Related Rate Problems - Solutions 1. Air is being pumped into a spherical balloon so that its volume increases at a rate of 100 cm3/s. How fast is the radius of the balloon increasing when the diameter is 50 cm? 4 3 V= r 3 dV 2 dr =4 r dt dt 100=4 25 2 dr dt dr 1 = cm/s. dt 25 2. A ladder 10ft long rests against a vertical wall. If the bottom of the ladder slides away from the wall at a rate of 1 ft/s. how fast is the top of the ladder sliding down the wall when the bottom of the ladder is 6 ft from the wall? x 2 y 2=100 y dx dy 2 y =0 dt dt 10 2x x 26128 dy 3 =− ft/s. dt 4 dy =0 dt 3. A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 5 ft/s along a straight path. How fast is the tip of his shadow moving when he is 40 ft from the pole? 15 6 x y By similar triangles, 15 6 = . That is, 9 y=15 x . y y −x 9 dy dx =15 dt dt 9 dy =155 dt dy 25 = ft/s. dt 3 4. Car A is traveling west at 50 mi/h and car B is traveling north at 60 mi/h. Both are headed for the intersection of the two roads. At what rate are the cars approaching each other when car A is 0.3 mi and car B is 0.4 mi from the intersection? x y x 2 y 2=z 2 2x z dx dy dz 2 y =2 z dt dt dt 20.3−5020.4 −60=20.5 dz =−78 mi/h. dt dz dt 5. A water tank has the shape of an inverted circular cone with base radius 2m and height 4m. If water is being pumped into the tank at a rate of 2 m3/min, find the rate at which the water level is rising when the water is 3 m deep. 2 1 V = r2 h 3 4 r by similar triangles h V= r 2 h = and hence r= h 4 2 1 3 h 12 dV 1 dh = 3 h2 dt 12 dt 2= 1 dh 3 32 12 dt dh 8 = m/min. dt 9 6. A hot air balloon rising straight up from a level field is being tracked from a spectator 500 ft from the liftoff point. At the moment the angle of elevation is π , the angle is increasing at the rate of 0.14 rad/min. How fast is the 4 balloon rising at that moment? tan = y 2 Ө sec 500 sec 2 y 500 d 1 dy = dt 500 dt 4 0.14 = 5001 dydt dy =140 ft/min. dt 7. A mechanic is reboring a 6-in-deep cylinder to fit a new piston. The machine they are using increases the cylinder’s radius one-three thousandth of an inch every minute. How rapidly is the cylinder volume increasing when the bore diameter is 3.8 inches? 2 V = r 6 r dV dr =12 r dt dt 6 dV 1 =121.9 dt 3000 dr 19 = in3/min dt 2500
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