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Quantitative Aptitude
Direction (1-5): In this question two questions
numbered I and II are given. You have to solve
both the equations and find out the correct
option.
1.
I.
II.
A.
B.
C.
D.
E.
2.
A. x > y
B. x ≥ y
C. x < y
D. x ≤ y
E. x = y or the relationship cannot be
established
4.
x>y
x≥y
x<y
x≤y
x = y or the relationship cannot be
established
II.
A.
B.
C.
D.
E.
I.
5.
II.
A.
B.
C.
D.
E.
3.
I.
x>y
x≥y
x<y
x≤y
x = y or the relationship cannot be
established
x>y
x≥y
x<y
x≤y
x = y or the relationship cannot be
established
I.
II.
A.
B.
C.
D.
E.
I.
x>y
x≥y
x<y
x≤y
x = y or the relationship cannot be
established
II.
Direction (6-10): Study the following line graph carefully and answer the following questions.
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6.
7.
8.
9.
A. 6595
B. 2795
C. 1905
D. 2545
E. None of these
10. What is the ratio of accounts opened in
bank A in May and November together to
that of bank B in January and September
together?
A. 102: 11
B. 72: 15
C. 62: 15
D. 77: 102
E. None of these
What is the difference between total
number of accounts opened in bank A in
May, July and September together and the
no. of accounts opened in bank B in the
same months?
A. 3700
B. 32700
C. 32000
D. 3500
E. None of these
If number of accounts opened in Bank A in
January 2017 increases by 20% and that of
Bank B by 10% as compared to the
corresponding no. of accounts opened in
these Banks in January in 2016. Then find
the difference between no. of accounts
opened in bank A and bank B in January
2017.
A. 3100
B. 5000
C. 2500
D. 5100
E. None of these
The number of accounts opened in Bank B
in October is equal to average of accounts
opened in same bank in September and
November, also the accounts opened in
bank A in October is 1/2 of account opened
in bank B in the October month. Find the
number of account opened in bank A in
October.
A. 2400
B. 3500
C. 3700
D. 2000
E. None of these
The total number of accounts opened in
March 2017 increased by 40% as
compared to that in March 2016. If the
accounts opened in bank A in March 2017
are 25% more than that in 2016. Then find
the difference between number of accounts
opened in bank B in March 2017 and in
March 2016.
Direction (11-15): What approximate value
will come in place of the question mark (?) in
the following questions? (You are not expected
to calculate the exact value.)
11. 95.2 × 79.985 + 59.99%299.99 = ?2
A. 92
B. 88
C. 76
D. 68
E. 75
12. 18.92 × 20.024 + 299.9 × 5.99 = 13 × ?
A. 694
B. 964
C. 644
D. 786
E. 724
13.
A. 512
C. 774
E. 894
B. 664
D. 744
A. 2015
C. 1965
E. 1785
B. 1845
D. 1895
A. 42
C. 48
E. 53
B. 59
D. 33
14.
15.
Direction (16-20): Refer to the table and answer the questions that follow:
All costs provided are for 1 kg.
Cost price = production cost + cost of transportation + cost of handling
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26. In a 100m race A beats B by 10m and in a
300m race B beats C by 75m.If A beats C
by 10sec in the 100m race, then what is
the area of the circle in m 2 along which C
completes
1
round
in
100
sec?
(approximate value)
A. 8400
B. 8401
C. 8433
D. 8440
E. 8460
27. The denominator of an irreducible fraction
is greater than the numerator by 3. If we
reduce the numerator of the reciprocal
fraction by 4 and subtract the given
fraction from the resulting one, we get
7/40. Find the sum of numerator and
denominator of original fraction?
A. 13
B. 15
C. 12
D. 17
E. 10
28. A can do a piece of work in 18 days and B
can do the same work in 12 days. A and B
starts the work together but after 3 days B
leave the job and C join with A. A and C
complete the remaining works in 3 days. If
for complete work Rs 24000 has been
given, then what amount is received by C?
A. Rs 12000
B. Rs 9000
C. Rs 10000
D. Rs 8000
E. None of these
29. A shopkeeper marked his selling price of
goods at 50% above the cost price. He sells
half the stock at this price, one –third of his
remaining stock at a discount of 25% on
the marked price and rest on discount of
20% on marked price. Find the gain
percent all together.
