Dr. Sangeeta Khanna Ph.D
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G:\Grand Test - VII Complete Inorg. Non-Med-Q.doc
CHEMISTRY COACHING CIRCLE
Dr. Sangeeta Khanna Ph.D
READ THE INSTRUCTIONS CAREFULLY
1.
2.
3.
The test is of 2 hours duration.
The maximum marks are 188.
This test consists of 60 questions.
Section – A (Single Answer) Negative Marking
This Section contains 21 multiple choice questions. Each question has four choices A), B), C) and
D) out of which ONLY ONE is correct.
21 × 3 = 63 Marks
1.
Distinguishing reagent between silver and lead salts is:
a. H2S gas
c. Na2CrO4
2.
b. Dil. HCl solution followed by heating
d. NH4Cl (solid) + (NH4)2CO3 solution
The temperature of blast furnace to produce iron from its ore Fe2O3 varies from 5000C at the top of the
furnace to about 19000C at the bottom of the furnace. Which of the reaction is not possible at the
lowest temperature ( ~ 5000C) is:
a. Fe2O3 + CO  2Fe3O4 + CO2
c. Fe2O3 + 3CO  2Fe + 3CO2
3.
b. Fe2O3 + CO  2FeO + CO2
d. CaO + SiO2  CaSiO3
Which of the following statements is not true with reference to the metallurgy of iron?
a. The ore is concentrated by magnetic separation technique
b. Before smelting, the concentrated ore is subjected to calcination
c. The flux used is SiO2
d. The temperature in the reduction zone of the blast furnace is in the range 520K – 975K.
4.
Larger number of oxidation states are exhibited by the actinoids than those by the lanthanoids, the
main reason being
a. more reactive nature of the actinoids than the lanthanoids
b. 4f orbitals are more diffused than the 5f orbitals
c. lesser energy difference between 5f and 6d than between 4f and 5d orbitals
d. more energy difference between 5f and 6d than between 4f and 5d orbitals
5.
Ammonia forms the complex ion [Cu(NH3)4]2+ with copper ions in alkaline solution but not in acidic
solution. The probable reason for this is :
a.
b.
c.
d.
6.
In acidic solution hydration protects Cu2+ ion
In acidic solution proton coordinates with ammonia molecules to form NH 4 ions and NH3
molecules are not available
In alkaline solutions insoluble Cu(OH)2 is precipitated which is soluble in excess of any alkali
Copper hydroxide is amphoteric substance
When tin is heated with excess of alkali solution, the product is :
a. SnO2
7.
b. Sn(OH)2
c. Sn(OH)4
d. SnO3-2
Among the element of IV a group, the oxidising power of tetravalent species decreases in the order :
a. Ge>Sn>Pb
b. Ge>Pb>Sn
Dr. Sangeeta Khanna Ph.D
c. Pb>Sn>Ge
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G:\Grand Test - VII Complete Inorg. Non-Med-Q.doc
d. Pb>Ge>Sn
CHEMISTRY COACHING CIRCLE
Dr. Sangeeta Khanna Ph.D
8.
Consider following statements about borax:
A:
Each boron atom has four B – O bonds
B:
Each boron atom has three B – O bonds
C: Two boron atoms have four B – O bonds while other two have three B – O bonds
D: Each boron atom has one – OH group
Select correct statement(s):
a. A, B
9.
b. B, C
c. C, D
d. A, C
An inorganic compound(A) shows the following reactions:
(i)
It is white solid and exists as dimmer; gives fumes of (B) with wet air.
(ii) It sublimes on 1800C and forms monomer if heated to 8000C.
(iii) Its aqueous solution turns blue litmus to red.
