Maths Literacy Paper 1 & 2 Exam Revision Learner’s Guide
Spring School October 2011
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Topic 1: Financial Maths
Question 1
1.1.
Calculate the price of one 500g brick of margarine if a box containing thirty
500g bricks of margarine costs R399,00.
(2)
1.2
Naledi intends selling oranges at her school market day. She buys one dozen
oranges for R9,00. She decides to sell the oranges in packets of six at R6,00
per packet.
Calculate:
1.2.1 The cost price of ONE orange.
1.2.2 The profit she will make per dozen oranges sold.
1.2.3 How much it would cost Naledi to buy 108 oranges.
1.3 Convert $1 215,00 to rand. Use the exchange rate $1 = R10,52
(2)
(2)
(2)
(2)
1.4 Andrew earns a taxable salary of R 8 525,00 per month after deductions for
pension and medical aid. His tax rate is 28%. How much money will be
deposited into his account?
(2)
Question 2
Adapted from2008 DoE Preparatory Examination Paper 1
The pie charts below show the yearly expenditure of the Pythons Soccer Club and
the Mamba Soccer Club for 2010.
2.1. What was the total expenditure of Pythons Soccer Club for 2010?
2.2. What percentage was spent by the Mamba Club on transport?
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2.3. What percentage was spent by the Mamba Club on equipment?
2.4. Calculate the actual amount spent by the Pythons Club on maintenance.
2.5. The Pythons Club receives its income from membership fees. The club
had 100 members in 2010, each paying R450 membership fee for the
year. All the members paid in full for 2010. What was the club’s income
from membership fees in 2010?
2.6. The Pythons Club increased its membership fees by 6% for 2011.
Calculate the new membership fee for ONE member.
2.7. The total income of the Mamba Club for 2010 was R42 000. Calculate the
club’s surplus (profit) for 2010.
Profit = Income – Expenditure
(2)
(2)
(2)
(3)
(2)
[13]
Question 3
Adapted from November 2008 Paper 1
The Lighthouse Foundation provides food parcels, uniforms and clothing to needy children
in Limpopo.
Each year the Lighthouse Foundation presents a financial report to all its stakeholders (see
Table below).
TABLE:
Lighthouse Foundation Financial Report for 1 Mar 2010 to 28 Feb 2011
INCOME
Item
Private donations
Local
Overseas
Subsidy
Local municipality
EXPENSES
Amount
(in rand)
Item
Administration costs
Salaries for part-time
78 240 employees
57 120 Telephone
Stationery/Postage
308 160 Bank charges
Services rendered to
children
Food parcels
Vegetable gardens
(seedlings, fertiliser, etc.)
School uniforms
Clothing
TOTAL INCOME
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Transport costs
443 520 TOTAL EXPENSES
Amount
(in rand)
128 833
15 571
2 379
2 899
178 200
5 812
10 047
30 456
22 822
397 019
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Use the information in the table above to answer the following questions:
3.1. Write down the period of time covered by the financial report.
3.2. Name the Lighthouse Foundation's main source of income.
3.3. Express the subsidy from the local municipality as a percentage of the
total income. (Round off the answer to ONE decimal place.)
3.4. Calculate the average cost of ONE school uniform if 48 children received
school uniforms.
3.5. The overseas donations are from Japanese businessmen. Determine the
amount in yen that the Foundation received from overseas donations.
1 Japanese yen (¥) = 0,08 South African rand (R).
(1)
(1)
(4)
(3)
(3)
[12]
Question 4
Mrs Phumzile is starting a transport business. She owns one taxi, and she employs
Pieter as a taxi driver. The table below shows a list of the income and expenses of
Mrs Phumzile’s business for the month of February 2007.
Income
Expenses
Maintenance costs:
a) Fuel
R1065.40
b) Service and repairs
R546.09
c) Cleaning
R60.00
Insurance for taxi
R305.45
Taxi licence fee
R400.00
Taxi driver’s salary
R3 500.00
Taxi association fee
R200.00
Fares collected
R7 842.00
TOTAL
R7 842.00
R6 076.94
4.1. Determine the following:
4.1.1. The total cost of maintenance.
4.1.2. How many litres of fuel were used if fuel costs R7,00 a litre.
4.1.3. What percentage of the total expenses is allocated to salary.
4.2. On Monday 18 February, Pieter worked from 06:00 to 15:30. How many
hours did he work on that day?
