Vision SBI PO: Data Interpretation
Price (in ` thousand)
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Directions (Q. 1-5): Study the following bar-graph carefully to answer the given questions.
The graph shows the prices of three different types of smartphones in different years.
Samsung
16
14
12
10
8
6
4
2
0
2009
2010
LG
2011
Year
Lenovo
2012
2013
1. In which year was the average price of all three smartphones the minimum?
1) 2009
2) 2010
3) 2011
4) 2012
5) 2013
2. A shopkeeper purchased 20 Samsung, 25 LG and 30 Lenovo smartphones in 2011 and sold all
types of smartphones at the rate of `13300. What is his percentage loss or profit?
1) 89%
2) 0.99%
3) 0.71%
4) 71%
5) 0.56%
3. The price of LG smartphones in 2012 was what per cent of its price in 2013?
1) 104.5%
2) 107.68% 3) 110.9%
4) 113.04% 5) 115.06%
4. If the total number of sales of Lenovo was 20000 in 2010 and the total number of sales of Samsung
was 18500 in that year, then what was the difference of income of Samsung and Lenovo?
1) `10500000 2) `10700000 3) `10900000 4) `10300000 5) `10200000
5. Which smartphone has the minimum average price during the given five years?
1) Samsung
2) LG
3) Either Samsung or LG
4) Either LG or Lenovo
5) Lenovo
Directions (Q. 6-10): Study the following bar-graph and pie-chart carefully to answer the
following questions.
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Speed of stream
14
10
C
10
6
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Boat
D
Speed of boat
B
12
A
14
18
10
0
5
10
15
20
(Speed in kmph)
Percentage of distance travelled by Shyam by the four different boats
D
16%
A
40%
C
26%
B
18%
Total distance travelled = 1000 km
6. What is the difference of time taken by boat A and boat B to travel 200 km upstream?
1) 68 hours
2) 72 hours
3) 71 hours
4) 75 hours
5) 84 hours
7. What is the time taken by Shyam to reach his destination upstream?
1) 272 hours 2) 245 hours 3) 240 hours 4) 232 hours 5) 268 hours
8. If the speed of boat C is increased by 40% and the speed of stream decreases by 20% then what
is the difference between the time taken by the boat now and that taken previously to travel 200
km? (Assume opposite direction of stream)
1) 28
6
4
hours 2) 22 hours
23
5
4
5
3) 20 hours
5
6
4) 18 hours
5
6
5) 35 hours
9. If the speed of boat D increases by 10% then what is the approximate time taken by Shyam to
reach 500 km by boat D? (Assume opposite direction of stream)
1) 88 hours
2) 92.6 hours 3) 68 hours
4) 78 hours
5) 44 hours
10. What is the ratio of the time taken by boat C to that taken by boat D? (Assume same direction of
stream)
1) 9 : 7
2) 7 : 5
3) 5 : 3
4) 4 : 3
5) 3 : 2
Answers With Explanations:
1
1. 3; Average price of all three smartphones in 2009 = 3 × (13500 + 11500 + 12500) = `12500
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In 2010 =
In 2011 =
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In 2012 =
1
× (13000 + 13500 + 11500) = `12666.7
3
1
× (14000 + 13500 + 13000) = `13500
3
1
× (12500 + 13000 + 13500) = `13000
3
1
× (13500 + 11500 + 14000) = `13000
3
In 2013 =
Hence, in 2011 the average price is the maximum for all the three smartphones.
2. 2; Cost price of 20 Samsung, 25 LG and 30 Lenovo smartphones in 2011
= 20 × 14000 + 25 × 13500 + 30 × 13000 = `1007500
 Selling price = 13300 × (20 + 25 + 30) = `997500
% loss =
1007500 – 997500
 100%
1007500
= 0.99%
3. 4; Price of LG smartphones in 2012 = `13000 and in 2013 = `11500
Price of LG smartphones in 2012 is
 13000  100 

%
11500 
= 113.04% of its price in 2013
4. 1; Income of Lenovo in 2010 = 20000 × 11500 = `230000000 = 23 crore
Income of Samsung in 2010 = 18500 × 13000 = 240500000 = 24.05 crore
 Reqd difference = 240600000 – 230000000 = `10500000 = 1.05 cr
5. 2; Average price of Samsung =
=`
66500
5
Average price of LG =
1
5
1
5
× (13500 + 13000 + 14000 + 12500 + 13500)
= `13300
× (11500 + 13500 + 13500 + 13000 + 11500) = `
63000
5
= `12600
Average price of Lenovo =
1
5
× (12500 + 11500 + 13000 + 13500 + 14000) = `
64500
5
= `12900
LG has the minimum average price during the given years.
6. 4; Time taken by boat A to travel 200 km =
Time taken by boat B to travel 200 km =
200
14 – 12
200
18 –10
= 25 hrs
= 100 hrs
 Reqd difference = (100 – 25) = 75 hours
7. 2; Total distance travelled by Shyam = 1000 km
Distance covered by boat A = 1000 ×
Time taken by boat A =
Time taken by boat B =
400
18 –10
40
100
= 400 km
= 50 hours
18
100
14 –12
1000 
26
100
10 – 6
= 90 hours
1000 
Time taken by boat C =
= 65 hours
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16
100
14 –10
1000 
Time taken by boat D =
= 40 hours
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 Total time taken by Shyam = (50 + 90 + 65 + 40) = 245 hours
140
8. 1; Speed of boat C after 40% increase in its speed = 10  100 = 14 kmph
Speed of stream after 20% decrease = 6 ×
Now, time taken by boat C =
200
14 – 4.8
Time taken by boat previously =
 Difference = (50 –
21
17
)
23
=
28
=
200
10 – 6
6
23
=
200
9.2
200
4
80
100
=
21
= 4.8 kmph
17
23
hours
= 50 hours
hours
110
9. 2; New speed of boat D = 14  100 = 15.4 kmph
Time taken to travel 500 km =
500
15.4 –10
10. 5; Time taken by boat C =
x km
(10  6)
Time taken by boat D =
 Reqd ratio =
x x
:
16 24
= 92.54  92.6 km
x km
(10  14)
=3:2
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