(iv) Addition of NH4OH and NaOH separately to a solution of (A) gives white precipitate which is
however soluble in excess of NaOH.
a. AlCl3
b. AlH3
c. SiCl4
d. BCl3
10. A red compound (A) is treated with conc. HNO3 to give a chocolate brown precipitate (B). The
precipitate is filtered and the filtrate is neutralized with NaOH. Addition of KI to the resulting solution
gives a yellow precipitate (C). The precipitate (B) on warming with conc. HNO 3 in the presence of
Mn(NO3)2 produces a pink-coloured solution due to the formation of (D). (A), (B), (C) and (D)
respectively are
a. HgI2; Hg(NO3)2, HgO, Hg(OH)2
c. Pb3O4; PbO; PbI2; Pb(MnO4)2
b. Pb3O4; PbO2; PbI2; Pb(MnO4)2
d. Pb3O4; PbO2; PbI2; Pb2MnO4
11. Which of the following complexes is not able to exhibit optical isomerism?
b. [Co (EDTA)]–
a. [Al (OX)3]3–
NH2
c. Trans – [Co (en)2 Cl. NH3]2+
Co(en)2
d. (en)2Co
NH2
12. Oxidation number of Cr in the following complex is: [O2 = Super oxide ion)
3+
(O2)
(H2O)6Cr
a. 3
O–O
Cr(H2O)6
b. 6
c. 4
d. 5
13. Which of the following have been arranged in increasing order of bond order as well as bond
dissociation energy:
a. O 22  O 2  O 2  O 2
b. O 22  O 2  O 2  O 2
c. O 2  O 2  O 22  O 2
d. O 2  O 22  O 2  O 2
Dr. Sangeeta Khanna Ph.D
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G:\Grand Test - VII Complete Inorg. Non-Med-Q.doc
CHEMISTRY COACHING CIRCLE
Dr. Sangeeta Khanna Ph.D
14. Match List I with List – II and select the correct answer using the codes given below the lists:
List – I
(Metals )
A. Zinc
1.
List – II
(Ore’s)
Azurite
B. Tin
2.
Carnallite
C. Copper
3.
Calamine
D. Magnesium
4.
Cassiterite
C
2
1
D
1
2
Codes:
a.
c.
A
3
3
B
4
4
b.
d.
A
4
4
B
1
3
C
3
2
D
2
1
15. If Phosphoric acid is allowed to react with sufficient quantity of NaOH, the product obtained is:
a. Na3PO4
b. NaH2PO4
c. Na2HPO4
d. NaHPO3
16. Cl2 gas is obtained by various reactions but not by
heat
heat
a. KMnO4 + conc. HCl 
b. KCl + K2Cr2O7 + conc. H2SO4 
heat
d. KCl + F2 
c. MnO2 + conc. HCl 
17. Pick out the correct statement.
a. Pure para hydrogen can be obtained by decreasing the temperature
b. Pure ortho hydrogen can be obtained by increasing the temperature
c. By decreasing the temperature, pure ortho hydrogen can be obtained
d. By increasing the temperature, pure para form of hydrogen can be obtained
18. TlI3 is black coloured sparingly soluble ionic compound. In its aqueous solution, it will give
a. Tl+ and I 3 ions
b. Tl3+ and I– ions
c. Tl+, I– ions and I2
d. Tl+ and I– ions
19. Which statement about Na2S4O6 is correct?
a. Oxidation state of all the atoms is 2.5
b. Two S atoms have oxidation state +2, while the other two have oxidation state +3.
c. Three S atoms have oxidation state +3, the fourth S atom has oxidation state +4.
d. Two S atoms have oxidation state + 5, while the other two S atoms have oxidation state zero.
20. Chlorine behaves as an oxidizing agent upon reaction with :
a. Fe2(SO4)3
b. O3
c. Na2S2O3
d. PbO2
21. A deliquescent white crystalline hydroxide X reacts with nitrate Y to form another hydroxide which
decomposes to give an insoluble brown layer of its oxide. X is a powerful castic and breaks down the
proteins of skin flesh X and Y are
a. NaOH, AgNO3
b. NaOH, Zn(NO3)2
Dr. Sangeeta Khanna Ph.D
c. NaOH, Al(NO3)3
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G:\Grand Test - VII Complete Inorg. Non-Med-Q.doc
d. Ca(OH)2, HgNO3
CHEMISTRY COACHING CIRCLE
Dr. Sangeeta Khanna Ph.D
SECTION – B (Assertion & Reason Type) Negative Marking
This Section contains 4 multiple choice questions. Each question has four choices A), B), C) and D)
out of which ONLY ONE is correct. (Mark only one choice.)
4 × 3 = 12 Marks
(a) If both assertion & reason are CORRECT & reason is the CORRECT explanation of the assertion.
