CHEM 110 (Beamer)
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PRACTICE HOMEWORK 16 – CONVERSION FACTORS 5
RATE AND DENSITY AS CONVERSION FACTORS
General Information
 Do Date: Wednesday (2/17).

Yes. This is also the test date. Hopefully, you will have done all of the practice homework assignments in preparation for Exam 1.
 Do all of the Practice Homework assignments and bring them to class. Keep this in your class notebook.
Reading
 Class Notes: Notes-01
 Chapter 2.3 and Chapter 2.4. There are examples that might help.
 You may only use Appendices 1, 2, 3, and 4. You may not use google-searched conversion factors.
Part 1: Writing Conversion Factors

Write the conversion factor from the given information. Use unit abbreviations. Timing: 6 minutes, max (1 minute max, each).
Example 1)
The density of aluminum is 2.7 grams per cubic centimeter of aluminum.
1)
The density of water (H2O) is 1.00 g/mL
2)
A faucet leaks at 0.500 milliliters (H2O) per minute.
3)
The speed of light through the vacuum of space is 3.00 × 108 meters per second.
4)
When ignited, 1.00 gram of propane gas (C3H8) produces 49.9 kilojoules (kJ) of energy.
2.7 g Al = 1 cm3 Al
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CHEM 110 (Beamer)
5)
A 747-passenger jet has a maximum (safe) speed of 920. kilometers per hour.
6)
At a given temperature, helium gas (He) has a density of 4.00 grams per cubic meter.
Part 2: Calculations

Perform the following calculations. You will need to be able to interpret the information for conversion factors.

You must use dimensional analysis format to show your work. (Units through each step; units in answer; apply sigfigs rules)

Note: Most of these questions are multi-step.
7)
The density of mercury (Hg) is 13.53 grams per milliliter at room temperature (treat this as an exact number). Calculate the volume of mercury (in
milliliters) of a 725.00-gram sample of mercury. Timing: 5 min, max (3 min, max, on an exam).
8)
A “fast” land turtle can run at a rate of 4.0 miles per hour (treat this as an exact number). Calculate the distance (in feet) that a turtle can run in 15.0
minutes. Assume the turtle is running at a constant speed for the entire time. (From Appendix 3: 1 mile =5280 feet). Timing: 7 min, max (5 min, max,
on an Exam).
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CHEM 110 (Beamer)
9)
Terminal velocity is the fastest rate that an object can fall due to wind resistance. The terminal velocity on Earth is approximately 200 kilometers per
hour. (Treat this value as an “exact” number.) At terminal velocity, how much time (in seconds) does an object require to fall a distance of 1.00
kilometer? Timing: 8 min max (6 min, max, on a similar question on an Exam).
Question 10
A college student in Santa Barbara has only $22.15 to his name when he graduates. At 6 AM, he finds out that he has a good job waiting for him in San Diego…
…if he can get there by 5 PM. His fuel gauge on his car is empty. He uses $18.00 to fill the tank and hopes he will get there. His car gets 32.5 miles per gallon
(treat this as a measured value). The average gas price in California (as of 2/6/16) is $2.41 per gallon (treat this as an exact number).
10a)
Calculate the distance (in kilometers) that the automobile can travel with $18.00 of gas in the car. Timing: 10 min (8 min on a similar question on
an Exam)
10b)
The distance to San Diego is 355 km. Will he make it to San Diego on $18.00 of gas? Yes or No? Timing: 10 seconds, max.
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CHEM 110 (Beamer)
Question 11
A rectangular piece of tin foil has a length of 10.00 cm and a width of 8.50 cm. The density of the tin foil is 7.31 grams per cubic centimeter (treat this values as
an exact number).
Question 11a)
A student obtains the mass of the piece of tin foil: 0.972 grams. Use the mass and the conversion factor for density of tin to determine the
volume of the piece of tin foil. Timing: 5 min, max (3 min, max, on an Exam)
Question 11b)
Write the equation for the volume of a rectangular box.
Question 11c)
You have calculated the volume of the sheet of tin foil, and you have the length and the width of the tin foil. Calculate the thickness (height)
of the piece of tin foil. You must show your work. Timing (6 min, max, 4 min on an Exam)
1)
1.00 g H2O = 1 mL H2O
8)
1.00 mi
2)
0.500 mL H2O = 1 min
9)
18.0 s
10a)
391 km
10b)
Yes. He also got the job and crashed at a friend’s place for the weekend.
11a)
0.133 cm3 Sn
8
3)
3.00 × 10 m = 1 s
4)
1.00 g C3H8 = 1 kJ
2
5)
920. km = 1 hr
OR 9.20 × 10 km = 1 hr
6)
4.00 g He = 1 m3 He
11b)
V=l × w × h
7)
53.585 mL Hg
11c)
1.56 × 10–3 cm
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