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4.3. Pieter’s basic salary is R17,50 per hour. If Pieter wants to earn R200,00 per
day, how many hours does he have to work? Give your answer to the
nearest hour.
(3)
4.4. Mrs Phumzile asks Pieter to go on a trip of 120 km. Pieter drives the taxi at
an average speed of 90 km/h. How long will the trip take? Write your answer
correct to one decimal place. Given the formulae:
Distance = Speed x Time
Distance
Speed 
Time
Distance
Time 
Speed
(3)
[15]
Question 5
Adapted from November 2009 Paper 1
5.1. What percentage of the grants allocated during 2007 were for old-age
pensioners?
(1)
5.2. Calculate the difference between the number of beneficiaries receiving child
support grants during 2005 and 2007.
(3)
5.3. Calculate the following missing values from the table:
5.3.1. A
(2)
5.3.2. B
(2)
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5.4. The percentage of the total number of beneficiaries for each type of grant
during 2005 is represented as a bar graph on the next page. Complete the
graph by adding in bars to represent the percentage of allocations for the
different types of grants during 2007.
(4)
[12]
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Question 6
Adapted from DoE/Feb-Mar Exam 2009 Paper 2)
The Hospitality Studies department of Ses’fikile High School bakes brown bread in
order to raise funds for the shortfall incurred in their day-to-day expenses.
The school charges the Hospitality Studies department a fixed weekly cost of
R400,00 for water and electricity.
The cost of producing one loaf of brown bread, including labour and ingredients, is
R3,50. The brow bread is sold at R6,00 a loaf.
If one loaf of brown bread requires 450g of flour, determine the maximum number of
loaves of brown bread that can be baked from a 12,5kg bag of flour.
(4)
6.1. The table below shows the weekly cost of making the bread.
TABLE: Weekly cost of making brown bread
Number of loaves
Total income
(in rand)
0
400
40
540
80
680
120
A
160
960
B
1 240
300
1 450
The formula used to calculate the total cost per week is:
Total cost per week = Fixed weekly cost + (number of loaves of bread ×
cost per loaf)
Use the given formula to determine the values of A and B in the table.
(4)
6.2. The table below shows the weekly income from selling the bread.
TABLE: Weekly income received from selling bread.
Number of loaves
Total income (in rand)
0
0
40
240
120
C
Determine the values of C and D in the table.
150
900
D
960
250
1 500
300
1 800
(4)
6.3. Use the values from the Tables in question 2.1 and 2.2 to draw TWO
straight-line graphs on the same grid, showing the total COST per week of
making bread and the INCOME per week from selling bread. Clearly label
the graphs ‘COSTS’ and ‘INCOME’.
(8)
[20]
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Question 7:
Adapted from DoE Preparatory Exam 2008 Paper 2
Mukala is busy building his new house. The length of the house is 11 m and the
width is 6,10 m. The building is a double storey. The details below are found in his
notebook
TABLE 3
STAGE OF WORK
1. Foundations
2. Building of walls below the top floor
3. Plastering of walls inside and outside below the
top floor
4. Preparing for throwing the concrete on the top
floor
5. Throwing the concrete on the top floor
6. Building of support columns
7. Roofing
8. Electrical installation
9. Building of walls on the top floor up to the roof
10. Plastering of walls inside and outside on the top
floor
LABOUR COST
R5 500,00
R7 000,00
R6 000,00
R4 500,00
R18 000,00
R4 500,00
R14 000,00
R3 600,00
R9 000,00
R11 000,00
7.1. Express the cost of the most expensive stage of the work as a percentage of
the total labour cost.
(3)
7.2. The length of the top floor is 11 m; the width, including the balcony, is 7,60 m
and the thickness is 17 cm. Calculate the volume of the concrete used for
the top floor.
Volume of a rectangular prism = length × width × height
(4)
7.3. A cubic metre of concrete costs R850,00. How much did Mukala pay for the
concrete for the top floor?
(3)
[10]
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Question 7
7.1. R5 5000 + R7 000 + R6 000 + R4 500 + 18 000 + R4 500 + R14 000 +
R3 6000 + R9 000 + R11 000 = R83 100,00 
R18 000
× 100% 
R83 100
= 21,6606…%
= 21,7% 
7.2. Length = 11 m
Wide = 7,60m

