8th Grade
Mathematics
Unit: 05 Lesson: 02
Mix-It Madness (pp. 1 of 2)
Solve each equation by selecting a response from Table B and writing it in the appropriate place in
Table A for each equation below. After selecting a response from Table B, “X” it out. Not all the
responses in Table B will be used.
Table A
Original
Equation
Problem 1
x
+ 7 = 10
3
Problem 2
Problem 3
Problem 4
3x + 7 = 19
3x – 7 = 17
3x + 7 = 2x – 7
Step 1 for
Solving Equation
Simplified Equation
after Step 1
Step 2 for
Solving Equation
Solution
Table B
x + 7 = −7
3x = −14
add 7 to both sides
of the = sign
x = ( 14)
x
=3
3
divide both sides of
the = sign by 3
3x = 12
add (− 2x) to both
sides of the = sign
3x + 7 = −7
subtract 7 from both
sides of the = sign
divide both sides of
the = sign by 3
3x = 24
multiply both sides
of the = sign by 3
x=8
x
= 17
3
subtract 7 from both
sides of the = sign
x = 14
x=4
x=9
subtract 7 from both
sides of the = sign
–
© 2010, TESCCC
08/01/10
8th Grade
Mathematics
Unit: 05 Lesson: 02
Mix-It Madness (pp. 2 of 2)
In each column circle the equation that is equivalent to the original equation.
Original Equation 1
Original Equation 2
Original Equation 3
2x + 6 = 20
5y + 4 = 19
25 = 3n – 2
A.
2x – 6 = 20
A.
5y = 23
A.
3n – 2 = 25
B.
2x + 6 = 20 – 6
B.
5y = 15
B.
3n + 2 = 25 + 2
C.
2x + 6 = 20 + 6
C.
9y = 19
C.
3n – 2 + 2 = 25
D.
2x + 6 – 6 = 20 – 6
D.
5y = 19
D.
3n – 2 = 25 – 2
Original Equation 5
Original Equation 4
f
 2 = (  16)
4
55 = 7w – 8
A.
7w = 63
A.
B.
7w = 47
B.
C.
(−w) = 55
D.
(−15w) = 55
© 2010, TESCCC
Original Equation 6
f
= (  18)
4
4m – 3 = 2m + 6
A.
4m – 3 = 6
f
 2 = (  16)  2
4
B.
2m – 3 + 3 = 6 + 3
C.
f
 2 + 2 = (  16) + 2
4
C.
4m – 3 + 3 = 6 + 3
D.
f
 2 = (  16) + 2
4
D.
2m – 3 = 6 + 3
08/01/10
8th Grade
Mathematics
Unit: 05 Lesson: 02
Mix-It Madness (pp. 1 of 2) KEY
Solve each equation by selecting a response from Table B and writing it in the appropriate place in
Table A for each equation below. After selecting a response from Table B, “X” it out. Not all the
responses in Table B will be used.
Table A
Original
Equation
Problem 1
x
+ 7 = 10
3
Problem 2
Problem 3
Problem 4
3x + 7 = 19
3x – 7 = 17
3x + 7 = 2x – 7
Step 1 for
Solving Equation
subtract 7 from
both sides of the
= sign
subtract 7 from
both sides of the
= sign
add 7 to both
sides of the =
sign
add (−2x) to
both sides of the
= sign
Simplified Equation
after Step 1
x
=3
3
3x= 12
3x = 24
x + 7 = (−7)
Step 2 for
Solving Equation
multiply both
sides of the =
sign by 3
Solution
divide both sides divide both sides
of the = sign by
of the = sign by
3
3
x=9
x=4
subtract 7 from
both sides of the
= sign
x = (−14)
x=8
Table B
subtract 7 from both
sides of the = sign
x + 7 = −7
3x = −14
add 7 to both sides
of the = sign
x = (−14)
x
=3
3
divide both sides of
the = sign by 3
3x= 12
add (– 2x) to both
sides of the = sign
3x + 7 = −7
subtract 7 from both
sides of the = sign
divide both sides of
the = sign by 3
3x = 24
multiply both sides
of the = sign by 3
x=8
x
= 17
3
subtract 7 from both
sides of the = sign
x = 14
x=4
x=9
© 2010, TESCCC
08/01/10
8th Grade
Mathematics
Unit: 05 Lesson: 02
Mix-It Madness (pp. 2 of 2) KEY
In each column circle the equation that is equivalent to the original equation.
Original Equation 1
Original Equation 2
Original Equation 3
2x + 6 = 20
5y + 4 = 19
25 = 3n – 2
A.
2x – 6 = 20
A.
5y = 23
A.
3n – 2 = 25
B.
2x + 6 = 20 – 6
B.
5y = 15
B.
3n + 2 = 25 + 2
C.
2x + 6 = 20 + 6
C.
9y = 19
C.
3n – 2 + 2 = 25
D.
2x + 6 – 6 = 20 – 6
D.
5y = 19
D.
3n – 2 = 25 – 2
Original Equation 5
Original Equation 4
Original Equation 6
f
 2 =  16
4
55 = 7w – 8
4m – 3 = 2m + 6
A.
f
=  18
4
A.
4m – 3 = 6
B.
7w = 47
B.
f
 2 = (  16)  2
4
B.
2m – 3 + 3 = 6 + 3
C.
(−w) = 55
C.
C.
4m – 3 + 3 = 6 + 3
D.
(−15w) = 55
D.
D.
2m – 3 = 6 + 3
© 2010, TESCCC
2
+
6
1
7w = 63
=
2
+
2
f4
A.
︵ ︶
f
 2 = (  16) + 2
4
08/01/10