(b) If both assertion & reason are CORRECT, but reason is NOT the CORRECT explanation of the assertion.
(c) If assertion is CORRECT, but reason is INCORRECT.
(d) If assertion is INCORRECT, but reason is CORRECT.
1.
Assertion (A): Baeyer’s process is used for refining of aluminium.
Reason (R) : Red bauxite contains iron oxide which is removed in Baeyer’s process.
a. (a)
2.
d. (d)
b. (b)
c. (c)
d. (d)
Assertion (A): Diborane on complete methylation gives B2H2(CH3)4.
Reason (R): Diborane structure shows two three-centre bonds, which cannot be replaced.
a. (a)
4.
c. (c)
Assertion (A): Nitrogen is unreactive at room temperature but becomes reactive at elevated
temperatures or in presence of a catalyst.
Reason (R): In nitrogen molecule there is extensive delocalization of electrons.
a. (a)
3.
b. (b)
b. (b)
c. (c)
d. (d)
Assertion (A): Li2CO3 decomposes on heating while Na2CO3 and K2CO3 don’t.
Reason (R): Lattice energy decides thermal stability of ionic compounds. Li2CO3 has a smaller lattice
energy as compared to Na2CO3 and K2CO3.
a. (a)
b. (b)
c. (c)
d. (d)
SECTION – C (Comprehension Type) Negative Marking
This Section contains 3 paragraphs. Each of these questions has four choices A), B), C) and D) out of
which ONLY ONE is correct. (Mark only one)
10 × 3 = 30 Marks
Paragraph -1
The zero (or 18) group of periodic table consists of six gaseous elements namely He, Ne, Ar, Kr, Xe,
and Rn. On account of their highly stable ns2p6 configuration in the valence shell, these gases have
little tendency to undergo any reaction, hence they were called ‘inert gases’. However, due to finding of
number of reaction of these elements, these are correctly called ‘noble gases’.
1.
The following noble gas not present in the atmosphere is
a. Ne
2.
b. Xe
c. Rn
Xe forms more number of compounds than the other noble gases
a. due to its lower ionization potential
c. due to its electronic structure
3.
d. Ar
b. due to its higher electron affinity
d. none of these
Charcoal at -100°C absorbs
a. Ne and Kr
b. He and Ne
Dr. Sangeeta Khanna Ph.D
c. He and Ar
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G:\Grand Test - VII Complete Inorg. Non-Med-Q.doc
d. Ar, Kr and Xe
CHEMISTRY COACHING CIRCLE
Dr. Sangeeta Khanna Ph.D
4.
Which of the following is not true for xenone fluoride.
a. These are good oxidizing agent
c. These are good fluorinating agent
b. They are readily hydrolysed
d. These are good reducing agent
Passage – 2
Boiled with
Na2CO3 and
water
Acidified with
HNO3
Soda extract
Mixture of two salts
Water
Solution
White ppt.
AgNO3 solution
White ppt.
(readily soluble
in NH4OH)
Solution
H2S
Black ppt.
Boiled with
NaOH solution
Deep blue
solution
Gas
BaCl2 water
HCl
Excess NH3
Nessler’s
reagent
KCN
Brown ppt.
(B) Colourless
(C)
Solution
CH3COOH + K4[Fe(CN)6]
Red brown ppt.
(A)
H2S
No ppt.
5.
The red brown precipiate formed in step (A) consists of
a. Hg2[Fe(CN)6]
6.
c. Cu2[Fe(CN)6]
d. Pb2[Fe(CN)6]
c. [Cu(CN)4]2–
d. [Cu(CN)4]3–
Colourless solution formed in step (B) contains
a. [Hg(CN)4]2–
7.
b. Cd2[Fe(CN)6]
b. [Cd(CN)4]2–
The ions present in the original mixture of salts are
a. NH 4 , Cu2+, Cl–, SO 24 
b. Cu2+, Cd2+, NO 3 , SO 24 
c. Hg2+, Cd2+, Cl–, SO 24 
d. Pb2+, Cu2+, NO 3 , Cl–
Passage – 3
Compared to the oxyacids of nitrogen, phosphorus presents a much more complicated picture
particularly due to the formation of condensed phosphates. Phosphorus forms oxyacids in oxidation
numbers, +1, +3, +4 and +5. The oxyacids with oxidation number +3 and +5 occur in meta-, pyro- and
ortho-forms. The three oxyacids, H3PO2, H3PO3 and H3PO4 are based on sp3 hybridized phosphorus
and may be conceived to be formed from hypophosphorous acid by stepwise replacement of H by
OH.