Volume of the slab = l × w × h
= 11 x 7,60 x 0,17 
= 14,212m3 
Percentage =
(3)
Thickness = 17cm = 0,17m
(4)
7.3. A cubic meter cost R850 including the delivery.
Volume of the slab = 14,212 m3 
Mukala will pay: 14,212 m3 × R850 = R12 089,20 
(3)
Question 8
Adapted from November Exam 2008 Paper 2
Mrs Maharaj makes duvet sets, which she sells at the local street market at R150,00 per set
(including VAT).
 If she makes 50 or less duvet sets per month, her production costs are R100,00 per set.
 If she makes more than 50 duvet sets per month, her production costs are reduced by
15% per set.
Mrs Maharaj has to pay R8 400 annually for the rental of her stall and she has weekly
transport costs of R75.
8.1. Mrs Maharaj prepares a monthly budget.
8.1.1. Show that her fixed cost for the month of February is R1 000,00.
8.1.2. How does her fixed cost for February compare to her average
monthly fixed costs? Show ALL calculations.
8.2. Calculate the production cost per duvet set if 90 sets are made per month.
(2)
(5)
(2)
8.3. The table below shows Mrs Maharaj's production cost for different quantities
of duvet sets made in February.
TABLE 1: Cost of duvet sets made in February
0
30
50
51
Number of duvet sets
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56
60
70
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D
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Total cost per month
(in rand)
1 000 4 000 6 000 5 335 5 760 6 100
C
7 800
The formula used to calculate the total cost is:
Total cost = fixed monthly cost + (number of duvet sets  cost per set)
Use the formula and the given information to determine the missing values C
and D.
8.4. Mrs Maharaj draws two graphs to represent her income and expenses for
different quantities of duvet sets. The graph showing her INCOME for
different quantities of duvet sets has already been drawn on the next page.
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INCOME AND EXPENSES
12000
11000
10000
9000
8000
Amount in rand
7000
6000
5000
4000
3000
2000
1000
0
0
10
20
30
40
50
60
70
80
Number of duvet sets
Use the values from TABLE 1 to draw a second graph on this grid showing
the total EXPENSES for February for making different quantities of duvet
sets. Label the graph as 'EXPENSES'.
(7)
8.5. Use the two graphs to answer the following questions:
8.5.1. How many duvet sets must Mrs Maharaj sell to break even?
8.5.2. What profit will she make if all 80 duvet sets are sold?
8.5.3. Suppose Mrs Maharaj makes 80 duvet sets, but only sells 70 of
them. Calculate her profit for February.
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Solution to Topic 1
Question 1
R399
1.1.

