Electron Concentration n(x) Hole Concentration p(x) Electrical

EE143 F2010
Microfabrication
controls dopant
concentration
distribution
ND(x) and NA(x)
Lectre 21
Electron Concentration n(x)
Hole Concentration p(x)
Carrier Mobility
Fermi level Ef (x) , Electric Field
Electrical resistivity
PN Diode Characteristics
Sheet Resistance
MOS Capacitor
Professor N Cheung, U.C. Berkeley
MOS Transistor
1
EE143 F2010
Lectre 21
Electron and Hole Concentrations
for homogeneous semiconductor at thermal equilibrium
n: electron concentration (cm-3)
p : hole concentration (cm-3)
ND: donor concentration (cm-3)
NA: acceptor concentration (cm-3)
Assume completely
ionized to form ND+
and NA-
1) Charge neutrality condition:
ND + p = NA + n
2) Law of Mass Action
n p = ni2
:
Note: Carrier concentrations depend on
NET dopant concentration (ND - NA) !
Professor N Cheung, U.C. Berkeley
2
EE143 F2010
Lectre 21
How to find n, p when Na and Nd are known
n- p = Nd - Na (1)
pn = ni2
(2)
(i) If Nd -Na > 10 ni : n  Nd -Na
(ii) If Na - Nd > 10 ni : p  Na- Nd
* Either n or p will dominate for typical doping situations
Professor N Cheung, U.C. Berkeley
3
EE143 F2010
Lectre 21
The Fermi-Dirac Distribution (Fermi Function)
Probability of available states at energy E being occupied
f(E) = 1/ [ 1+ exp (E- Ef) / kT]
where Ef is the Fermi energy and k = Boltzmann constant=8.617  10-5 eV/K
f(E)
T=0K
0.5
E -Ef
Professor N Cheung, U.C. Berkeley
4
EE143 F2010
Properties of the Fermi-Dirac Distribution
Lectre 21
Probability
of electron state
at energy E
will be occupied
(1) f(E)  exp [- (E- Ef) / kT] for (E- Ef) > 3kT
•This approximation is called Boltzmann approximation
Note:
At 300K,
kT= 0.026eV
(2) Probability of available states at energy E NOT being occupied
1- f(E) = 1/ [ 1+ exp (Ef -E) / kT]
Professor N Cheung, U.C. Berkeley
5
EE143 F2010
Lectre 21
Fermi Energy (Ei) of Intrinsic Semiconductor
Ec
Eg /2
Ei
Eg /2
Ev
Professor N Cheung, U.C. Berkeley
6
EE143 F2010
Lectre 21
How to find Ef when n(or p) is known
Ec
q|F|
Ei
Ev
Ef
(n-type)
Ef
(p-type)
n = ni exp [(Ef - Ei)/kT]
Let qF  Ef - Ei
Note: Ef is not
very sensitive to
carrier
concentration
When n doubles,
Ef changes by
kT/q(ln 2) =
18mV
n = ni exp [qF /kT]
Professor N Cheung, U.C. Berkeley
7
EE143 F2010
Lectre 21
Dependence of Fermi Level with Doping Concentration
Ei  (EC+EV)/2 Middle of energy gap
When Si is undoped, Ef = Ei ; also n =p = ni
Professor N Cheung, U.C. Berkeley
8
EE143 F2010
Lectre 21
Work Function of Materials
METAL
Work function
= q
SEMICONDUCTOR
Eo
Ef
Vacuum
energy level
q
Ef
Eo
EC
EV
qM is determined
qS is determined
by the metal material
by the semiconductor material,
the dopant type,
and doping concentration
Professor N Cheung, U.C. Berkeley
9
EE143 F2010
Lectre 21
Work Function (qM) of MOS Gate Materials
Eo = vacuum energy level
Ef = Fermi level
EC = bottom of conduction band EV = top of conduction
band
q = 4.15eV (electron affinity)
Eo
Eo
Eo
qM
qM
Ef
Al = 4.1 eV
