This resource is only intended for use by a single teacher. If you would like to share it, you can download an additional license for half price! Visit your “My Purchases” page to do this. Math problems involving percents can be tricky. They can be worded in many different ways, and getting set up to solve them is confusing. These questions appear on standardized tests very frequently. The foolproof key to success with percent problems is to rewrite the question as an equation! To write an equation, you must TRANSLATE from an English sentence into an equation (a mathematical sentence). Here’s how… When you see the word “what,” replace it with a variable like x because that is the unknown part we are looking for. When you see the word “is,” replace it with a “equals” sign. When you see the word “of,” replace it with multiplication. When you see a percent, replace it with its decimal form. When you see… Replace it with… “What” a variable (x) because this is the unknown part that we are trying to find “Is” = “Of” multiplication a percent its decimal form Example 1: 40 is 12 percent of what number? STEP 1: TRANSLATE / REPLACE Go on to the next page to continue. Example 1: 40 is 12 percent of what number? STEP 1: TRANSLATE / REPLACE 40 = .12 ˚ (x) Go on to the next page to continue. Example 1: 40 is 12 percent of what number? STEP 1: TRANSLATE / REPLACE 40 = .12 ˚ STEP 2: SOLVE (x) (divide both sides by .12) Go on to the next page to continue. Example 1: 40 is 12 percent of what number? STEP 1: TRANSLATE / REPLACE 40 = .12 ˚ STEP 2: SOLVE (x) (divide both sides by .12) x = 333.3 STEP 3: CHECK THAT YOUR ANSWER IS REASONABLE Example 2: What is 15% of 350? Example 2: What is 15% of 350? x = .15 ˚ 350 Solve (multiply .15 by 350): x = 52.5 Example 3: What percent of 75 is 20? Example 3: What percent of 75 is 20? x% ˚ 75=20 Solve (divide both sides by 75): x = 0.26 Since our final answer should be a PERCENT here, we need to convert from decimal form to percent form. Final answer: 26. 6% Practice: Write an equation for each, then solve. 1. What is 45 percent of 300? 2. What percent of 20 is 8? 3. 64 is what percent of 800? 4. 12 percent of what number is 90? 5. 40 percent of 85 is what number? Practice: Write an equation for each, then solve. 1. What is 45 percent of 300? x = .45(300) 135 2. What percent of 20 is 8? x(20) = 8 40% 3. 64 is what percent of 800? 64 = x(800) 8% 4. 12 percent of what number is 90? .12(x) = 90 750 5. 40 percent of 85 is what number? .40(85) = x 34 Answer Key Application Example: One pair of jeans has a regular price of $24.99 and has a discount of 25% off. A second pair has a regular price of $19.99 and has a discount of 10% off. Which pair ends up being cheaper with the discounts? Go on to the next page to continue. Application Example: One pair of jeans has a regular price of $24.99 and has a discount of 25% off. A second pair has a regular price of $19.99 and has a discount of 10% off. Which pair ends up being cheaper with the discounts? First, we have to put into words what we are trying to find for each pair of jeans. Then we can translate each into an equation. 1. What is 25% of 24.99? 2. What is 10% of 19.99? translate translate x = .25(24.99) x = . 10(19.99) solve solve $6.25 off $2.00 off Go on to the next page to continue. Application Example: One pair of jeans has a regular price of $24.99 and has a discount of 25% off. A second pair has a regular price of $19.99 and has a discount of 10% off. Which pair ends up being cheaper with the discounts? First, we have to put into words what we are trying to find for each pair of jeans. Then we can translate each into an equation. 1. What is 25% of 24.99? 2. What is 10% of 19.99? translate translate x = .25(24.99) x = . 10(19.99) solve solve $6.25 off $2.00 off For this example, we want to know which pair is overall cheaper, so we need to subtract from the original prices. 1st pair: $24.99 – $6.25 = $18.74 2nd pair: $19.99 – $2.00 = $17.99 The second pair ends up being cheaper. Practice: Write an equation for each, then solve. 1. After a 15% discount, the cost of a car is reduced by $6,799. What was the original cost? 2. 30 out of 170 wedding guests sent an “no” RSVP back. What percent of the guests who were invited are not attending? Practice: Write an equation for each, then solve. Answer Key 1. 2. After a 15% discount, the cost of a car is reduced by $6,799. What was the original cost? “15% of what original amount is 6799?” .15(x) = 6799 $45,326.67 30 out of 170 wedding guests sent an “no” RSVP back. What percent of the guests who were invited are not attending? “30 is what percent of 170?” 30 = x(170) about 17.6%
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