8.
H3PO2 + CuSO4  (X) ; a red precipitate. The compound (X) is
a. Cu
9.
b. Cu2O
c. Cu
d. Cu2H2
P4(white) + (A) (an alkaline solution)  (B) (reducing gas) + (C)
(C) + dil. H2SO4  (E) (ppt.) + (D) (oxyacid of P)
Compound (E) gives apple green colour in the flame. Thus, (A), (B), (C), (D) and (E) respectively are
a. Ba(OH)2 ; PH3 ; Ba(H2PO2)2 ; H3PO2 ; BaSO4
b. Ca(OH)2 ; P2H4 ; Ca(H2PO2)2 ; H3PO2 ; CaSO4
c. Ba(OH)2 ; PH3 ; Ba(H2PO3)3 ; H3PO3 ; BaSO4
d. Ba(OH)2 ; P2H4 ; Ba(H2PO2)2 ; H3PO3 ; BaSO4
Dr. Sangeeta Khanna Ph.D
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G:\Grand Test - VII Complete Inorg. Non-Med-Q.doc
CHEMISTRY COACHING CIRCLE
Dr. Sangeeta Khanna Ph.D
10. Which of the following represent the Pyrophosphoric acid
O
O
O
O
||
||
||
||
|
|
a. H  P  O  P  O  H
|
|
OH
O
OH
O
||
b. H  P  P  OH
OH OH
O
||
||
c. H  P  O  P  H
O
||
d. HO  P  O  P  OH
|
|
|
|
OH
H
OH
OH
SECTION – D (More than One Answer Type) Negative Marking
This Section contains 7 multiple choice questions. Each question has four choices A), B), C) and D)
out of which ONE OR MORE may be correct.
7 × 3 = 21 Marks
1.
Colour of KMnO4 is decolourised without evolution of any gas. The radical present may be :
a. SO 24 
2.
b. SO32 
Which of the following statements is correct ?
a. K2Cr2O7 oxidises HCl into CrO2Cl2
c. K2Cr2O7 oxidises C2H5OH into CH3COOH
3.
d. C2O 42
c. Sn2+
b. K2Cr2O7 oxidises KI into KIO3
d. I2 react with conc. HNO3 to form HIO3
The C – O bond length of carbon monoxide was found to increase on its coordination with Cr. This is a
consequence of
a. donation of an e– pair from filled d-orbital of Cr to vacant  orbital of CO
b.  bond formation between Cr and C
c. Due to donation of electron from CO to Cr
d. Due to decrease in bond order of metal and CO
4.
Which of the following ligand gives chelate complexes?
a. SCN–
5.
c. DMG
d. NH2NH2
Which of the following statement is correct:
a.
b.
c.
d.
6.
b. C 2 O 24 
CN– may act as complexing and reducing agent
In alkaline solution, cyanogen disproportionates into cyanide and cyanate ion
The cyanate ion is isoelectronic with CO2
CN– ion is pseudohalide ion
Which of the following statements is not correct?
a. Aluminium is among the best conductors of electricity
b. Physical properties of aluminium are characteristic of a true metal
c. Aluminium does not dissolve in aqueous sodium hydroxide solution
d. Aluminium reacts vigorously with hot conc. HNO3, oxides of nitrogen are evolved.
Dr. Sangeeta Khanna Ph.D
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G:\Grand Test - VII Complete Inorg. Non-Med-Q.doc
CHEMISTRY COACHING CIRCLE
Dr. Sangeeta Khanna Ph.D
7.
The strength of the trihalides as Lewis acid increases in the order
BF3  BCl 3  BBr 3
( weakest )
( strongest )
Which is correct of the following statements?
a.
b.
c.
d.
The tendency to form p - p bonding is maximum in BF3.
