14 NON-FOUNDATION Arithmetic and Geometric Sequences and their Summation Name : 14E Date : Mark : 14.3B Geometric Mean ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ ○ Key Concepts and Formulae If x, y and z are any three consecutive terms of a geometric sequence, then y = ± xz . 1. (a) Insert a positive geometric mean between 24 and 6. 1 2 (b) Insert a negative geometric mean between -18 and - . (c) Insert a geometric mean between 7 and 35, leave your answer in surd form. Solution (a) Let x be the positive geometric mean between 24 and 6. \ x = ( 24 )( 6 ) = ( 144 ) = ( 12 ) \ The required geometric mean is ( 12 ). 1 2 (b) Let x be the negative geometric mean between -18 and - . \ x = - (-18)Ê - 1 ˆ Ë 2¯ = - 9 = -3 \ The required geometric mean is -3. (c) Let x be the geometric mean between 7 and 35. \ x = ± 7(35) = ± 245 = ±7 5 \ The required geometric mean is 7 5 or -7 5 . 95 ○ ○ Number and Algebra 2. If the geometric mean between 25 and y is -10, find the value of y. Solution Q -10 is the geometric mean between 25 and y. \ -10 = - ( 25 )( y ) (-10)2 = (- 25y )2 100 = 25y y = ( 4 ) 3. (a) Insert two geometric means between 3 and 192. 4 and 36. 9 1 9 and - . (c) Insert four geometric means between 27 32 (b) Insert three geometric means between Solution (a) Let R1 be the common ratio of the geometric sequence formed. The geometric sequence formed is: 3, 3R1, ( 3R12 ), 192 Q The 4th term is also given by 3R1( \ 3 R1 ( 3 ) = 192 ( 3 ) = ( 64 ) R1 3 ) . R1 = ( 4 ) \ The two required geometric means are ( 12 ) and ( 48 ). (b) Let R2 be the common ratio of the geometric sequence formed. The geometric sequence formed is: 4 ,( 9 ), ( 2 4 R2 9 ), ( Q The 5th term is also given by ( \ 4 4 R 2 = 36 9 R2 96 4 R2 9 4 = 81 3 4 R2 9 4 4 R2 9 ), 36 ). 14 Arithmetic and Geometric Sequences and their Summation R2 = ( 3 ) or ( -3 ) When R2 = ( 3 ), the three required geometric means are ( When R2 = ( -3 ), the three required geometric means are ( - 4 3 4 3 ), ( 4 ) and ( 12 ). ), ( 4 ) and ( -12 ). (c) Let R3 be the common ratio of the geometric sequence formed. The geometric sequence formed is: 1 27 , 1 27 R3, 1 27 1 2 R3 , 27 3 R3 , 1 27 Q The 6th term is also given by \ 4 R3 , 1 27 9 32 5 R3 . 5 1 9 R3 = 27 32 R3 5 = - R3 = - 243 32 3 2 \ The four required geometric means are - 4. 1 3 1 1 , , - and . 16 18 12 8 If x - 6, x + 2 and -5x + 2 are in geometeric sequence, find the values of x. Solution Q x - 6, x + 2 and -5x + 2 are in geometric sequence. \ ( x+2 ) = ± ( x-6 )( -5x + 2 ) (x + 2)2 = [± (x - 6)(-5x + 2)]2 x 2 + 4x + 4 = -5x 2 + 32x - 12 6x 2 - 28x + 16 = 0 3x 2 - 14x + 8 = 0 (3x - 2)(x - 4) = 0 x = 2 or 4 3 97
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