TiSi2 = 4.6 eV
q = 4.15eV
q = 4.15eV
EC
EC
Ef
0.56eV
Ei
Ei
0.56eV
EV
n+ poly-Si
Professor N Cheung, U.C. Berkeley
qM
0.56eV
Ef
0.56eV
EV
p+ poly-Si
10
EE143 F2010
Lectre 21
Work Function of doped Si substrate
F
* Depends on substrate concentration NB
Eo
Eo
qs
Ef
kT  N B 


ln 
q
 ni 
q = 4.15eV
EC
0.56eV
|q F|
Ei
EV
n-type Si
s (volts) =
4.15 +0.56 - |F|
Professor N Cheung, U.C. Berkeley
qs
Ef
0.56eV
q = 4.15eV
EC
0.56eV
Ei
0.56eV
|qF|
EV
p-type Si
s (volts) =
4.15 +0.56 + |F|
11
EE143 F2010
Lectre 21
The Fermi Energy at thermal equilibrium
At thermal equilibrium ( i.e., no external perturbation),
The Fermi Energy must be constant for all positions
Electron energy
Material A
Material B Material C Material D
EF
Position x
Professor N Cheung, U.C. Berkeley
12
EE143 F2010
Lectre 21
Electron Transfer during contact formation
System 1
Before
contact
formation
EF1
EF
System 2
Net
negative
charge
E
Professor N Cheung, U.C. Berkeley
EF2
e
EF2
+ Net
positive + charge + -
System 2
System 1
e
System 1
After
contact
formation
System 2
EF1
System 1
EF
-
System 2
+
+
+
E
13
EE143 F2010
Lectre 21
Applied Bias and Fermi Level
Fermi level of the side which has a relatively higher electric potential will have a
relatively lower electron energy ( Potential Energy = -q  electric potential.)
Only difference of the E 's at both sides are important, not the absolute position
of the Fermi levels.
q Va
E f1
Side 2
Side 1
+
Va > 0
-
Ef 2
E f1
q| Va |
Ef
2
Side 2
Side 1
+
Va < 0
-
Potential difference across depletion region
= Vbi - Va
Professor N Cheung, U.C. Berkeley
14
PN junctions
EE143 F2010
Lectre 21
Thermal Equilibrium
NA
- and
E-field
p
(x) is 0
ND+ and n
Depletion region
Quasi-neutral
region
--
++
--
++
p-Si
NA- only
(x) is -
(x) is 0
Quasi-neutral
region
n-Si
ND+ only
(x) is +
Complete Depletion Approximation used for charges inside depletion region
(x)  ND+(x) – NA-(x)
http://jas.eng.buffalo.edu/education/pn/pnformation2/pnformation2.html
Professor N Cheung, U.C. Berkeley
15
EE143 F2010
Lectre 21
Energy Band Diagram with E-field
Electron
Electron
Energy
Energy
E-field
+
2
1
Electric potential
(2) < (1)
+
EC
EV
2
x
E-field
-
1
Electric potential
(2) > (1)
EC
EV
x
Electron concentration n
q ( 2 ) / kT
n( 2 ) e
q[  ( 2 )   ( 1 )] / kT
 q(1) / kT  e
n(1) e
Professor N Cheung, U.C. Berkeley
16
EE143 F2010
Lectre 21
Electrostatics of Device Charges
1) Summation of all charges = 0 2  xd2 = 1  xd1
2) E-field =0 outside depletion regions
(x)
p-type
Semiconductor
- xd1
Professor N Cheung, U.C. Berkeley
x
xd2
- 
E=0
n-type
Semiconductor

x=0
E 0
E=0
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EE143 F2010
Lectre 21
3) Relationship between E-field and charge density (x)
d [ E(x)] /dx = (x) “Gauss Law”
4) Relationship between E-field and potential 
E(x) = - d(x)/dx
Professor N Cheung, U.C. Berkeley
18
EE143 F2010
Lectre 21
Example Analysis : n+/ p-Si junction
(x)
+Q'
p-Si
n+ Si
x
d
x
Depletion
region
Depletion region
