Name: ___________________________________________ Date: _________________________ Copyright © 2015 www.studentpuzzles.com Primary Equivalent Fraction Strips β (Worksheet 1) Fill in the missing numerator or denominator that makes the equivalent fraction expression correct and a match to the shaded portion of the fraction strip. The first one is done for you. π π 1) 3) 5) 7) 9) 11) 13) 15) π π π π π π π π 1 2 1 3 2 4 = = 2 4 10 π π π π π π π π π π π π ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ π π π π π π π π π π π π ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ = 6 14 = 3 8) 5 2 12 4 12 = = 2 10 = 1 10) 6 2 π π π π π π π π π π π π π π π π π π π π ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ π π π π π π π π π π ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ 6) 12) 6 20 = 3 π π π π π π π π π π π π π π 14) 16) π π π π π π π π π π π π π π π π π π π π π π 1 2 π π π π 4) π π π π π π π π π π π π π π ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ π π π π π π π π π π ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ π π 2) π π π π π π = 2 3 = 2 6 = π π π π 4 6 = π π π π 6 8 = π π 1 3 = = π π π π 1 2 π π π π 1 3 = 8 4 1 2 4 2 2 2 Name: ___________________________________________ Date: _________________________ Copyright © 2015 www.studentpuzzles.com Key to Primary Equivalent Fraction Strips β (Worksheet 1) Fill in the missing numerator or denominator that makes the equivalent fraction expression correct and a match to the shaded portion of the fraction strip. The first one is done for you. π π 1) 3) 5) 7) 9) 11) 13) 15) π π π π π π π π 1 2 1 3 2 4 = = 2 6 6 14 4 10 π π π π π π π π π π π π ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ π π π π π π π π π π π π ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ = = 3 7 2 5 2 12 4 12 8) = 1 6 = 2 6 π π π π π π π π π π π π π π π π π π π π ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ π π π π π π π π π π ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ 2 10 = 6) 1 5 10) 12) 6 20 = 3 10 π π π π π π π π π π π π π π 14) 16) π π π π π π π π π π π π π π π π π π π π π π 1 2 π π π π 4) π π π π π π π π π π π π π π ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ π π π π π π π π π π ππ ππ ππ ππ ππ ππ ππ ππ ππ ππ π π 2) π π π π π π π π π π π π π π π π = 4 8 2 3 = 4 6 2 6 = 1 3 = 2 3 = 3 4 1 3 = 2 6 = 2 4 = 2 6 4 6 6 8 π π π π 1 2 π π π π 1 3
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