Boron halides exist as discrete molecule
Due to back bonding, the electron deficiency of boron atom is partly made up and hence Lewis
acid character of BF3 is lowest.
Except BF3, rest gives fumes in air due to hydrolysis.
SECTION – E (MATRIX MATCH) No negative Marking
This Section contains 4 questions. Each question has four choices (A, B, C and D) given in Column I and
five statements (p, q, r, and s) in Column II.
(8 × 4 = 32 Marks)
1.
Match the Column – I to Column – II
Column – I (reaction)
(A) HgS  Hg
(B) NaCl  Na
(C) Al2O3  Al
(D) ZnS  Zn
2.
3.
Column I with Column II.
Column I
(A) Caustic soda
(B) Hypo
(C) Microcosmic salt
(D) Aq. Na2CO3
(p)
(q)
(r)
(s)
Column II
Gives precipitate with Cu+2 salt
Shows Changes on strong heating
Violet colour of iodine disappears on reaction
Complex formation with AgNO3
(p)
(q)
(r)
(s)
Column II
Releases a gas/vapour on treatment with water
Gives flame colour
Reacts with nitrogen
Isostere of CO2
Column I with Column II.
(A)
(B)
(C)
(D)
4.
Column – II (method involved)
(p) Self reduction
(q) Electrolysis
(r) Roasting
(s) Carbon reduction
Column I
Hydrolith
Calcium cyanamide
Calcium carbide
Calcium metal
Column I with Column II.
(A)
(B)
(C)
(D)
Column I
[Cr (NH3)4Br (NO2)] Br
[Cr(en)2Cl2]+
[Cr (NH3)4ClBr]Br
[Co (NH3)6][Ni(CN)6]
Dr. Sangeeta Khanna Ph.D
Column II (Isomeric possible)
(p) Geometrical isomers
(q) Linkage isomers
(r) Ionisation isomers
(s) Optical isomers
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G:\Grand Test - VII Complete Inorg. Non-Med-Q.doc
CHEMISTRY COACHING CIRCLE
Dr. Sangeeta Khanna Ph.D
SECTION – F (Integer Type) No negative Marking.
This Section contains 10 questions. The answer to each question is a single digit integer. The
correct digit below the question number in the ORS is to be bubbled.
10 × 3 = 30 Marks
1.
The value of x in the complex HxCo(CO)4, on the basis of E.A.N. rule is (At. No. Co = 27):
2.
What will be the magnitude of charge in given complex. [Cr (OX )(en)(gly )]
3.
How many of the following compounds will not turn K2Cr2O7 green:
H2O2;
HNO2; K2MnO4;
HNO3; SO2;
SO3;
NO2;
N2O5;
HClO4; O3
How many of the following have one lone pair on central atom:
XeO3; XeO2F2;
XeF2; XeF4;
PCl3;
NO 2 ; N(CH3)3;
POCl3;
ClO 2 ;
IV
4.
ClF5
5.
How many of the following are dibasic acids:
H3PO2; H3PO3; H3PO4; H2SO4; H4P2O7; H2SO3; H4P2O5; H4P2O6; H2S2O7; H2SO5
6.
With which of the following HNO2 act as oxidising agent;
SnCl2; SO2; Urea; KI; H2O2; Bromine water; KMnO4; H2S; NaOH, SO3
7.
How many of the following metals can be extracted by self reduction method of their ore
Hg; Cu; Pb; Fe; Al; Mg; Na; Ag; Au; Mn
8.
How many of the following on heating give Nitrogen gas.
(NH4)2Cr2O7; NH4NO2; NH4NO3; Ba(N3)2; Urea; AlN; Mg3N2; HNO2; HNO3; (NH4Cl + NaNO2); Calcium
Ammonium nitrate
9.
How many of the following have sp3d hybridised atom.
KI3; ClO 4 ; ClF3; PCl5; SF4; XeO2F2; XeF2; ClF 4 ; I3 ; SbCl5
10. How many of the following metal sulphide are yellow.
PbS; FeS; ZnS; As2S3; SnS2; Bi2S3; MnS; Ag2S; HgS; CdS
Dr. Sangeeta Khanna Ph.D
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CHEMISTRY COACHING CIRCLE