A. 35.63%
B. 32.25%
C. 32.35%
D. 33.75%
E. None of these
30. A black container contains a mixture of two
pulses X and Y in the ratio 10:7 when 8.5
grams of mixture are drawn off and then
the container is filled with Y, the ratio of X
and Y becomes 10:9. How many grams of
pulse X was contained by the container
initially?
A. 47.5 grams
B. 63 grams
C. 44.5 grams
D. 42.5 grams
E. 42 grams
31. Radhika has two daughters by name Rinku
and Sindhu.The ratio of the age of Radhika
and Rinku is 3:1 and that of Rinku and
Sindhu is 8:5. Given that Rinku is six years
elder to Sindhu.Find the ratio of their ages
after 12 years.
16. Find the profit/loss% on selling sugar if the
cost of transportation is half of the cost of
transportation of barley.
A. 6.54%
B. 7.14%
C. 6.67%
D. 7.78%
E. None of these
17. Find the cost of transportation of milk
powder if its selling price is Rs. 38 per kg.
A. Rs. 3
B. Rs. 3.5
C. Rs. 4
D. Rs. 6
E. Rs. 5
18. Assuming the cost of handling barley and
lentils to be Rs. 0, find the difference in the
selling price of barley and lentil if they are
sold at the same profit%.
A. Rs. 7.67
B. Rs. 9.33
C. Rs. 10.23
D. Rs. 6.67
E. Rs. 11.87
19. Find the cost of transportation of wheat per
kg if the selling price of a quintal of wheat
is Rs. 2200.
A. Rs. 3
B. Rs. 2
C. Rs. 5
D. Rs. 4
E. None of these
20. Selling lentils at Rs. 90 per kg, a profit% of
20% is obtained. Cost of handling being
variable, find the value by which cost of
handling should be reduced such that profit
made is 25%.
A. Rs. 4
B. Rs. 3
C. Rs. 6
D. Rs. 7
E. None of these
Direction (21-25): What will come in place of
the question mark (?) in the following number
series?
21. 13, 14, 46, 289, (?), 4438, 12214
A. 1413
B. 735
C. 1028
D. 1313
E. 1333
22. 25, 14, 16, 26.5, (?), 143.5, 434.5
A. 35.5
B. 56
C. 17.5
D. 71.5
E. 72
23. 17, 68, 289, (?), 6177.375, 30.886.875
A. 1445
B. 1372.75
C. 1589.5
D. 1517.25
E. 1300.5
24. 8226, (?), 268, 63, 18, 7, 6
A. 1371
B. 1365
C. 1385
D. 1350
E. 1375
25. 5, 6, 16, 57, 244?
A. 1245
B. 1125
C. 1260
D. 648
E. None of these
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A. 29:15:12
B. 30:14:10
C. 29:14:11
D. 30:14:11
E. 30:13:11
32. A, B enter a partnership investing amounts
in the ratio 2 : 3 initially. After 5 months, A
withdraws Rs. 2400 while B increases his
investment by 20%. Then after a few
months, C invests 150% of A’s initial
investment. If the ratio of profits at the end
of a year of A, C is 58 : 45 and B, C is 67 :
25. Find the initial investment made by B.
A. Rs. 7200
B. Rs. 8800
C. Rs. 12800
D. Rs. 10800
E. Rs. 9600
33. A certain amount of money was partly
invested in plan A at 10% p.a compound
interest for 2 years and partly in plan B at
12% p.a. simple interest for 3 years. If the
interest earned is same from the both the
plAns. Find the money which was invested
in plan A if the amount invested in plan B
was Rs. 1540.
A. Rs. 2160
B. Rs. 1980
C. Rs. 2440
D. Rs. 3120
E. None of these
34. If a 4 digit number is formed with digits 1,
2, 3 and 5. What is the probability that
the number is divisible by 25, if repetition
of digits is not allowed?
A. 1/12
B. 1/4
C. 1/6
D. 1/2
E. None of these
35. An inverted right circular cone has a radius
of 12 cm. This cone is partly filled with a
liquid which is dripping from a hole in the
tip at a rate of 4/3 cm3/hour. The level of
liquid is 4 cm from the top and surface area
of liquid is 64π cm2. How long will it take
the cone to completely empty?
