint = (11/2, 3) or (5.5,3) 8β4 13) π = 6β3 15) π = Answer: m = 4/3 β1β(β5) 4β2 2β3 β1 0 5β5 0 17) π = 7β7 = 19) π = 4β3 = 1 4 =2 Answer: m = 2 Answer: m = undefined Answer: m = 0 21) Plot the point (0,-5) then go up 2 and right 3 three times. points labeled (0,-5) (3,-3) (6,-1) (9,1) 23) Plot the point (0,0) then go up 2 and right 3 three times. 25) Plot the point (0,-2) then go up 3 and right 2 three times. 27) First solve for y 3x + 2y = 10 -3x -3x 2y = -3x + 10 2π¦ 2 = π¦= β3π₯ 2 β3 π₯ 2 + 10 2 + 5 (now plot point (0,5) and go down 3 right 2 three times) 29) First solve for y 2x + 3y = 0 3y = -2x π¦= β2 π₯ 3 (now plot point (0,0) and go down 2 right 3 three times) 31) x-intercept let y = 0 2x + 0 = 12 2x = 12 x=6 y-intercept let x = 0 2(0) + y = 12 y = 12 Answer: x-intercept (6,0) y-intercept (0,12) 33) x-intercept, let y = 0 4x + 2(0) = 15 4x = 15 x = 15/4 or 3.75 y-intercept, let x = 0 4(0) + 2y = 15 2y = 15 y = 15/2 or 7.5 15 Answer x-intercept ( 4 , 0) ππ(3.75,0) y-intercept (0, 15 ) ππ(0,3.5) 2 35) First clear fractions by multiplying by 6 1 2 6 β 2π₯ β6 β3π¦ = 6 β 2 6 π₯ 2 β 12 π¦ 3 = 12 3x β 4y = 12 x-intercept, let y = 0 3x β 4(0) = 12 3x = 12 x=4 y-intercept, let x = 0 3(0) β 4y = 12 -4y = 12 y = 12/-4 = - 3 Answer: x-intercept (4,0) y-intercept (0,-3) 37) First multiply by 3 to clear the fraction 2 3 3 β π₯ + 3 β 5π¦ = 3 β β2 2x + 15y = -6 x-intercept, let y = 0 2x + 15(0) = -6 2x = -6 x = -3 y-intercept, let x = 0 2(0) + 15y = -6 15y = -6 y = -6/15 y = -2/5 Answer: x-intercept (-3,0) y-intercept (0,-2/5) 39) m = 4 x1 = 5 y1=-2 Use formula y β y1 = m(x β x1) y β (-2) = 4(x β 5) y + 2 = 4x β 20 -2 -2 Answer: y = 4x β 22 41) m = 2 3 x1 = 6 y1=5 Use formula y β y1 = m(x β x1) yβ5= 2 3 yβ5= 2 π₯ 3 (x β 6) - 12 3 2 3 yβ5= π₯β4 +5 +5 2 Answer: y = 3 π₯+1 43) m = 5 x1 = 0 y1=-2 (hint the y-intercept is the point (0,-2)) Use formula y β y1 = m(x β x1) y β (-2) = 5(x β 0) y + 2 = 5x Answer y = 5x β 2 45) The m = 3 as the line y = 3x + 6 has a slope of m = 3. Our line is parallel, so it must have the same slope. m = 3 x1 = 4 y1=1 Use formula y β y1 = m(x β x1) y β 1 = 3(x β 4) y β 1 = 3x β 12 +1 +1 Answer: y = 3x β 11 4 9 47) The m = 4/9 as the line y = x +3 has a slope of m = 4/9. Our line is parallel, so it must have the same slope. m= 4 9 x1 = 0 y1=1 Use formula y β y1 = m(x β x1) yβ1= 4 9 yβ1= 4 π₯ 9 (x β 0) +1 +1 4 Answer: y = 9 π₯+1 3 49) The line y = 3x + 6 has a slope of m = 3, or you may think of it as m = 1. The slope of our line will be the reciprocal of this slope with the opposite sign. Our line will have a slope of m = m= β1 3 x1 = 4 y1=1 Use formula y β y1 = m(x β x1) yβ1= β1 3 yβ1= β1 π₯ 3 +1 (x β 4) 4 +3 +1 Answer: y = β1 7 π₯+3 3 (hint 4/3 + 1 = 4/3 + 3/3 = 7/3) β1 3 4 9 51) The line y = π₯ + 3 has a slope of m = 4/9. Our line is perpendicular so change the sign and find the reciprocal to find our slope. The slope of our line is m = β 9/4 m= β9 4 x1 = 0 y1=1 Use formula y β y1 = m(x β x1) yβ1= β9 (x 4 yβ1= β9 π₯ 4 +1 β 0) +1 Answer: y = β9 π₯+1 4 53) First I need to find the slope of the line that passes through (3,1) and (4,5) 5β1 4 π = 4β3 = 1 = 4 m = 4 x1 = 3 y1=1 Use formula y β y1 = m(x β x1) y β 1 = 4(x β 3) y β 1 = 4x β 12 +1 +1 Answer: y = 4x β 11 55) First I need to find the slope of the line that passes through (-4,5) and (-2,1) 1β5 π = β2β(β4) = β4 2 = β2 m = -2 x1 = -4 y1=5 Use formula y β y1 = m(x β x1) y β 5 = -2(x β (-4)) y β 5 = -2(x + 4) y β 5 = -2x β 8 +5 +5 Answer: y = -2x β 3
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