D o37+2=8
Now: _
27◊+9=37
4b
5◊+5=3◊+11
O
04S(xt2)=3(x+4)
_
3
As
as
as2(x+6)+2x=s(x+1)+3
00
2◊+12+2=9◊+5+3
" 4◊+12
55◊+8
/ /12=1
-
-4X
-4_X
- 8 4=1X ï
4=x
Literal
Equation
using 0
anything
4 equation with
dpt.
for the variables
It
4
with more than one variabl
any equation
x
rib
Atbt EX
d
act:
A=12 (bxh)
UT substit
m
X
u
_
_
de
A=lxW
AK
Z
=
d
V
\
or
at D.
12vine
Pv=nRT +b
M:
V=lxwxh
m=dV
y=mx
-X,)2+/1/2-Y,)2
'12
\
dir
DR
able
isolate
the
var.
Objective/ goal:
for
w
solve
tow
x w
ï = I.
A
40=
A
10=l
40=10xw
}
o
w
\
ï
At
of
_ 10\
10
4
=
_
= w
for
d=rt
t
_
I
/
d
E=r
ï
for
Z
/
bte
>
b= x
_
J
c
to
_
EX
x
Ac
X=
r
/\
-
_
a
+
a
_
X-a
Fan
271b=C forx
/
-3
.
+b +b
_
_
|1=1ctb
0
2x=ic+b
T 2
_
_
2
forc
Perimeterot Rectangle
for
ax+by=C
f
or
L
P=2w+2L
UX
ax
_
-2W
by=c-ax
P-2w=2L
FW C
=
=
\
=L
ï
P-2W
_ 2
-
x
\b =
_
_
.
ï
y=eax
b
ï
.
{
W
for
b
for
b
a=U
V
=
Ixwxh
-U
in
-
It
C
|
A-U=-b
= \
_
-1
|
r
-
comm..
pro
of
| )
ï
o
T2\
V= lXhX W
exh exh 10=3
_
x
.
4X w
> ex
10= 12xW
402
in
=wT
19-14 - "in
at = b
"
must
_ 12
'
= W
for
The
R=5
R=TLS
ï
FL
PV=nRTforR
x x
_
TL
PV=ntR
\ x
,
-
_
NT
NT
prnt
Rd
=
it Is
ï
at
be
= be
Ex
Xe
a=
b
abet
Y
x
a=b_Cy abide
|
a
fore
for C
|
XC
T
a
=
be
c
ï data
ca=b
(a=
be
At be
heat
ate
tit
Geog
T
as
\a
_
ï
ï
51 5th
_
=
b
_
a
T
Hwy #1-14
+30
back
#
15
own