Section 10.3 Multiplying and Simplifying Radical Expressions Product Rule π π ο If βπ and βπ are real numbers, then π π π βπ β βπ = βππ Simplifying Radical Expressions ο Step 1: Find the index, n, of the radical expression. ο Step 2: Rewrite the radicand as the product of two factors; one of which is the greatest perfect nth power factor. ο Step 3: Use the product rule and find the nth root of the perfect nth power. Exercises (Solution 1) Step 1: Identify indices Indices of β3 and β14 are 2. Step 2: Use product rule, if indices are same. β3 β β14 = β3 β 14 = β42 Step 3: Find the perfect nth power factor Since the index is 2, find the perfect square factor. 42 = 2 β 3 β 7. No square factor. Step 4: Simplifying radicals The radicand 42 does not include the perfect square factor. Therefore, β42 is simplified. (Solution 2) Step 1: Identify indices 3 3 Indices of β2 and β11 are 3. Step 2: Use product rule, if indices are same. 3 3 3 β2 β β11 = β2 β 11 = β22 Step 3: Find the perfect nth power factor Since the index is 3, find the perfect square factor. 22 = 2 β 11. No square factor. Step 4: Simplifying radicals The radicand 22 does not include the perfect cube factor. Therefore, β22 is simplified. (Solution 3) Step 1: Identify indices. Indices of β10π₯ and οΏ½3π¦ are 2. Step 2: Use product rule, if indices are same. β10π₯ β οΏ½3π¦ = οΏ½10π₯ β 3π¦ = οΏ½30π₯π¦ Step 3: Find the perfect nth power factor Since the index is 2, find the perfect square factor. 30π₯π¦ = 2 β 3 β 5 β π₯ β π¦. No square factor. Step 3: Simplifying radicals The radicand 30xy does not include the perfect square factor. Therefore, οΏ½30π₯π¦ is simplified. Cheon-Sig Lee Page 1 Section 10.3 Multiplying and Simplifying Radical Expressions (Solution 4) Step 1: Identify indices. The index is 2. Step 2: Find the perfect nth power factor. Since the index is 2, find the perfect square factor. 175 = 5 β 5 β 7 = 52 β 7 = 25 β 7. The perfect square factor is 25 because 52 = 25 Step 3: Simplifying radicals β175 = β25 β 7 = β25 β β7 = 5β7 (Solution 5) Step 1: Identify indices. The index is 2 Step 2: Find the perfect nth power factor. Since the index is 2, find the perfect square factor. 12π₯ = 2 β 2 β 3 β π₯ = 22 β 3 β π₯ = 4 β 3 β π₯. The perfect square factor is 4 because 22 = 4 Step 3: Simplifying radicals β12π₯ = β4 β 3π₯ = β4 β β3π₯ = 2β3π₯ (Solution 6) Step 1: Identify indices. The index is 3 Step 2: Find the perfect nth power factor. Since the index is 3, find the perfect cube factor. 32π₯π¦ 3 = 2 β 2 β 2 β 2 β 2 β π₯ β π¦ 3 = 23 β 22 β π₯ β π¦ 3 . So, β32π₯π¦ 3 = (β2)3 β 22 β π₯ β π¦ 3 = β8 β 4 β π₯ β π¦ 3 Thus, the perfect cube factor is β8 and π¦ 3 Step 3: Simplifying radicals 3 3 3 3 3 3 οΏ½β32π₯π¦ 3 = οΏ½β8 β 4 β π₯ β π¦ 3 = ββ8 β οΏ½π¦ 3 β β4π₯ = β2π¦ β4π₯ (Solution 7) Step 1: Identify index. The index is 2. Step 2: Find the perfect nth power factor. Since the index is 2, find the perfect square factor. π₯ 15 = π₯ 14+1 = π₯ 14 β π₯ The perfect square factor is π₯ 14 because π₯ 14 = (π₯ 7 )2 Step 3: Simplifying radicals 14 οΏ½π₯ 15 = οΏ½π₯ 14 β π₯ = οΏ½π₯ 14 β βπ₯ = π₯ 2 βπ₯ = π₯ 7 βπ₯ (Solution 8) Step 1: Identify index. The index is 2 Step 2: Find the perfect nth power factor. Since the index is 3, find the perfect cube factor. 