21 Novembre 2007 – Esame di Ammissione Scuola di Dottorato in Scienze Molecolari CHIMICA INORGANICA 1b 1. Lead is FCC and its atomic radius is 1.746 10 cm-8. What is the volume of its unit cell? A. ~121 Å3; B. ~43 Å3; C. ~66 Å3. 2. Silver has a face-centered cubic structure with a lattice constant of 4.077 Å. Its atomic weight is 107.88 g/mol. Calculate the density of silver. A. 5.29 g/cm3; B. 10.58 g/cm3; C. 2.65 g/cm3. 3. Zinc has a HCP structure. The height of the unit cell is 4.935 Å. The centers of the atoms in the base of the unit cell are 2.66 Å apart. How many atoms are there per hexagonal unit cell? A. 2; B. 4; C. 6. 4. By referring to data pertaining to the question 3., what is the volume of the hexagonal unit cell? A. 30.24 Å3; B. 181.44 Å3; C. 90.72 Å3. 5. By referring to data pertaining to the question 3. And by considering that the Zn atomic weight is 65.39 g/mol, what is the calculated density? A. 7.18 g/cm3; B. 1.19 g/cm3; C. 4.79 g/cm3. 6. Sodium and chlorine weigh is 22.997 and 35.457 g/mol, respectively. If the density is 2.165 g/cc, calculate the dimensions of the unit cell of NaCl. A. 5.64 Å; B. 2.82 Å; C. 11.28 Å. 7. Iron is changed from BCC to FCC. What is the percent volume change? (Radii for BCC and FCC iron are 1.238 and 1.27 Å, respectively.) A. ~1% contraction; B. ~1% expansion; C. no difference. 8. Arrange the following metal complexes in order of increasing o: [CoI6]3- (1), [CoF6]3- (2), [Rh(OH2)6]3+ (3), [Rh(CN)6]3- (4), [RhI6]3- (5), [Ir(CN)6]3- (6). A. 1 < 2 < 5 < 3 < 4 < 6 B. 6 < 4 < 3 < 5 < 2 < 1 C. 2 < 1 < 4 < 3 < 5 < 6 9. Determine the hapticity (x) of the polyene/polyenyl organic ligands in the following 18-electron compounds: (1) Ir(C5H5)(C3H5)Cl; (2) Mn(C7H7)(CO)3; (3) Mo(C5H5)(CO)3-; (4) Fe(C7H8)(CO)3 A. 1 = 5,3; 2 = 7; 3 = 5; 4 = 7 B. 1 = 5,3; 2 = 5; 3 = 5; 4 = 4 C. 1 = 5; 2 = 7; 3 = 5; 4 = 7 10. Identify the first row transition metal (M) in the following 18-electron compounds: (1) M(CO)5(CH3); (2) M(6-C8H8)(CO)3; (3) M(5-C5H5)(3-C7H7)(CO); (4) [M(7-C7H7) (CO)3]+ A. 1 = Mn; 2 = Cr; 3 = Fe; 4 = Cr B. 1 = Fe; 2 = Cr; 3 = Mn; 4 = Mn A. 1 = Cr; 2 = Mn; 3 = Fe; 4 = V
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