30
= R13,30 
OR
Total number of grams in a box = 500g x 30
= 15 000g 
R399
Cost of 500g =
× 500 
15 000
= R13,30 
1.2
1.2.1
1.2.2
1.2.3.
R 9,00

12
= R0,75 
Cost of 1 orange =
dozen oranges sell for R12,00 
Profit = E12,00 – R9,00
= R3,00 
Cost = 108 × R0,75 
= R81,00 
(2)
(2)
(2)
1.3. $1 = R10,52
$1 215,00 = R10,52 x 1215,00 
= R12 781,80 
(2)
1.4 Tax: R 8 525,00 x 0,28 =R 2 387,00
Income: R 8 525,00 – R 2 387,00 =R 6 138,00
(2)
Question 2
2.1. Pythons: R54 000 
2.2. 45%
2.3. 100% - (45% + 11% + 14%) 
= 30% 
2.4. 33% of R54 000
= 0,33 × 54000 
= R17 820 
2.5. 100 × R450 
= R45 000 
2.6. R450 + (6% of R450)
6
= R450  + (
× R450)
100
= R450 + R27  = R477 
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2.7. R42 000 – R35 000 
= R7 000 
(2)
[13]
Question 3
3.1. 1 March 2010 – 28 February 2011 or 12 months
3.2. Local municipality or Subsidy 
R308 160
3.3.
× 100% 
R443 520
= 69, 48051948 % 
 69,5% 
3.4. Average cost of one school uniform
= R10 047 ÷ 48 
= R209,3125 
= R209,31 
3.5. R0,08 : 1 yen = R57 120 : x
0,08 57 120
=

