Others
7
Simplifying
Expressions
7
Distribution
7
Exponents I Exponents II
7
7
7
10
10
10
10
Final
Jeopardy
Others (7)
1.
D
2.
Rita has a container with a liter of milk and is wondering how many fluid ounces of
milk are in the container. She knows that 1 gallon is about 3.785 liters, and there
are 128 fluid ounces in a gallon. She sets up the expression below to convert 1
liter to fluid ounces.
1
3.785
128
1
33.82 fluid ounces
Others (10)
1.
B
2.
B
D
Simplifying Expression (7)
1.
C
2.
A
Simplifying Expression (10)
Find the perimeter of the Shape.
8x + 38
Distributive (7)
Find the Perimeter of the Rectangle.
3x + 1
4x – 5
P = 2L + 2W
P = 2 (4x – 5) + 2 (3x + 1)
P = 8x – 10 + 6x + 2
P = 14x – 8
Distributive (10)
Find the Area of the Rectangle.
3x + 1
4x – 5
A=L*W
A = (4x – 5) (3x + 1)
A = (4x)(3x) + (4x)(1) + (-5)(3x) + (-5)(1)
A = 12x2 + 4x – 15x – 5
A = 12x2 – 11x – 5
Simplying Expression (7)
Simply:
(x3 –
9x + 8) – ( 5x2 – 2x – 4)
x3 – 9x + 8 – 5x2 + 2x + 4
3
x
–
2
5x
– 7x + 12
Exponent I (7)
Given the Rectangle has the
length of 4x3y2 and the width of
3x5y. Find the Area.
A= L*W
A = (4x3y2) (3x5y)
A = 12x8y3
Exponent I (10)
Simplify with no negative exponent(s).
 4 3 5 
 x y 
3

3
9x
4
y
3

2
3
 4  3*3 5*3 2 4*2 3*2
   x y (9) x y
3
64 9 15
192x
8 6

9

x y * 81x y  192xy  9
y
27
Exponent II (7)
Given the Area of the Rectangle is 10x5y8.
The length is 2x3y5. Find the width.
A=l*w
A
 w
l
5
8
10 x y
w
3 5
2x y
5x y  w
2
3
Exponent II (10)
 2x y
2
 3x
3
3

y 
5 3
2
3
2*3
5*3
2 x y
 2 3*2 3*2
3 x y
3
6
15
2 x y
 2 6 6
3 x y

x
6  ( 6)
0
15 6
y
3
2
2 *3
9
9
x y
y


8*9
72