Simple Machines Worksheet A 1. The Ramseys are moving to a new town, so they have called in the ACME moving company to take care of their furniture. Debbie, one of the movers, slides the Ramseys’ 2200-N china cabinet up a 6.0-m-long ramp to the moving van, which stands 1.0-m off the ground. 2200N a) What is the ideal mechanical advantage of the incline? ௗ ݀ = 6݉ = ܣܯܫ ௗೠ 1m ݀௨௧ = 1݉ ܨ =? = ܣܯܫ ଵ ܨ௨௧ = 2200ܰ = ܣܯܫ6 b) If Debbie must exert a 500-N force to move the china cabinet up the ramp with a constant speed, what is the actual mechanical advantage of the ramp? ி ܨ = 500ܰ = ܣܯிೠ 2200 = ܣܯ 500 = ܣܯ4.4 c) What is the efficiency of the ramp? ெ ସ.ସ %݂݂݁ = ூெ × 100 = × 100 %݂݂݁ = 73% d) What is the force of friction on the ramp? (The force of friction is the difference in the force needed without friction, from IMA, and the actual force used on the real machine with friction) = ܣܯܫ6 , this is how much What force would I use Therefore, subtract ideal force you multiply your input force without friction from actual force used to get friction ி = ܣܯܫೠ 500ܰ − 366.7ܰ = 133.3ܰ = ܨ without friction. In ideal Machine 6 = ଶଶே 6= ܨ = 133.3ܰ ி ଶଶே ܨ = 366.7ܰ (without friction) 2. Jack and Jill went up the hill to fetch a pail of water. At the well, Jill used a force of 20.0N to turn a crank handle of radius 0.400m that rotated an axle of radius 0.100m, so she could raise a 60.0N bucket of water. a) What is the ideal mechanical advantage of the wheel? (Radii are proportional to distance) 0.4m ௗ ܨ ݀ = 0.4݉ = ܣܯܫௗ 0.1m ி = ܣܯܫ ݀௨௧ = 0.1݉ ܨ = 20ܰ ܨ௨௧ = 60ܰ ி ೠ .ସ .ଵ IMA = 4 b) What is the actual mechanical advantage of the wheel? ி = ܣܯிೠ = ܣܯଶே = 3 ே c) What is the efficiency of the wheel? ெ ଷ %݂݂݁ = ூெ × 100 = ସ × 100 %݂݂݁ = 75% ܨ௨௧ 4. A jackscrew with a handle 30.0 cm long is used to lift a car sitting on the jack. The car rises 2.0 cm for every full turn of the handle. What is the ideal mechanical advantage of the jack? 0.3 2 ௨௧ 0.02 2 0.3 ? 1.885 ௨௧ 60 ೠ . IMA = 94 . 5. Tom’s favorite pastime is fishing. a) How much work is required for Tom to reel in a 10.0-kg bluefish from the water’s surface to the deck of a fishing boat, 5.20 m above the water, if the reel of his fishing pole is 85.0% efficient? . . ? ೠ 100 85% 100 ௨௧ 5.2 10 ? ௨௧ 10 9.81 98.1 85% ଶ ೠ ೠ ೠ 100 6.00 10 b) If Tom supplies a force of 15 N to the reel’s crank handle, what is the actual mechanical advantage of the fishing pole? . ೠ 6.5 c) What is the ideal mechanical advantage of the fishing pole? 100 . 85% 100 7.7 6. Clyde, a stubborn 3500-N mule, refuses to walk into the barn, so Farmer MacDonald must drag him up a 5.0-m ramp to his stall, which stands 0.50-m above ground level. a) What is the ideal mechanical advantage of the ramp? 5 ೠ 0.5m ௨௧ 0.5 . ? ௨௧ 3500 10 3500N b) If Farmer MacDonald needs to exert a 450-N force on the mule to drag him up the ramp with a constant speed, what is the actual mechanical advantage of the ramp? 450 ೠ 7.8 c) What is the efficiency of the ramp? 100 . 100 78% SM 1. The efficiency of a squeaky pulley system is 73 %. The pulleys are used to raise a mass. What force is exerted on the machine if a rope is pulled 18.0 m in order to raise a 58 kg mass a height of 3.0 m? ݂݂݁ = 73% ݂݂݁ = ܨ =? ݂݂݁ = ݀ = 18.0݉ ௐೠ × 100 ிೠ ௗೠ 73% = ݉ = 58݇݃ ௐ ி ௗ × 100 (ହଽே)(ଷ) (ி )(ଵ଼) × 100 ݀௨௧ = 3.0݉ ܨ = 129.9ܰ ܨ = 1.3 × 10ଶ ܰ ݉ ܨ௨௧ = ݉݃ = ሺ58݇݃ሻ ቀ9.91 ଶ ቁ = 569ܰ ݏ SM 2. The ramp in this figure is 18 m long and 4.5 m high. a. What force parallel to the ramp (FA) is required to slide a 25 kg box at constant speed to the top of the ramp if friction is disregarded? ܨ∥ = ܨ ߠ݊݅ݏ݃݉ = ߠ݊݅ݏ ݉ = 25݇݃ ܨ∥ = (25݇݃)(9.81 ௦మ )sin(14.5 ) Must push against ݃ = 9.81 ௦మ ܨ∥ = 61.4ܰ 4.5 ߠ = ି݊݅ݏଵ ൬ ൰ = 14.5 18 b. What is the IMA of the ramp? ݀ = 18݉ = ܣܯܫௗ ௗ = ܣܯܫସ.