Section 1.4 Quadratic Equations Example 1: Solve the following

Section 1.4
Quadratic Equations
Definition:
An equation that can be written in the form
π‘Žπ‘₯ 2 + 𝑏π‘₯ + 𝑐 = 0
where a, b, and c are real numbers with a β‰  0, is quadratic equation. The given form is
called standard form.
1. Solving by Factoring:
To solve a quadratic equation by factoring, rewrite the equation, if necessary, so that one
side is equal to 0 and use the Zero-Product Property.
Zero-Product Property:
π‘Žπ‘ = 0 if and only if π‘Ž = 0 or 𝑏 = 0.
Example 1: Solve the following equations by factoring.
a) π‘₯ 2 βˆ’ 3π‘₯ = βˆ’2
b) π‘₯ 2 + 3π‘₯ = 18
c) 4π‘₯ 2 βˆ’ 4π‘₯ = βˆ’1
Section 1.4 Quadratic Equations
d) 6π‘₯ 2 + 7π‘₯ = 3
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Square root Property:
If π‘₯ 2 = π‘˜, then π‘₯ = βˆšπ‘˜ or π‘₯ = βˆ’βˆšπ‘˜
Example 2: Solve each quadratic equation.
a) π‘₯ 2 = 17
c) (π‘₯ βˆ’ 4)2 = 1
b) 49π‘₯ 2 + 36 = 0
d) (2π‘₯ βˆ’ 1)2 = 12
2. Solving by Completing the Square:
To solve π‘Žπ‘₯ 2 + 𝑏π‘₯ + 𝑐 = 0 with a β‰  0, by completing the square, use these steps.
Step 1 If a β‰  1, divide both sides of the equation by a.
Step 2 Rewrite the equation so that the constant term is alone on one side of the equality
symbol.
Step 3 Take a half of the coefficient of π‘₯, and then square the result. Now add this square
to each side of the equation.
Step 4 Factor the resulting trinomial as a perfect square and combine like terms on the
other side.
Step 5 Use the square root property to complete the solution.
Example 3: Solve π‘₯ 2 βˆ’ 4π‘₯ βˆ’ 14 = 0 by completing the square.
Step 1
Step 2
Step 3
Step 4
Step 5
Section 1.4 Quadratic Equations
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Example 4: Solve 9π‘₯ 2 βˆ’ 12π‘₯ + 9 = 0 by completing the square.
3. Solving by the Quadratic Formula:
The solution of the quadratic equation π‘Žπ‘₯ 2 + 𝑏π‘₯ + 𝑐 = 0 with a β‰  0 are given by the
quadratic formula.
βˆ’π‘ ± βˆšπ‘ 2 βˆ’ 4π‘Žπ‘
π‘₯=
2π‘Ž
Example 5: Find all solutions of the following each quadratic equation:
a) π‘₯ 2 βˆ’ 4π‘₯ = βˆ’2
b) 2π‘₯ 2 = π‘₯ βˆ’ 4
Example 6: Solve for the specified variable. Use ± when taking square roots.
Section 1.4 Quadratic Equations
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a) A =
πœ‹π‘‘2
4
, for 𝑑
b) π‘Ÿπ‘‘ 2 βˆ’ 𝑠𝑑 = π‘˜ (π‘Ÿ β‰  0), for 𝑑
The quantity under the radical in the quadratic formula, 𝑏 2 βˆ’ 4π‘Žπ‘, is called the
discriminant.
βˆ’π‘ ± βˆšπ‘ 2 βˆ’ 4π‘Žπ‘
π‘₯=
2π‘Ž
Example 7: Determine the number of distinct solutions, and tell whether they are rational,
irrational, or nonreal complex numbers.
a) 5π‘₯ 2 + 2π‘₯ βˆ’ 4 = 0
b) π‘₯ 2 βˆ’ 10π‘₯ = βˆ’25
c) 2π‘₯ 2 βˆ’ π‘₯ + 1 = 0
Section 1.4 Quadratic Equations
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