A. 512π hr.
B. 256 hr.
C. 128π hr.
D. 120π hr.
E. None of these
SOLUTIONS
1. Ans. E
I.
Now divide by coefficient of y2,
Now after changing the sign we get
Now after changing the sign we get
II.
x≥y
3. Ans. E
Now after changing the sign we get
The relationship cannot be established
2. Ans. B
I.
II.
II.
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B = 45 + 65 + 72 = 182
∴ Required difference = 182 – 145 = 37
Hence, 3700 is the difference between total
number of accounts opened in bank A in May, July
and September together and the no. of accounts
opened in bank B in the same months.
The relationship cannot be established
4. Ans. E
7. Ans. D
Number of accounts opened in bank A in January
2016 = 7000
There is an increase of 20% in January 2017 =
1400
⇒ Number of accounts opened in bank A in
January 2017 = 8400
Number of accounts opened in bank B in January
2016 = 3000
There is an increase of 10% in January 2017 =
300
⇒ Number of accounts opened in bank B in
January 2017 = 3300
∴ Required difference = 8400 – 3300 = 5100
Hence, 5100 is the difference between no. of
accounts opened in bank A and bank B in January
2017.
I.
II.
8. Ans. C
The number of accounts opened in Bank B in
October is equal to average of accounts opened of
same bank in September and November
⇒Average of accounts opened in bank B in
October = (72 + 76)/2 = 74
The accounts opened in bank A in October is 1/2
of account opened in bank B in the October
month
No of accounts opened in bank A in October
= 1/2 × 74 = 37
Hence, the number of accounts opened in bank A
in October is 3700
The relationship cannot be established
5. Ans. A
I.
Now after changing the sign we get x = 39, 2
II.
9. Ans. B
Total accounts opened in March 2016 = 8500 +
3800 = 12300
⇒ Total accounts opened in March 2017 = 12300
+ 4920 = 17220
Accounts opened in bank A in March 2016 = 8500
⇒ Accounts opened in bank A in March 2017 =
8500 + 2125 = 10625
∴ Accounts opened in bank B in March 2017 =
17220 – 10625 = 6595
∴ Required difference = 6595 – 3800 = 2795
Now after changing the sign we get
6. Ans. A
Number of accounts opened in Bank A in May=62
Number of accounts opened in Bank A in July=48
Number of accounts opened in Bank A in
September = 35
⇒Total number of accounts opened in bank
A = 62 + 48 + 35 = 145
Number of accounts opened in Bank B in May=45
Number of accounts opened in Bank B in July=65
Number of accounts opened in Bank B in
September = 72
⇒Total number of accounts opened in bank
10. Ans. D
Number of accounts opened in bank A in May and
November together = 6200 + 1500 = 7700
Number of accounts opened in bank B in January
and September together = 3000 + 7200 = 10200
∴ Required ratio = 7700/10200 = 77/102 = 77 :
102
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16. Ans. B
From the table,
Cost of production of sugar = Rs. 20
Cost of handling of sugar = Rs. 3
Selling price of sugar = Rs. 30
Cost of transportation of barley = Rs. 10
Given, cost of transportation of sugar is half of the
cost of transportation of barley
Cost of transportation of sugar = Rs. 5
Cost price of sugar = 20 + 3 + 5 = Rs. 28
11. Ans. B
95.2 X 79.985+59.99%299.99= ?2
95 X 80+60*300=?2
12. Ans. A
⇒ Profit% = 7.14%
18.92×20.024+299.9×5.99=13×?
192 ×20+300×6=13×?
361×20+1800= 13×?
7220+1800= 13×?
17. Ans. C
From the table for milk powder,
Production cost = Rs. 33
Cost of handling = Rs. 3
Let the cost of transportation be ‘a’.
Total cost price = 33 + 3 + a = Rs. 36 + a
Loss% = 5%
Given, selling price = Rs. 38
13. Ans. D
⇒ a – 2 = 1.8 + 0.05a
⇒0.95a = 3.8
⇒ a = Rs. 4
18. Ans. D
From the table,
Production cost of barley = Rs. 50
Transportation cost of barley = Rs. 10
Given, handling cost is Rs. 0.