-qNa
is very thin and is
approximated as
Emax =qNaxd/s
x=0
E (x)
3) 
Slope = qNa/s
xd
2)  E = 0
a thin sheet charge
1)  Q’ = qNaxd
Professor N Cheung, U.C. Berkeley
4)  Area under E-field curve
= voltage across depletion region
= qNaxd2/2s
19
EE143 F2010
Lectre 21
Superposition Principle
(x)
If 1(x)  E1(x) and V1(x)
2(x)  E2(x) and V2(x)
then
1(x) + 2(x)  E1(x) + E2(x) and
V1(x) + V2(x)
+qND
-xp
x
-qN- A
+xn
x=0
2(x)
1(x)
+qND
Q=+qNAxp
-xp
x
-qNA
+xn
x
Q=-qNAxp
x=0
Professor N Cheung, U.C. Berkeley
+
x=0
20
EE143 F2010
Lectre 21
1(x)
-xp
2(x)
+qND
Q=+qNAxp
x
+xn
-qNA
Q=-qNAxp
x=0
x=0
E1(x)
E2(x)
-xp
x
Slope =
- qNA/s
-
Professor N Cheung, U.C. Berkeley
x
x=0
+
+xn
x
-
x=0
Slope =
+ qND/s
21
EE143 F2010
Lectre 21
Sketch of E(x)
E(x) = E1(x)+ E2(x)
-xp
Slope = - qNA/s
x=0
+xn
x
Slope = + qND/s
-
Emax = - qNA xp /s
= - qND xn /s
Professor N Cheung, U.C. Berkeley
22
EE143 F2010
Lectre 21
The MOSFET
Metal-OxideSemiconductor
GATE LENGTH, L
GATE WIDTH, W
Field-Effect
Transistor
Gate
Source
OXIDE
THICKNESS, Tox
Drain
Substrate
Desired characteristics:
• High ON current
• Low OFF current
VT
CURRENT
• No current through the gate
to channel
• Current flowing between the
SOURCE and DRAIN is
controlled by the voltage on
the GATE electrode
|GATE VOLTAGE|
Professor N Cheung, U.C. Berkeley
EE143 F2010
Lectre 21
n-channel MOSFET
G
S
n
D
gate
oxide insulator
p
n
• Without a gate voltage applied, no current can flow
between the source and drain regions (2 pn diodes
back-to -back)
• Above a certain gate-to-source voltage (threshold
voltage VT), a conducting layer of mobile electrons is
formed at the Si surface beneath the oxide. These
electrons can carry current between the source and
drain.
Professor N Cheung, U.C. Berkeley
EE143 F2010
Lectre 21
The MOSFET as a Controlled Resistor
• When VDS is low, ID increases linearly with VDS
Inversion charge density Qi(x) = -Cox[ VGS – VT - V(x) ]
where Cox 
ox
/ tox.
ID
VGS = 2 V
VGS = 1 V > VT
VDS
IDS = 0 if VGS < VT
Professor N Cheung, U.C. Berkeley
EE143 F2010
Lectre 21
Pinch-off and Saturation
• As VDS increases, V(x) along channel increases.
Inversion-layer charge density Qn at the drain end of the channel is
reduced; therefore, ID increases slower than linearly with VDS.
• When VDS reaches VGS  VT, the channel is “pinched off” at the drain
end, and ID saturates (i.e. it does not increase with further increases
in VDS).
+
–
VGS
VDS > VGS - VT
G
D
S
n+
-
Professor N Cheung, U.C. Berkeley
VGS - VT
+
n+
pinch-off
region
I DSAT
W
VGS  VT 2
  nCox
2L
EE143 F2010
Professor N Cheung, U.C. Berkeley
Lectre 21
EE143 F2010
Lectre 21
NMOS versus PMOS
NMOS
Saturation
Cut-off
0 Vto
Triode
vGS
vDS Vto
PMOS
Triode
Saturation
vDS Vto
Professor N Cheung, U.C. Berkeley
Cut-off
Vto
0
vGS
EE143 F2010
Professor N Cheung, U.C. Berkeley
Lectre 21
EE143 F2010
Professor N Cheung, U.C. Berkeley
Lectre 21
EE143 F2010
Lectre 21
IDsat 
Not proportional to
(VGS-Vt)2
Professor N Cheung, U.C. Berkeley