1
x
0,08 x = 57 120
0,08 x
57 120
=

0,08
0,08
x = 714 000 yen 
(1)
(1)
(4)
(3)
(3)
[12]
Question 4
4.1.1. Maintenance costs:
4.1.2.
4.1.3.
= R1065,40 + R546,09 + R60 
= R1 671,49 
No. of litres of fuel
= R1065,40 ÷ 7 
= 152,2l 
R3 500
× 100% 
R6 076,94
= 57,59%
(2)
(2)
(3)
4.2. Hours worked = 15:30 – 6:00 
= 9h30 min 
(2)
4.3. No. of hours = R200 ÷ R17,50 
= 11,4287
≈ 12 hrs 
(3)
4.4.
Distance

Speed
120 km
Time 

90 km/h
Time 
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Time = 1h 20 min 
(3)
[15]
Question 5
5.1. 18,2% 
(1)
5.2. Difference = 7 908 138  – 5 662 911 
= 2 245 227 
(3)
5.3. Missing values
5.3.1. A = 100% - 22,3% - 60,2% - 3,6% 
A = 13,9% 
(2)
B = 2 194 066 + 7 908 138 + 1 420 335 + 517 580 
B = 12 036 739 
5.4. The graph
5.3.2.
 Old-age 2007 (accept 18%)
 Disability in 2007 (accept 12%)
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 Child support in 2007 (accept 66%)
 Other in 2007 (accept 4%)
(4)
[12]
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Question 6
12,5 kg

450 g
12 500 g
=

450 g
= 27,78 
6.1. Number of loaves =
 27 loaves 
(4)
6.2. Total cost = fixed cost + (number of loaves × cost per loaf)
A = 400 + (120 x R3,50) 
A = R820 
AND
1 240 = 400 + (B × R3,50) 
840 = (B × R3,50)
840
3,50 B
=
3,50
3,50
240 loaves = B 
(4)
6.3. Income = number of loaves × price of loaf
C = 120 x R6,00 
C = R720,00 
AND
960 = D x R6,00 
960 = 6D
960
6D
=
6
6
D = 160 loaves 
(4)
Question 7
7.4. R5 5000 + R7 000 + R6 000 + R4 500 + 18 000 + R4 500 + R14 000 +
R3 6000 + R9 000 + R11 000 = R83 100,00 
R18 000
× 100% 
R83 100
= 21,6606…%
= 21,7% 
7.5. Length = 11 m
Wide = 7,60m

Volume of the slab = l × w × h
= 11 x 7,60 x 0,17 
= 14,212m3 
Percentage =
(3)
Thickness = 17cm = 0,17m
7.6. A cubic meter cost R850 including the delivery.
Volume of the slab = 14,212 m3 
Mukala will pay: 14,212 m3 × R850 = R12 089,20 
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Question 8
8.1.1.
8.1.2.
R8 400
+ 4 × R 75 
12
= R700 + R300
= R 1 000
Annual transport costs = R75 × 52 
= R3 900,00 
Fixed monthly cost
=
(2)
Total annual costs = R8 400,00 + R3 900,00
= R12 300 
R12 300
12
= R1 025,00 
Average monthly costs =
The fixed costs for February is R25,00 less than the average monthly
fixed costs..
8.2. 15% reduction means the cost = 85% of R100
New production cost = 0,85 × R100  = R85,00 
(5)
(2)
8.3. 80 is more than 50, so the cost is R85 per duvet set.
Total cost = fixed cost + (no. of duvet sets  cost per set)
So C = R1 000 + 70 × R85 
= R1 000 + R5 950
= R 6 950 
R 1 000 + D  R 85 = R 7 800 
D  R 85 = R 6 800
D=
R 6 800

