Algebra Name ________________________________________ CHAPTER 7 FUNCTIONS AND TRANSFORMATIONS Period ______ Date ____________________________ Dilations and Reflections of Absolute Value Functions: π(π) = |π| In questions 1 through 6, a) quickly sketch the graph of the parent function, π(π₯) = |π₯| b) identify the vertex of each new function c) graph the new function d) make a table of values for the new function e) write a verbal description of the transformation from the parent graph, π(π₯) = |π₯|, to the new function 1. π¦ = 2|π₯| 2. π¦ = β3|π₯| Vertex: ( , ) Vertex: ( , ) x y x Description of the transformation: 1 3. π¦ = 3 |π₯ + 3| Vertex: ( , ) x y y Description of the transformation: 3 4. π¦ = β 4 |π₯ β 2| Vertex: ( , ) x y Description of the transformation: Description of the transformation: 5. 6. π¦ = β |π₯ β 4| + 3 4 Vertex: ( , ) π¦ = 2|π₯ + 1| β 6 Vertex: ( x , ) y Description of the transformation: 1 x y Description of the transformation: In questions 7 through 12, a) write a verbal description of the transformation from the parent graph, π(π₯) = |π₯|, to the new function b) write an absolute value function for the graph 7. Description: 8. Description: 9. Description: Equation: 10. Description: Equation: Equation: 11. Description: Equation: Equation: 12. Description: Equation: 13. The graph of π(π₯) = |π₯| is given below. Sketch the new graph completing the transformations in the order given. a) First translate the absolute value function up 2 b) First vertically stretch the function by a factor spaces. Then vertically stretch the translated of 3 (multiply the function by 3). Then function by a factor of 3 (multiply the function translate the stretched absolute value function by 3). up 2 spaces. 14. Are the graphs in 13(a) and 13(b) the same graph? Why or why not? 15. Write equations for each of the two new functions you graphed in question 13(a) and (b). Equation for 13(a): Equation for 13(b): In problems 16-23, given the graphs shown below, find the value of each expression. Evaluate: 16. π(3) = 17. (π)(β2) = 18. π(π₯) π(π₯) π(2) + π(β4) = 19. π(1) β π(1) = Solve: 20. π(π₯) = β4; π₯ =? 21. π(π₯) = 0; 22. π₯ =? 23. π(π₯) = π(π₯); π(π₯) = β4; π₯ =? π₯ =? Algebra ANSWERS CHAPTER 7 FUNCTIONS AND TRANSFORMATIONS Dilations and Reflections of Absolute Value Functions: π(π) = |π| 1. π¦ = |π₯| β 2 Vertex: (0, β2) x -2 -1 0 1 2 y 0 -1 -2 -1 0 2. π¦ = |π₯| + 4 Vertex: (0, 4) x -2 -1 0 1 2 y 6 5 4 6 0 Description of the transformation: The graph of π(π₯) = |π₯| was shifted down two units. Description of the transformation: The graph of π(π₯) = |π₯| was shifted up four units. 3. π¦ = |π₯ + 3| Vertex: (β3, 0) 4. π¦ = |π₯ β 2| Vertex: (2, 0) x -5 -4 -3 -2 -1 y 2 1 0 1 2 x -5 -4 -3 -2 -1 y 2 1 0 1 2 Description of the transformation: The graph of π(π₯) = |π₯| was shifted left three units. Description of the transformation: The graph of π(π₯) = |π₯| was shifted right two units. 5. π¦ = |π₯ β 1| + 3 Vertex: (1, 3) 6. π¦ = |π₯ + 5| β 2 Vertex: (β5, β2) x -1 0 1 2 3 y 5 4 3 4 5 Description of the transformation: The graph of π(π₯) = |π₯| was shifted right one unit and up three units. x -7 -6 -5 -4 -3 y 0 -1 -2 -1 0 Description of the transformation: The graph of π(π₯) = |π₯| was shifted left five units and down two units. 7. π¦ = |π₯ + 2| + 1 Vertex: (β2, 1) x -4 -3 -2 -1 0 8. π¦ = |π₯ β 3| β 1 Vertex: (3, β 1) y 3 2 1 2 3 x 1 2 3 4 5 y 1 0 -1 0 1 Description of the transformation: The graph of π(π₯) = |π₯| was shifted left two units and up one unit. Description of the transformation: The graph of π(π₯) = |π₯| was shifted right three units and down one unit. 9. Vertex: (0, β3) 10. Vertex: (β2, 0) Equation: π¦ = |π₯| β 3 Equation: π¦ = |π₯ + 2| 11. Vertex: (3, 1) 12. Vertex: (β4, β2) Equation: π¦ = |π₯ β 3| + 1 Equation: π¦ = |π₯ + 4| β 2 13. The cost in dollars of trampoline jumping at Sky High Sports in Valencia is a function of the number of hours you jump. The relationship between both variables can be modeled as πΆ(π‘) = 3.50π‘ + 6.00. a) Find the value of πΆ(4) Write a sentence to interpret your answer in the context of the problem. πΆ(4) = 20. This means that for four hours on trampoline jumping, you must pay $20. b) Solve the equation πΆ(π‘) = 30.50. Write a sentence to interpret your answer in the context of the problem. If πΆ(π‘) = 30.50, then π‘ = 7. This means that if you are willing to spend $30.50 on trampoline jumping, you will be able to do so for seven hours. In problems 14-21, given the graphs shown below, find the value of each expression. 14. π(2) = 3 15. π(2) = 1 16. π(3) = 5 17. π(0) = β1 18. π(0) + π(β1) = β5 19. 20. If π(π₯) = 3, then π₯ =? π₯=2 21. If π(π₯) = β2, then π₯ =? π₯=0 If π(π₯) = π(π₯), then π₯ =? π₯=3
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