Aquatic Herbicide Applicator Certification Training Math/Calibraton Ken Langeland UF/IFAS Agronomy Department Center for Aquatic and Invasive Plants Math Symbols • • • Unknown value: a, b, ----- x, y, z Equals: = Multiply: x, (value 1)(value 2) Example: 2x2=4, (2)(2)=4 • Divide: ÷, / – Example: 4÷2=2, 4/2=2 Things You’ll Have to Do • • • • • • Determine areas Determine volumes Determine amount of herbicide Determine sprayer output Determine speed Calibrate sprayer KNOW! •One mile = 5,280 ft •One acre = 43,560ft2 •One gallon = 4 quarts, 8 pints, 128 oz •Acre-feet=Average Depth x Surface Acres Length: The distance between two points ● ● Units: inches (in), feet (ft), miles (mi) Area: Surface enclosed by connected lines Height Width Diameter Length Base Area=length x width Area=3.14 x (radius)2 (radius=diameter/2) Area=1/2base x heigth Units: square feet (in2, ft2, mi2, acres) One acre=43,560 ft2 Area=Length x Width Area=900 ft x 600 ft Area=540,000 ft2 600ft Example: Determine the area in acres of a rectangular pond that measures 900 ft by 600 ft. 900ft Convert answer to acres Acres=540,000ft2÷43,560ft2 Acres=12.4 Area=3.14 x radius2 Area=3.14 x 902 Area=25,434 ft2 Acres=ft2/43,560 Acres=0.58 radius=diameter/2 radius=180ft/2 radius=90ft 180ft Example: Determine the area in acres of a round pond with a diameter of 180 feet. Area=1/2base x height Area=270ft/2 x 1200ft Area=162,000ft2 1200ft Example: Determine the area in square feet of a triangular-shaped cove that has an opening (base) of 270 ft and the distance from the opening to the shoreline (height) is 1200 ft. 270ft How Much Herbicide • Pounds or gallons of herbicide per acre • Concentration of herbicide in treated water • Dilutions, percent solutions Determining Amount of Herbicide Needed Surface Area Applications Herbicide needed= recommended pounds per acre x surface area to be treated or recommended gallons per acre x acres to be treated Example: How many pounds of granular herbicide are needed to treat a rectangular pond that measures 120 ft by 40 ft if the herbicide label recommends application of 120 pounds of product per acre. Area=120ft x 40ft Area=4,800ft2 Acres=4,800ft2÷43,560ft2 Acres=0.11 Pounds of herbicide=0.11 x 120=13.2 120ft 40ft Area=3.14 x radius2 Area=3.14 x 4002 Area= 502,400ft2 Acres=502,400ft2 ÷ 43,560ft2 Acres=11.5 Gallons=2 x 11.5 Gallons=23 800ft How many gallons of herbicide are needed to treat a circular pond that measures 800 ft across (diameter) if the herbicide label recommends application of 2 gallons of product per acre. length Depth w id t h Volume: Capacity measured in three dimensions Volume=length x width x depth Units: in3, ft3, acre-ft, pints, quarts, gallons Acre-ft=surface acreage x depth (ft) 4ft 2ft 6ft 9ft 8ft 10 ft 9ft 12 acres Acre-ft=surface acres x average depth Acre-ft=12 acres x (9ft+10ft+9ft+8ft+6ft+4ft+2ft)/7 Acre-ft=82.3 Application Based on Herbicide Concentration in Treated Water • One acre-ft of water weighs 2,700,000 lbs or 2.7 million lbs • Therefore, 2.7 lbs per acre-ft is 1ppm • Lbs ai needed=recommended ppm x acre-ft x 2.7 • Lbs product=lbs ai ÷ % ai in product • Gallons product needed=lbs ai ÷ lbs ai per gallon Determine how much herbicide product, which contains 2 lbs active ingredient (ai) per gallon, to apply to a pond that is 1.6 acres in surface area and has an average depth of 4 ft to result in a concentration of 0.37 ppm of the ai. Acre-ft=average depth x surface acreage Acre-ft=4ft x 1.6 acres Acre-ft=6.4 Pounds a.i. needed=recommended x acre-ft x 2.7 Pounds a.i. needed=0.37 x 6.4 x 2.7=6.39 Product needed=6.39÷2lb ai/gal=3.2 gal Determining Amount of Herbicide Needed for Proportion or % Solution in Spray Solution • If recommendation is given as herbicide volume per final spray volume – Herbicide volume=(Given herbicide ÷ Given spray volume ) x spray volume • If recommendation is given as percent solution – Herbicide volume=Spray volume x (% recommended ÷ 100) Example: Four gallons of spray mix are to be prepared for application in a backpack sprayer. How many ounces of herbicide product should be included in the final spray mix if the label recommends using 2 gallons product in 75 gallons of spray mix? Herbicide volume=(Given herbicide ÷ Given spray volume ) x spray volume Herbicide volume=(2 gal ÷ 75 gal) x 4 gal Herbicide volume=0.1 gal Ounces=0.1 gal x 128 oz/gal = 13.7 Four gallons of 1.5% spray mix are to be prepared for application using a backpack sprayer. How many ounces of herbicide product should be included in the final spray mix? Herbicide volume=Spray volume x (% recommended ÷ 100) Herbicide volume=4gal x (1.5% ÷ 100) Herbicide volume=.06gal Herbicide volume=.06gal x 128oz per gal Herbicide volume=7.68oz KNOW! • • • • • GPA = GPM/Acres per minute GPM = GPA x Acres per minute GPA = Gallon sprayed/Acres treated LBPA = PPM/Acres per minute LBPM = PPA x acres per minute Calibration for Mix Tank Application 1. Measure gallons per minute (GPM) 2. 