R 85
D = 80 
(5)
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8.4.
INCOME AND EXPENSES
12000
11000
10000
9000
Amount in rand
8000
7000
6000
5000
4000
3000
2000
1000
0
0
10
20
30
40
50
60
70
80
Number of duvet sets
 Plotting given points from table  Plotting calculated points (C; D)
 Joining points up to (50; 6000) with straight lines
 Plotting (51 ; 5335)
 Joining points up to (80 ; 7800)
(7)
Using the graphs:
8.4.1.
8.4.2.
8.4.3.
20 Duvet sets 
Profit = Income – expenses
= R12 000  – R7 800 
= R4 200 
Profit = Income from 70 sets – Expenses from 80 sets
= R10 500  – R7 800 
= R2 700 
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Topic 2: Space, Shape and Measurement
Question 1
Adapted from November, 2010, Paper 1, Question 1.3
During an experiment, an amount of liquid was poured into a calibrated rectangular
container, as shown in the diagram below.
A calibrated container has accurate measurements marked on it. It is used to
measure volume.
The dimensions of the container are:
Length = 50cm, breadth = 40cm and height = 45cm
1.1
1.2
Calculate the volume, in cm 3 , of the container.
Use the following formula: Volume  length  breadth  height
(2)
3 000 cm 3 of the liquid was poured into the calibrated container.
Calculate the height of the liquid in the container by using the following
formula:
volume of liquid
Height of liquid 
length  breadth
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Question 2
Adapted from November, 2010, Paper 1 Question 2.1
Thandiwe wants to make a new pencil holder. She has a choice of an open
cylindrical holder or an open rectangular holder. She wants to cover the outside of
the holder to match the table cloth on her desk.
A cylindrical holder with : radius = 5cm and height = 15cm
A rectangular holder with: length = 10cm, breadth = 8cm and
height = 15cm
Determine the surface area of :
2.1
the cylindrical holder
Surface area of a cylinder  2  radius  height, and using   3,14
2.2
the rectangular holder
Surface area of a rectangula r prism  2  length  breadth   height
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Question 3
Adapted from November, 2010, Paper 1, Question 4.2
Mrs. Smith and her touring parting decide to visit an indoor swimming pool.
3.1
The kiddies pool at the indoor pool has a diameter of 5m. There is a
protective fence 3m around the outside of the perimeter of the pool as shown
in the diagram below:
.
Pool
Fence
5m
3m
3.1.1 Determine the perimeter of the fence.
Use the formula:
Perimeter    diameter, and using   3,14
(3)
3.1.2 The area between the pool and the fence needs to be grassed. Grass
is bought in trays which can cover 4 m 2 and each tray costs R89,95.
Determine how much it will cost to grass the required area.ℓ
Use the formula:
3.2
Area of a circle    r 2 , using   3,14
(11)
The kiddies pool is filled with 6 000 litres of water. Mrs. Smith wanted to know
what this volume of water would be in gallons.
Convert the volume of water in the pool into gallons if 1 gallon = 4,546 l
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Question 4
Adapted from November, 2010, Paper 1, Question 5.1
Mr J Khoso owns a plot, as shown in the diagram below (not drawn to scale). His
house (D) is on the eastern side of the plot. Also on the plot is a cattle kraal (A), a
circular water tank (B), and a vegetable garden (C).
4.1
Give the general direction for the water tank from the house?
(1)
4.2
Determine the perimeter of Mr. Khoso's plot.
(3)
4.3
Calculate the volume of water in the circular water tank, if the height of the
water in the tank is 2m.
Use the formula:
4.4
2
(3)
Determine the area of the cattle kraal.
Use the formula:
4.5
Volume    radius   height, and using   3,14
1
Area of triangle   base  height
2
(3)
Calculate the total area of Mr Khoso's plot
1
Use the formula:
Area of a trapezium   sum of parallel sides   height
2
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Question 5
Adapted from November, 2010, Paper 2, Question 4
5.1
Triggers Enterprises was awarded the tender for making rectangular
cardboard boxes to package bottles of cough syrup. Each bottle is packed in
a cardboard box with a square base, as shown below:
*
The diameter of the base of the bottle is 58mm and the height of the box is
143mm.
The length of the side of the box must be approximately 105% of the diameter
of the base of the bottle.
The height of the box is approximately 102% of the height of the bottle.
*
*
The following formulae may be used:
Area of a circle    radius  , and using   3,14
2
Area of a square  side length 
Area of rectangle  length  breadth
2
The following conversions may be useful:
1 cm 2  100mm 2
1 m 2  10 000 cm 2
5.1.1 Calculate the height of the bottle to the nearest mm.
(3)
5.1.2 In order to minimise the cost of cardboard required for the box, the following
guideline is used:
The difference between the areas of the base of the cardboard box and the
base of the bottle should not be more than 11cm2
Determine whether the dimensions of this cardboard box satisfy the above
guideline. Show ALL appropriate working.
(11)
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5.2
To ensure that the box is strong enough, the cardboard used for the box has a
mass of 240 grams per m 2 . g / m 2