Total cost price of barley = 50 + 10 = Rs. 60
Selling price of Barley = Rs. 70
14. Ans. C
Profit %
From the table,
Production cost of lentils = Rs. 60
Transportation cost of lentils = Rs. 5
Handling cost is Rs. 0
Total cost price = Rs.65
Let the selling price be ‘a’.
Given, profit% is same
(a-65)*100/70 =50/3
⇒ 6a – 390= 70
⇒ a = 460/6 = Rs. 76.66
Difference between the selling price = Rs. 6.67
15. Ans. E
19. Ans. A
From the table,
Production cost of wheat = Rs. 12
Let the transportation cost be ‘b’.
Handling cost of wheat = Rs. 5
Given, selling price of a quintal of wheat is Rs.
2200
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∴ Selling price of 1kg of wheat
= 2200/100 = Rs. 22
Total cost price = 12 + 5 + b = 17 + b
Profit% = 10%
23. Ans. E
The pattern of given series is:
→ 17,
→ 68 = 17 × 4,
→ 289 = 68 × 4.25,
→ (?) = 489 × 4.5,
→ (?) = 1300.5
→ 6177.375 = 1300.5 × 4.75,
→ 30,886.875 = 6177.375 × 5,
Thus, the missing number is 1300.5
⇒ 50 – 10b = 17 + b
⇒ 11b = 33
⇒b=3
20. Ans. B
From the table,
Production cost of lentils = Rs. 60
Transportation cost of lentils = Rs. 5
Let the handling cost be ‘a’.
Total cost price = 65 + a
Given, selling price = Rs. 90 and profit% is 20%
24. Ans. B
The pattern of given series is:
→ 8226,
→ (?) = 8226 ÷ 6 - 6,
→ (?) = 1365
→ 268 = 1365 ÷ 5 – 5,
→ 63 = 268 ÷ 4 – 4,
→ 18 = 63 ÷ 3 -3,
→ 7 = 18 ÷ 2 -2
→ 6 = 7 ÷ 1 -1
Thus, the missing number is 1365
⇒ 125 – 5a = 65 + a
⇒ 60 = 6a
⇒ a = Rs. 10
Now, the profit% = 25%
Let the handling cost be ‘b’
Total cost price = 65 + b
25. Ans. A
⇒ 100 – 4b = 65 + b
⇒ b = Rs. 7
Reduced handling cost
= Rs. 10 – 7 = Rs. 3
21. Ans. D
26. Ans. B
A/B=100/90 also B/C=100/75 then A/C=40/27
So in a race of 40m A beats C by 13m
In a race of 100m A beats C by 32.5m
So C covers 32.5m in 10 sec. speed of
C=3.25m/sec
Perimeter of circle=3.25*100=325m
Area=3252/4π=8401(approximately)
The pattern of given series is:
→ 13,
→ 14 = 13 + 15,
→ 46 = 14 + 25,
→ 289 = 46 + 35,
→ (?) = 289 + 45,
→ (?) = 1313
→ 4438 = 1313 + 55,
→ 12214 = 4438 + 65,
Thus, the missing number is 1313
27. Ans. A
let numerator of original fraction is x then
denominator x+3
22. Ans. B
The pattern of given series is:
→ 25,
→ 14 = 25 × 0.5 + 1.5,
→ 16 = 14 × 1 + 2,
→ 26.5 = 16 × 1.5 + 2.5
→ (?) = 26.5 × 2 + 3
→ (?) = 56
→ 143.5 = 56 × 2.5 + 3.5
→ 434.5 = 143.5 × 3 + 4
Thus, the missing number is 56
Original fraction
x
x3
and its reciprocal
x3
x
According to question,
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30. Ans. A
Let the Initial quantity of pulse X and Y be 10x
and 7x respectively
When 8.5 gms of mixture are drawn, then
quantity of X in mixture left
= (10x - (10/17) × 8.5)
⇒ Quantity of X in mixture left = 10x – 5
Quantity of Y in mixture left = (7x – (7/17) × 8.5)
⇒ Quantity of Y in mixture left = 7x – (7/2)
According to the given information:
Numerator will be an Integer so, x = 5
Original fraction =
Sum = 5 + 8 = 13
x
5
5
=

x3 53 8
⇒90x – 45 =70x – 35 + 85
⇒90x – 70x = 45 + 85 – 35
⇒20x = 130 – 35
⇒20x = 95
⇒x = 95/20= 4.75
 10x = 10 × 4.75 = 47.5 grams
Hence, 47.5 grams of pulse X was contained by
the container initially.
