Algebra 2 Review 3.4-3.7 Linear Equations Name: Date: Period: Section 3.4 Determine if the following equations are linear. If not, explain why not. 5 1 1. y x 7 2. x 9 y 24 3 2 4. x 12 5. 25 5xy Graph each equation using x- and y- intercepts. 7. 7 x 3 y 21 9. x 6 2 x4 y 3x 2 5 y 3. 6. 8. 5x 2 y 10 10. y 2 3 Write each equation in standard form using integers (no fractions or decimals allowed). 2 11. y 4 x 11 12. y x 25 3 1 5 2 13. 14. y 3 x 10 x 2y 4 6 5 Sections 3.5-3.6 Find the slope of each line. y 15. 5 –5 –4 –3 –2 y 16. 5 4 4 3 3 2 2 1 1 –1 –1 1 2 3 4 5 –5 x –4 –3 –2 –1 –1 –2 –2 –3 –3 –4 –4 –5 –5 y 17. –4 –3 –2 4 3 3 2 2 1 1 1 2 3 4 5 –5 x –4 –3 –2 –1 –1 –2 –2 –3 –3 –4 –4 –5 –5 Find the slope of the line that passes through each pair of points. 19. 1,2 and 4,3 20. 4,5 and 21. 4, 2 and 3 4 5 x 1 2 3 4 5 x 5 4 –1 –1 2 y 18. 5 –5 1 4,9 22. 3, 2 and 3, 4 4, 2 Find the value of r, given the slope of the line through each pair of points. 4 23. m ; r ,1 and 2, r 3 Graph each equation using slope and y-intercept. 2 24. y x6 3 25. Write an equation of a line with the given slope and point. 1 26. m 27. and 0, 3 4 28. m 0 and 2,1 29. Write an equation of a line with the given points. 30. 0,3 and 3,0 5,3 33. Write the equation of the line shown below. 34. y 35. 32. 2,3 31. –5 –4 –3 and –2 2 y 8 6x 2 and 6,4 3 no slope and 2,1 m 1,2 4,2 and y 5 5 4 4 3 3 2 2 1 1 –1 –1 1 2 3 4 5 x 1,5 2,5 and –5 –4 –3 –2 –1 –1 –2 –2 –3 –3 –4 –4 –5 –5 1 2 3 4 5 x 36. A jeweler’s salary was $28,500 in 2000 and $32,900 in 2004. The jeweler’s salary follows a linear growth pattern. Write an equation to model this growth (assume year 2000 is t=0). What will the jeweler’s salary be in 2005? Section 3.7 Determine if each line is parallel, perpendicular, or neither. 1 y x6 37. 38. 2 y 2 x 6 39. x9 y 2 40. 5 x 2 y 2 x y 2 x 3 y 18 4 x 6 y 24 Solve the problem. 41. Prove the triangle with vertices (3,5), (-2,6) and (1,3) is a right triangle. Algebra 2 Review 3.4-3.7 Write an equation of a line that is… 3 42. parallel to y x 5 and passes through the point 6,7 2 3 43. perpendicular to y x 5 and passes through the point 9, 12 2 44. vertical and passes through the point 5,10 45. horizontal and passes through the point 5,10 46. with an x-intercept of 4 and y-intercept of 3 Linear Equations ANSWER KEY 1. yes 2. yes 3. no, you can’t have a variable in the denominator, when you cross multiply you will get a product of variables 4. yes 5. no, you can’t have a product of variables 6. no, it is second degree ~ no exponent other than 1 for the variables Your graphs should include the following points for #7-10. 7. 3,0 9. vertical 11. and 0,7 8. 6,0 2,0 and 0, 5 10. horizontal 4 x y 11 12. 2 x 3 y 75 13. 3x 24 y 10 14. 2 x 5 y 35 15. m 1 4 16. m 17. m0 18. no slope 19. m 1 3 20. m 22. m0 21. and no slope and 0, 5 1 3 9 7 23. r 11 Your graphs should include the following points for #24-25. 24. 0,6 25. 0, 4 26. y 27. y 28. y 1 29. x 2 30. y x 3 31. x 1 32. y3 33. y and 3,4 1 x 3 4 34. 2 x 8 3 3 x 8 2 35. 36. ; $34,000 37. perpendicular 38. neither 39. perpendicular 40. parallel 41. Two of the slopes are opposite reciprocals; m = 1 and m = -1 and 1, 1 Algebra 2 Review 3.4-3.7 3 42. y x2 2 44. x 5 46. 3 y x3 4 Linear Equations 2 x 18 3 43. y 45. y 10
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