The layout of the opened cardboard box is shown below.
* Section C is a semicircle
* The area of each section D = 1 832 mm 2
2
* The area of section E = 2 855mm
5.2.1 Calculate the total mass of the cardboard needed for one box, to the
nearest gram.
(11)
5.2.2 The total cost of the cough syrup includes the cost of the cardboard
box.
Use the following frmula to calculate the cost of a boxed bottle of cough
syrup:
Total cost  R16,00  (mass of cardboard box)  R20,00 per kg
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Solutions to Topic 2: Space, Shape and Measurement
Question 1
1.1
Volume = length × breadth × height
= 50cm × 40cm × 45 cm
= 90 000 cm 3
1.2
Height of liquid 
volume of liquid
length  breadth
3 000cm 3
50cm  40cm
3 000cm 3

2 000cm 2
 1,5cm

Question 2
2.1
Surface area of a cylinder  2  radius  height
 2  3,14  5cm  15cm
 471 cm 2
2.2
Surface area of a rectangula r prism  2  length  breadth   height
 2  ( 10cm  8cm)  15cm
 2  18cm  15cm
 540 cm 2
Question 3
3.1.1
Perimeter    diameter
 3,14  (5m  3m  3m)
 3,14  11m
 34,54m
3.1.2
Grassed Area  Total Area - Pool Area
 (  r 2 ) - (   r 2 )
 ( 3,14  5,5 2 ) - (3,14  2,5 2 )
 (3,14  30,25) - ( 3,14  6,25)
 94,985m 2 - 19,625m 2
 75,36 m 2
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Number of trays required  75,36 m 2  4 m 2
 18,84 trays
 19 trays
Cost of grass  19 trays R89,95
 R1 709, 05
3.2
gallons = 6 000 l ÷ 4,546 l
= 1 319,84 gallons
Question 4
4.1
South Westerly direction.
4.2
Perimeter = 250m + 200m + 150m + 200m + 224m
= 1024m
4.3
Volume    radius   height
2
 3,14  (10 m) 2  2m
 3,14  100 m 2  2m
 628 m
3
4.4
1
Area of triangle   base  height
2
1
  200m  200m
2
 20 000 m 2
4.5
1
Area of a trapezium   sum of parallel sides   height
2
1
  (250m  (200m  150m))  200m
2
1
  600m  200m
2
 60 000 m 2
Question 5
5.1.1
100
102
 140,19...mm
 140 mm
Height of bottle  143mm 
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5.1.2
Difference in areas  area of base of box - area of base of bottle
 (l ) 2 - (  r 2 )
 (60,9mm) 2 - (3,14  (29mm) 2 )
 3708,81mm 2 - (3,14  841mm 2 )  3708,81mm 2 - 2640,74 mm 2  1068, 07 mm 2  100 cm 2
 10,6807cm 2
Therefore the dimensions of the cardboard box satisfy the guideline.
5.2.1
Area  (A  4)  (B  2)  (C  2)  (D  4)  (E  1)
1
 (143mm  60,9mm  4)  (60,9mm  60,9mm  2)  (3,14  (30,45mm) 2   2) 
2
2
2
(1 832mm  4)  (2 855mm  1)
 34 834,8mm 2  7417,62mm 2  2911,42mm 2  7328mm 2  2855mm 2
 55346,84mm 2  100cm 2  10 000m 2
 0,05534684m 2
Mass of 1 box  0,05534684m 2  240g
 13g
5.2.2
Total cost  R16,00  (mass of cardboard box)  R20,00 per kg
 R16,00  (13g  1000g)  R20,00
 R16,00  0,013kg  R20,00
 R16,00  R0,26
 R16,26
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Topic 3: Data Handling
Question 1: Bar Charts
Adapted from Feb/March, 2010, P1, Question 2
Mr Le Roux publishes children's books. Initially he published the children's books
only in English. He now intends to translate the books into other official South African
languages. The bar graph below shows the percentage distribution of the South
African population according to official language groups. The population of South
Africa was approximately 47 900 000 in 2009.
1.1 Which official language is spoken by the largest percentage of South Africa's
population?(1)
1.2 Use the graph to list the official languages that are used by less than 5% of the
population.(2)
1.3 What percentage of the population uses Siswati as an official language?
(2)
1.4 Calculate the number of South Africans that uses English as an official language.
(3)
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Question 2: Histograms
The histogram represents the weights of 60 babies and 6 babies weigh from 4 to
4.5kg.
2.1 Which category of birth weight had the most recorded births?
2.2 Calculate the number of babies weighing less than 3kg.
2.3 Create a frequency table for the information in this histogram.
2.4 Create a frequency polygon from the information in the table in 2.3
(2)
(4)
(8)
(6)
Question 3: Pie Charts
Adapted from November, 2010, P2, Question 3
Mr Riet wanted to show his colleagues that the South African government was
spending more on education than on most other departments.
The two graphs below show the budgeted government expenditure for the financial
years 2009/2010 and 2010/2011.
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The total expenditure budgeted for 2009/2010 was R834,3 billion and for 2010/2011
wasR900,9 billion.
3.1 Show that the difference between the amounts budgeted for education for the
financial years 2009/2010 and 2010/2011 is more thanR20 000 000 000. (8)
3.2 Give TWO possible reasons why you think the South African government should
increase its budgeted expenditure for education.
(4)
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Question 4: Mis-Representation of Data
Examine the Bar Graph below and answer the questions that follow.
4.1 What is the difference between the number of national passengers and
international passengers carried in 2003?
(3)
4.2 What is the ratio of national passengers to international passengers carried in
2003?
(3)
4.3 Does the airline carry more national or more international passengers?
(2)
4.4 Explain what message this chart wants people to believe about the statistics and
how it has achieved this.
(4)
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Question 5: Compound Bar Graphs
Examine the Bar Graph below and answer the questions that follow.
5.1
5.2
5.3
5.4
5.5
What percentage(%) of people took out medical insurance with a financial
adviser?
(2)
What percentage of people had life cover without having used a financial
planner?
(2)
What is the difference in % between the people who use a financial adviser
and those that do not when providing for retirement?
(3)
Explain what message this chart wants people to believe about the statistics
and whether it succeeded or not.
(4)
Explain why a pie chart was not used to represent the information in this
chart.
(2)
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Solutions to Topic 3: Data Handling
Question 1
1.1 Isizulu
1.2 IsiNdebele, Tshivenda, Xitsonga, Siswati
1.3 100%-(14,3+8,6+1,5+17,6+23,8+9,4+7,9+8,2+1,7+4,4)= 2,6%
1.4 8,6% of 47 900 000 = 47 900 000 X
=4 119 400 people.
Question 2
2.1 3-3.5kg
2.2 21 babies
2.3
Category/kg
Frequency
Cum. Freq.
1-1.5
2.5
2.5
1.5-2
2.5
5
2-2.5
6
11
2.5-3
11
22
3-3.5
13
35
3.5-4
10
45
4-4.5
6
51
4.5-5
5
56
5-5.5
2
58
5.5-6
2
60
2.4
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70
60
50
40
Series1
30
20
10
0
0
1
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3
4
5
6
7
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Question 3
3.1
17% of 834,3 billion in 2009 and 18% of 900,9 billion in 2010
Difference is 20.331 billion
3.2
An increase in school going population means there are more children
needing education and teachers deserve better salaries.
Question 4
4.1
6.2 million- 4.8 million = 1.4 million passengers
4.2
1,4:4,8 or 7:24
4.3
More international passengers.
4.4
There has been a large increase in passengers especially international
passengers. By starting the scale at 3.8 million rather than zero the change in
passenger volumes looks larger than it really is.
Question 5
5.1 96%
5.2 80%
5.3 58-42= 16%
5.4 People who had various insurances used a financial adviser to get the products.
Financial advisers are a key component to getting proper insurance cover and
investment products.
5.5 No- Each category is a unit on its own and does not form part of a whole.
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