28. Ans. C
A do the work for 3 days + 3 days = 6 days, B
work for 3 days and C work for 3 days.
31. Ans. D
The ratio of the ages of Radhika and Rinku is 3:1.
Let their ages be 3x and x respectively – (1).
The ratio of ages of Rinku and Sindhu is 8:5.
Let their ages be 8y and 5y.
Given that Rinku is 6 years elder to Sindhu.
Three days’ work of
C=
Ratio of share
 8y - 5y = 6 ⇒ y = 2.
Thus,the present ages of Rinku and Sindhu are 8
× 2 = 16 and 5 × 2 = 10 respectively.—(2)
From (1) and (2),we have x = 16.
Therefore,the age of Radhika is 3 × 16 = 48.
After 12 years,their ages would be 48 + 12 =
60,16 + 12 = 28 and 10 + 12 = 22 respectively.
So,the ratio is 60 : 28 : 22 or 30 : 14 :
11 (dividing throughout by 2).
(money divided according work done by them)
=12:9:15=4:3:5
Share of C
32. Ans. D
Given, A, B enter a partnership investing amounts
in the ratio 2 : 3.
Let the amounts be 2a and 3a respectively.
After 5 months, A withdraws Rs. 2400 while B
increases his investment by 20%.
∴ Investment of A for 7 months = 2a – 2400
Investment of B for 7 months = 3a + 20% of 3a =
3.6a
Given, C invests an amount 150% of A’s initial
investment.
∴C’s investment = 150% of 2a = 3a
Let the number of months for which C invested
the money in a year be b.
Total investments made by
29. Ans. D
Sells at marked price = x/2,
Sells at 25% discount = x/6
Sells at 20% discount = x/3
Profit =
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A = 2a × 5 + (2a – 2400) × 7 = 24a – 16800
Total investments made by
B = 3a × 5 + 3.6a × 7 = 40.2a
Total investments made by C = 3a × b = 3ab
Ratio of profits = Ratio of investments made
Given, ratio of profits at the end of a year of A, C
is 53 : 45 and B, C is 67 : 25.
(24a-16800)/3ab =58/45 and 40.2a/3ab =67/25
Solving these two equations we get, b = 5 months
and a = Rs. 3600
Initial investment of B = 3 × a = Rs. 10800
So the first two digits can be arranged in 2! ways.
Hence, required probability
35. Ans. C
Given, inverted right circular cone has a radius of
12 cm. This cone is partly filled with a liquid which
is dripping from a hole in the tip at a rate of 4/3
cm2/hour. The level of liquid is 4 cm from the top
and surface area is 64π cm2.
Surface area = πr2
∴ πr2 = 64π
⇒ r = 8 cm
Ratio of radius is equal to ratio of heights.
33. Ans. E
Let the amount invested in plan A be ‘a’.
For CI:
, CI = A – P
For SI: SI = (P × R × T)/100
Given, plan A : 10% p.a compound interest for 2
years
, where h1 is height of liquid level and
h2 is height of cone.
⇒ h2 = 1.5h1
⇒ h1 + 4 = 1.5h1
⇒ h1 = 8 cm
∴ h2 = 12 cm
Total volume of liquid inside the cone
⇒CI = a × 1.21 – a = 0.21a
Given, plan B : 12% p.a. simple interest for 3
years.
Amount invested = Rs. 1540
SI = (1540 × 3 × 12)/100
⇒SI = Rs. 554.40
Given, interest earned in both plans is the same.
∴0.21a = 554.40
⇒a = Rs. 2640
None of these is the correct answer.
⇒ Total volume of liquid inside the cone
Time in which the cone will be empty
34. Ans. A
Total number of four-digit numbers that can be
formed = 4! .
If the number is divisible by 25, then the last two
digits are 25.
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