ହ ೠ ଵ଼ ݀௨௧ = 4.5݉ = ܣܯܫ4 c. What are the real MA and the efficiency of the ramp if a parallel force (FA) of 75 N is actually required? ி ଶସହ.ଶହே = ܣܯிೠ = ହே = 3.27 = ܣܯ ܨ௨௧ = ݉݃ = ሺ25݇݃ሻ ቀ9.81 ௦మ ቁ = 245.25ܰ ܣܯ 3.27 × 100 = × 100 = 81.8% ܣܯܫ 4 SM 3. A person must move a large stone in her backyard. She gets a plank that is 3.50 m long to use as a lever and she wedges one end of the plank under the large stone. A smaller stone, 0.750 m from the large one, serves ݂݂݁ = as a pivot. The plank makes an angle of 20.0 o with the ground. When she pushes down on the end of the plank with a force of 210 N, the large stone begins to move. ܨ = 210ܰ ݀ = 2.75݉ ݀௨௧ = 0.75݉ You can use the lever arms as distances ܨ௨௧ =? ܹ ≥ ܹ௨௧ ܨ ݀ ≥ ܨ௨௧ ݀௨௧ ሺ210ܰሻሺ2.75݉ሻ = ሺܨ௨௧ ሻ(0.75݉) a. What upward force is being exerted against the large stone? ܨ௨௧ = 770ܰ b. What is the mechanical advantage of the lever? = ܣܯ ிೠ ி ܨ௨௧ = 7.70 × 10ଶ ܰ ே = ଶଵே = 3.67 SM 4. Why is it easier to loosen the lid from the top of a paint can with a long handled screwdriver than with a short-handled screwdriver? More Leverage: Longer handle means more input distance so there is more output force SM 5. You are attempting to move a large rock using a long lever. Is it more effective to place the lever’s axis of rotation nearer to your hands or nearer to the rock? Explain. It is more effective to put the lever’s axis (fulcrum) nearer the rock so that your input distance is greater than output distance thereby making the output force bigger than the input force. SM 6. A pulley system lifts a 1345 N weight a distance of 0.975 m. Paul pulls the rope a distance of 3.90 m, exerting a force of 375 N. a. What is the IMA of the system? ܨ௨௧ = 1345ܰ = ܣܯܫௗ = .ଽହ b. What is the MA? = ܣܯ ݀௨௧ = 0.975݉ ݀ = 3.90݉ ܨ = 375ܰ c. How efficient is the system? ௗ ଷ.ଽ ೠ = ܣܯܫ4 ிೠ ி = ଵଷସହே ଷହே = 3.587 ݂݂݁ = ூெ × 100 = ெ ଷ.ହ଼ ସ = ܣܯ3.59 × 100 = 89.7% SM 7. If you were to use a machine to increase the output force, what factor would have to be sacrificed? Give an example where this occurs. You have to sacrifice the distance the output force moves compared to the distance the input moves. SM 8. A leveling foot on an air track is a screw. It can be turned to move it into or out of the base of the air track to make the end go up or down. Suppose the leveling screw on a particular air track has 15 threads per cm. The screw has a knob of diameter 1.5 cm to make it easier to turn. 1ܿ݉ = ݑ15 ݐ ݂ ݏ݊݅ݐݑ݈ݒ݁ݎℎ݁ ݐℎ݀ܽ݁ݎ a. In one complete rotation of the screw, how far is the air track lifted? Therefore ଵ ௩௨௧ = ݀௨௧ ଵ ቀ ଵ ௨ ଵହ ௩௨௧௦ ቁ = 0.0667ܿ݉ ݑ b. What is the IMA of the screw? ݀ = ܿ݅ = ߨ݀ = ݁ܿ݊݁ݎ݂݁݉ݑܿݎሺ1.5ܿ݉ሻߨ = 4.71ܿ݉ = ܣܯܫ ௗ = ସ.ଵ = 70.69 = ܣܯܫ70.7 c. If a force of 0.50 N is necessary to rotate the knob to lift the air track, what is the weight of the end of the air track lifted, assuming the screw is 80% efficient? Weight = output force Need to know MA ݂݂݁ = 80% ܨ = 0.50ܰ ௗೠ . ݂݂݁ = ூெ × 100 ெ ெ 80% = . × 100 = ܣܯ56.5 = ܣܯ ிೠ 56.5 = .ହே ܨ௨௧ = 28.3ܰ ிೠ ி
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