3. 4. 5. – Gallons sprayed ÷ Minutes elapsed Determine acres per minute – Acres per minute=Acres sprayed ÷ Minutes elapsed Determine gallons per acre (GPA) – GPA=GPM ÷ Acres per minute Determine acres per tank – Acres per tank=Tank volume ÷ GPA Determine herbicide per tank – Acres per tank x Product per acre Determining Acres per Minute • • • • Acres per minute=Acres treated ÷ Minutes elapsed Acres per minute=swath (ft) x speed (ft per min) ÷ 43,560 Acres per minute=swath (ft) x speed (mph) ÷ 495 Acres per minute=2 x swath (ft) x speed (mph) ÷ 1000 Example: How much herbicide should be added to each full 100-gallon spray tank for a system that delivers 5 GPM, covers a 16ft swath, and travels 218 ft per minute if the recommended herbicide rate is 2 gallons product per acre? 1. GPM given 2. Determine acres per minute 3. Determine GPA 4. Determine acres per tank 5. Determine product per tank How much herbicide should be added to each full 100-gallon spray tank for a system that delivers 5 GPM, covers a 16-ft swath, and travels 218 ft per minute if the recommended herbicide rate is 2 gallons product per acre? Determine acres per minute: Acres per minute=swath (ft) x speed (ft per min)/43,560 Acres per minute=16 ft x 218 ft per minute ÷ 43,560 Acres per minute=.08 Determine GPA: GPA=GPM ÷ Acres per minute GPA=5GPM ÷ .08 Acres per minute GPA=63 Example: How much herbicide should be added to each full 100-gallon spray tank for a system that delivers 5 GPM, covers a 16-ft swath, and travels 218 ft per minute if the recommended herbicide rate is 2 gallons product per acre? Determine acres per tank: Acres per tank=Tank volume ÷ GPA Acres per tank=100 gallons ÷ 63 GPA Acres per tank=1.6 Determine product per tank: Product per tank=Acres per tank x Product per acre Product per tank=1.6 Acres per tank x 2 gal per acre Product per tank=3.2 gallons Calibration for Direct Metering Systems Determine required product per minute: 1. Determine acres per minute 2. Determine product per minute Product per minute=Product per acre (recommended) x acres per minute Determine product delivered per acre for measured product per minute: 1. Measure product delivered per minute 2. Determine acres per minute 3. Determine Product per acre Product per acre=product per minute ÷ acres per minute Example: How many ounces should be withdrawn per minute by a direct metering system to apply 1.5 gallons of herbicide product per acre if swath is 15 feet and speed is 105 feet per minute. Determine acres per minute: Acres per minute=swath (ft) x speed (ft per min)/43,560 Acres per minute=15 ft x 105 ft per min ÷ 43560 Acres per minute=.036 Determine product per minute needed: Product per minute=Product per acre x acres per minute Product per minute=(1.5 gal x 128 oz/gal) x .036 Product per minute=6.9 ounces Example: If a direct metering system known to deliver 8 ounces of herbicide product per minute is used “as is” on a boat that treats 0.04 acres per minute, how many gallons of herbicide product will be applied per acre? 1. Product per minute given 2. Acres per minute given 3. Product per acre=product per minute ÷ acres per minute Product per acre=8 oz ÷ 0.04 acres per minute Product per acre=200 oz 4. Convert ounces to gallons Product per acre=200 oz ÷ 128 oz per gallon Product per acre=1.6 gal Calibrating for Granular or Pellet Applications Determine how much product to deliver per minute for given application rate and speed 1. Determine acres per minute 2. Determine Lb per minute required Lbs per minute=lbs per acre recommended x acres per minute Example How many pounds of herbicide pellets should be delivered per minute from a spreader if swath is 40 feet, acres per minute is determined to be 0.32 and the label recommends 40 pounds per acre? 1. Acres per minute is given 2. Determine pounds per minute required Lbs per minute=lbs per acre recommended x acres per minute Lbs per minute=40 pounds x 0.32 acres per minute Lbs per minute=12.8 BE CAREFUL !
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