32π₯ 16 π¦ 6 = 25 π₯ 16 π¦ 6 = 23+2 π₯ 15+1 π¦ 6 = 23 β 22 β π₯ 15 β π₯ β π¦ 6 = 8 β 4 β π₯ 15 β π₯ β π¦ 6 Perfect cube factors are 8, π₯ 15 , and π¦ 6 . Step 3: Simplifying radicals 3 3 οΏ½32π₯ 16 π¦ 6 = οΏ½8 β 4 β π₯ 15 β π₯ β π¦ 6 3 3 3 3 = β8 β οΏ½π₯ 15 β οΏ½π¦ 6 β β4π₯ 15 6 3 = 2 β π₯ 3 β π¦ 3 β β4π₯ 3 = 2π₯ 5 π¦ 2 β4π₯ Cheon-Sig Lee Page 2 Section 10.3 Multiplying and Simplifying Radical Expressions (Solution 9) Step 1: Multiply radicals Since indices are same, radicals can be multiplied. β15 β β6 = β15 β 6 = β90 Step 2: Find the perfect nth power factor. Since the index is 2, find the perfect square factor. 90 = 2 β 3 β 3 β 5 = 32 β 2 β 5 = 9 β 10 The perfect square factor is 9 because 32 = 9 Step 3: Simplify radicals β15 β β6 = β90 = β9 β 10 = β9 β β10 = 3β10 (Solution 10) Step 1: Multiply radicals Since indices are same, radicals can be multiplied. β2π₯ β οΏ½12π¦ = οΏ½2π₯ β 12π¦ = οΏ½24π₯π¦ Step 2: Find the perfect nth power factor. Since the index is 2, find the perfect square factor. 24π₯π¦ = 2 β 2 β 2 β 3 β π₯ β π¦ = 22 β 2 β 3π₯π¦ = 4 β 6π₯π¦ The perfect square factor is 4 because 22 = 4 Step 3: Simplify radicals β2π₯ β οΏ½12π¦ = οΏ½24π₯π¦ = οΏ½4 β 6π₯π¦ = β4 β οΏ½6π₯π¦ = 2οΏ½6π₯π¦ (Solution 11) Step 1: Multiply radicals Since indices are same, radicals can be multiplied. οΏ½27π₯π¦ β οΏ½9π₯π¦ 2 = οΏ½27π₯π¦ β 9π₯π¦ 2 = οΏ½243π₯ 2 π¦ 3 Step 2: Find the perfect nth power factor. Since the index is 2, find the perfect square factor. 243π₯ 2 π¦ 3 = 3 β 3 β 3 β 3 β 3 β π₯ 2 β π¦ 2+1 = 34 β 3 β π₯ 2 β π¦ 2 β π¦ = 81 β 3 β π₯ 2 β π¦ 2 β π¦ Perfect square factors are 81, π₯ 2 , and π¦ 2 because 34 = (32 )2 = (9)2 = 81 Step 3: Simplify radicals οΏ½243π₯ 2 π¦ 3 = οΏ½81 β 3 β π₯ 2 β π¦ 2 β π¦ = β81 β οΏ½π₯ 2 β οΏ½π¦ 2 β οΏ½3π¦ = 9π₯π¦οΏ½3π¦ (Solution 12) Step 1: Multiply radicals Since indices are same, radicals can be multiplied. 5β3 β 2β24 = 5 β 2 β β3 β β24 = 10β3 β 24 = 10β72 Step 2: Find the perfect nth power factor. Since the index is 2, find the perfect square factor. 72 = 2 β 2 β 2 β 3 β 3 = 2 β 3 β 2 β 3 β 2 = 62 β 2 = 36 β 2 Perfect square factors are 36 because 62 = 36 Step 3: Simplify radicals 5β3 β 2β24 = 10β72 = 10β36 β 2 = 10β36 β β2 = 10 β 6 β β2 = 60β2 Cheon-Sig Lee Page 3 Section 10.3 Multiplying and Simplifying Radical Expressions (Solution 13) Step 1: Multiply radicals Since indices are same, radicals can be multiplied. οΏ½6π₯ 6 β οΏ½12π₯ 5 = οΏ½6π₯ 6 β 12π₯ 5 = οΏ½72π₯ 11 Step 2: Find the perfect nth power factor. Since the index is 2, find the perfect square factor. 72π₯ 11 = 2 β 2 β 2 β 3 β 3 β π₯ 10+1 = 2 β 3 β 2 β 3 β 2 β π₯ 10 β π₯ = 6 β 6 β 2 β π₯ 10 β π₯ = 36 β π₯ 10 β 2π₯ Perfect square factors are 36 and π₯ 10 because 62 = 36 and (π₯ 5 )2 = π₯ 10 Step 3: Simplify radicals οΏ½6π₯ 6 β οΏ½12π₯ 5 = οΏ½72π₯ 11 = οΏ½36 β π₯ 10 β 2π₯ = β36 β οΏ½π₯ 10 β β2π₯ 10 = 6 β π₯ 2 β β2π₯ = 6π₯ 5 β2π₯ (Solution 14) Write the walking speed of a dinosaur whose leg length is 15feet. Step 1: Define variables, information, and the question. W(x) = the walking speed = ? x = the length of the leg = 15 feet. The question is finding the walking speed at 15 feet, another words evaluating W(15) Step 2: Substituting and evaluating. π(π₯) = 4β3π₯ π(15) = 4β3π₯ = 4β3 β 15 = 4β45 = 4β9 β 5 = 4 β β9 β β5 = 4 β 3 β β5 = 12β5 Cheon-Sig Lee Estimate the walking speed at 15 feet Page 4
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