Sections 7.3, 7.4 SPECIAL PRODUCTS OF POLYNOMIALS, PROPERTIES OF EXPONENTS click for printing: 6 slides per page Product of binomials F.O.I.L. method Label L b l tterms Firsts, Lasts, Outsides, Insides F L F L (x+3)(x+5) O I I O Multiply: M li l d draw li line, write i product, d d draw, write… i Firsts x2 Outsides +5x Insides +3x Lasts +15 Combine C bi lik like tterms: x2+8x+15 8 15 Products of higher degree polynomials Be B very methodical th di l Draw line for the product of two terms Write the product of those terms Draw another line for product of terms Write the product of those two terms Etc: DO NOT DRAW ALL THE LINES AND GO BACK TO FIND THE PRODUCTS!! YOU WILL GET LOST!! Powers of polynomials ((x+3) 3)2 : exponent is 2: raised to second power (x+3)(x+3) write this way Now use F.O.I.L. method x2 + 3x + 3x + 9 = x2 + 6x + 9 x2+3 32 is not the same as (x (x+3) 3)2 Put in numbers to test this!! Shortcut to squaring binomial ((x+3) 3)2 Square first term x2 Multiply terms together and double it 6x Square last term 9 = x2 + 6x + 9 Product of conjugate factors (x+3)(x-3) ( 3)( 3) Use FOIL method x2 - 3x + 3x - 9 = x2 – 9 Special product: difference of 2 squares Quadratic function Standard St d d fform f(x) = Ax2 + Bx + C If it looks different, you need to write it in this form to use techniques to solve it Write in standard form: f(x) = Ax2 + Bx + C f(x) f( ) = -3(x-4) 3( 4)2 + 8 Square the binomial:(x-4)2=x2-8x+16 Distribute the -3 2+24x-48 -3(x ( 2-8x+16)=-3x ) Then add 8 3x2+24x-48+8= 24x 48 8 3x2+24x-40 24x 40 A=3, B=24, C=-40 Properties of exponents These Th apply l to t factors f t off tterms NOTE: when there are sums involved, you need d to use the h FOIL method h d to d deall with ih the terms in parentheses Product of same variable with exponents x2·x3=(x·x)(x·x·x)=x ( )( ) 5 x2·x3=x(2+3)=x5 (2x3y6)(3x8y7) =(2·3)(x ( )( 3x8)( )(y6y7) =6x11y13 Raising monomial to a power ((-2xy) 2 )3 =(-2xy)(-2xy)(-2xy) Write out =(-2)3x3y3 or cube each term =-8x3y3 Quotients with exponents x5 = xxxxx x2 = xx x5 = x(5-2)= x3 x2 = xxx = x3 Quotients with exponents x2 = xx x5 = xxxxx =1 x3 x2 = x(2-5)= x-3 x5 Negative exponents are fractions!! Quotients with exponents x3 = xxx =1 x3 = xxx x3 = x(3-3)= x0 = 1 x3 Zero exponents equal 1!! How are these different? (3 (3+x))2 = 9 + 6x 6 + x2 (3x)2 = 9x2 Are they both true? Raise a power to a power (3 (3x3)2 =(3x3)(3x3) write it out to see steps =(3)2(x3x3) =9x6 All exponent rules on page 594
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